Numbers & Place Value

Problem

Count groups several equivalent ways

There are 28 beads in an array of 4 rows with 7 beads in each row. Among four offered counting methods, we must find the one that does NOT give the correct total of 28.
Operations
Your answer
How to solve
Strategy Draw a Diagram — Picture the 7-by-4 array of beads, then evaluate each choice against the array and list the totals to spot the one that is not 28.
1STEP 1

Read the array as the true total

4 rows of 7 beads make the true total 7 x 4 = 28 — every correct method must match it.

7 × 4 = 28
2STEP 2

Check the addition and product choices

(A) 7+7+7+7, (B) 7 x 4, and (C) 4 x 7 all give 28 — repeated addition and either multiplication order count the same array.

7+7+7+7 = 28, 7×4 = 28, 4×7 = 28
3STEP 3

Check choice D

(D) adds 7 x 2 = 14 four times: 14 + 14 + 14 + 14 = 56, double the real 28 — so (D) is the wrong way to count.

7 × 2 = 14, 14 × 4 = 56 ≠ 28
Answer
D
Choices A, B, C all equal 28, the bead total, while D equals 56, twice as many, so D is clearly the wrong way to count.
Takeaway

Equal rows can be added or multiplied to the same total -- but counting each row as double overshoots, easy Grade 3 array sense!

  • Read the array as the true total
  • Check the addition and product choices
  • Check choice D
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▶ Practice — 10 problems