Fractions & Decimals

Problem

Compare fractions sharing numerator or denominator

I need to count how many of the digits 1 through 9 can be placed in the \bigstar so that the fraction 17\frac{1}{7} is less than 1\frac{1}{\bigstar}.
Fractions
Your answer
How to solve
Strategy Look for a Pattern — Both fractions have numerator 1, so the comparison depends only on the denominators: the unit fraction with the smaller denominator is larger. That pattern instantly tells me 1\frac{1}{\bigstar}17\frac{1}{7} exactly when \bigstar < 7, and I can list those digits to count them.
1STEP 1

Use the unit-fraction size rule

Cut a whole into more equal parts and each part shrinks, so with numerator 1 the fraction is bigger when the denominator is smaller.

17<1    <7\frac{1}{7} \lt \frac{1}{\bigstar} \iff \bigstar \lt 7
2STEP 2

List the digits 1 to 9 that are less than 7

We need \bigstar less than 7, with \bigstar chosen from 1 through 9. The digits less than 7 are 1, 2, 3, 4, 5, and 6.

1,2,3,4,5,6\bigstar ∈ {1, 2, 3, 4, 5, 6}
3STEP 3

Count the valid values

Count the digits in the list 1, 2, 3, 4, 5, 6.

6 numbers
Answer
6
Spot-check the boundaries: 16\frac{1}{6} greater than 17\frac{1}{7} (true, 6 counts) and 17\frac{1}{7} less than 17\frac{1}{7} is false (7 excluded) and 18\frac{1}{8} less than 17\frac{1}{7} so 17\frac{1}{7} less than 18\frac{1}{8} is false (8 excluded). Only 1-6 qualify, giving 6 - consistent with the answer.
Takeaway

For 1-over-something fractions, fewer parts means bigger pieces - so just count the denominators smaller than 7!

  • Use the unit-fraction size rule
  • List the digits 1 to 9 that are less than 7
  • Count the valid values
Where next?
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▶ Practice — 8 problems