Fractions & Decimals

Depth · one concept from first principles · step 2 of 4

Bouncing ball: repeated fraction-ratio heights

A ball always rebounds to 5/6 of the height it just fell from. It starts by being dropped from 24 ft. I need the height it reaches after its third bounce.
24 1 2 3 24 × 5/6 (1st) × 5/6 (2nd) × 5/6
Fractions
Your answer
How to solve
Strategy Look for a Pattern — Each bounce repeats the same action: multiply the current height by 5/6. Spotting this repeated structure (Look for a Pattern) lets me solve the easy first bounce, then reuse the same step two more times. I keep feet as the unit throughout to check the setup.
1STEP 1

First bounce

The ball falls from 24 ft and rebounds to 5/6 of that. Multiply 24 by 5/6.

24 × 5/6 = (24 × 5)/6 = 120/6 = 20 ft
2STEP 2

See the repeating rule

Every bounce takes 5/6 of the height just reached, so the rule repeats: x 5/6 each time.

bounce = previous height × 5/6
3STEP 3

Second bounce

Apply the rule to the first-bounce height of 20 ft.

20 × 5/6 = 100/6 = 50/3 ft
4STEP 4

Third bounce

Apply the rule one more time to the second-bounce height of 50/3 ft.

50/3 × 5/6 = 250/18 = 125/9 = 13 8/9 ft
Answer
1259\frac{125}{9} ft (= 138913\frac{8}{9} ft ≈ 13.89 ft)
The bounces 20 ft, 16.67 ft, 13.89 ft steadily decrease and each is a bit more than 4/5 of the one before, which matches 5/6 of a shrinking height; the unit stays feet and the answer is well below the 24 ft drop, so it is reasonable.
Takeaway

Each bounce is just 5/6 of the last height, so keep multiplying by 5/6 and the ball climbs a little less every time.

  • First bounce
  • See the repeating rule
  • Second bounce
  • Third bounce
Where next?
Another one like thissuggested
Same look, different logicsuggested

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▶ Practice — 12 problems

The same shape shows up later on the AMC, as Compound Area by Decomposition / Difference. Why the shapes repeat →