Depth · one concept from first principles · step 2 of 4
Rename repeated reciprocals to get a linear system
Solve the equation .
Depth · one concept from first principles · step 2 of 4
Solve the equation .
Each of the first two expressions equals the last one, 1.
Pairing each part with the plain number 1 keeps the equations simple.
8.EE.C.8Organize Information In More WaysLet A=1/(x+y) and B=1/(x-y). Both equations become linear in A and B.
The fractions were never the real difficulty; they are just two quantities used twice.
7.EE.A.2Convert To AlgebraWith and , the two equations become and .
is five pieces each the size of , so it is ; in the same way is and is .
names the same number everywhere it is used, so swapping each copy for does not change the value of either side.
From the second equation B=1+3A. Substitute into the first equation.
This is now a routine two-variable linear system.
8.EE.C.8Convert To AlgebraIf 1/(x+y)=-3 then x+y=-1/3, and if 1/(x-y)=-8 then x-y=-1/8.
Taking reciprocals of both sides is safe because neither side is 0.
8.EE.C.8Identify SubproblemsAdding the two equations gives 2x; subtracting them gives 2y.
A sum and a difference always pin down the two numbers.
8.EE.C.8Identify SubproblemsWhen the same messy piece keeps showing up, give it a new name and the problem often becomes one you already know how to solve.
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