Fractions & Decimals

Problem

Match fraction forms to compare sizes

I need to count how many whole numbers can replace the \bigstar so that the improper fraction \bigstar/8 sits strictly between the mixed numbers 4 and 38\frac{3}{8} and 5 and 18\frac{1}{8}.
Fractions
Your answer
How to solve
Strategy Organize Information in More Ways — To compare fairly, rewrite both mixed-number endpoints as improper fractions over 8 so every quantity has the same denominator. Then the numerators can be compared directly and the valid whole numbers listed.
1STEP 1

Rewrite the left endpoint over 8

Convert 4 38\frac{3}{8} to eighths: 4 wholes is 32 eighths, plus 3 eighths, giving 358\frac{35}{8}.

438=(4×8+3)/8=3584 \frac{3}{8} = (4× 8 + 3)/8 = \frac{35}{8}
2STEP 2

Rewrite the right endpoint over 8

Convert 5 18\frac{1}{8} to eighths: 5 wholes is 40 eighths, plus 1 eighth, giving 418\frac{41}{8}.

518=(5×8+1)/8=4185 \frac{1}{8} = (5× 8 + 1)/8 = \frac{41}{8}
3STEP 3

Compare numerators and list

358\frac{35}{8} less than \bigstar/8 less than 418\frac{41}{8}, so \bigstar is a whole number between 35 and 41: 36, 37, 38, 39, 40.

35<<4136,37,38,39,4035 \lt ★ \lt 41 → ★ ∈ {36,37,38,39,40}
4STEP 4

Count them

There are five whole numbers in the list.

{36,37,38,39,40} → 5
Answer
5
{36, 37, 38, 39, 40} → 5
The endpoints 35 and 41 are 6 apart; excluding both ends leaves the 5 whole numbers in between, which matches the count. Each candidate, like 368\frac{36}{8} = 4.5, indeed lands between 4 38\frac{3}{8} and 5 18\frac{1}{8}.
Takeaway

This only needs Grade 3 fraction sense: make the bottoms match, then just compare the top numbers!

  • Rewrite the left endpoint over 8
  • Rewrite the right endpoint over 8
  • Compare numerators and list
  • Count them
Where next?
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▶ Practice — 12 problems