Fractions & Decimals

Problem

Sum fractional parts of a whole

Treat all the tangerines as one whole. 3/4 of them were sold and 1/5 of them were eaten. We need to find what fraction is left over and decide whether that leftover fraction is really less than 1/10 of the whole.
Fractions
Your answer
How to solve
Strategy Identify Subproblems — This breaks naturally into small steps: first add the two parts that are gone (sold + eaten), then subtract from the whole to get the leftover, then compare the leftover to 1/10. A bar split into twentieths lets you see each part and check the comparison by eye, so a diagram supports the subproblem plan.
1STEP 1

Add the parts that are gone

Sold and eaten are both gone, so add them over twentieths: 15/20 + 4/20 = 19/20.

3/4+1/5=15/20+4/20=19/20
2STEP 2

Subtract to find the leftover

The whole is 1, which is 20/20. Take away the 19/20 that is gone to find what is left over.

1-19/20=20/20-19/20=1/20
3STEP 3

Compare the leftover with 1/10

In twentieths the leftover 1/20 is one piece while 1/10 is 2/20, two pieces.

1/10=2/20, 1/20 < 2/20
Answer
The claim is correct: the leftover is 120\frac{1}{20}, which is less than 110\frac{1}{10}.
Check the parts add to the whole: 3/4 + 1/5 + 1/20 = 15/20 + 4/20 + 1/20 = 20/20 = 1. Good. In decimals the leftover is 1/20 = 0.05 and 1/10 = 0.10, and 0.05 < 0.10, so the conclusion holds.
Takeaway

Make every part share the same denominator, then it is just counting equal pieces: 1 piece left out of 20 is less than 2 pieces, so less than 1/10.

  • Add the parts that are gone
  • Subtract to find the leftover
  • Compare the leftover with 1/10
Where next?
Another one like thissuggested
Step back and solidifysuggested

▶ Practice — 12 problems