Numbers & Place Value

Problem

Different factor pairs, same product

A wire is as long as a 9 cm stick placed end to end 4 times. Each triangle is made of three 2 cm sides. We want the greatest number of such triangles the wire can make.
Operations
Your answer
triangles
How to solve
Strategy Identify Subproblems — Break the problem into two small steps: first find the total wire length, then find how much wire one triangle needs, and finally see how many triangles fit. Tracking centimeters keeps the multiplication and division lined up correctly.
1STEP 1

Find the total wire length

Four 9 cm lengths joined end to end make 36 cm of wire in all.

9 × 4 = 36
2STEP 2

Find the wire one triangle needs

One triangle's three 2 cm sides use 6 cm of wire.

2 × 3 = 6
3STEP 3

Count how many triangles fit

Fitting 6 cm lengths into 36 cm gives 6 triangles, with no wire left over.

36 ÷ 6 = 6
Answer
6 triangles
36 ÷ 6 = 6
6 triangles use 6 times 6 = 36 cm, which is exactly the whole wire, so the answer fits with nothing wasted and the magnitude is sensible.
Takeaway

Find the whole length, find one triangle's length, then split into equal groups -- only Grade 4 grouping you already know!

  • Find the total wire length
  • Find the wire one triangle needs
  • Count how many triangles fit
Where next?
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▶ Practice — 12 problems