← Compare two weighings to cancel the container · Find Two Unknowns from Sum and Difference

Compare two weighings to cancel the container · 12 practice problems

4.OA.A.35.NBT.B.6

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 150 g

A box holding 66 identical bars of soap weighs 300 g300\ \text{g}. After putting in 22 more identical bars of soap, the box weighs 350 g350\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 6 equal soap bars inside weighs 300 g. When 2 more equal bars are added, the same box now holds 8 bars and weighs 350 g. We need the weight of the empty box alone.

Givens
  • The box plus 6 bars weighs 300 g.
  • The box plus 8 bars weighs 350 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 6 equal bars (300 g) and the second as the same box with 8 bars (350 g). The box is identical in both pictures.
box+6 bars=300,box+8 bars=350\text{box} + 6\ \text{bars} = 300,\quad \text{box} + 8\ \text{bars} = 350
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 2 extra bars, so subtracting gives the weight of just those bars.
350300=50350 - 300 = 50
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 50 g are the weight of 2 identical bars, so split it into 2 equal parts.
50÷2=2550 \div 2 = 25
Equal bars share the extra weight equally, so one bar is 25 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 300 g is the box plus 6 bars. Those 6 bars weigh 150 g, so removing them leaves the box.
6×25=150,300150=1506 \times 25 = 150,\quad 300 - 150 = 150
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 150 g
4 · Reviewdoes it hold up?

Check both weighings: 150 + 6 x 25 = 300 and 150 + 8 x 25 = 350. Both match the numbers given.

Another way: Work from the second weighing instead: 350 - 200 = 150, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 50 by 2 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 2 easy answer: 125 g

A box holding 55 identical bars of soap weighs 300 g300\ \text{g}. After putting in 22 more identical bars of soap, the box weighs 370 g370\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 5 equal soap bars inside weighs 300 g. When 2 more equal bars are added, the same box now holds 7 bars and weighs 370 g. We need the weight of the empty box alone.

Givens
  • The box plus 5 bars weighs 300 g.
  • The box plus 7 bars weighs 370 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 5 equal bars (300 g) and the second as the same box with 7 bars (370 g). The box is identical in both pictures.
box+5 bars=300,box+7 bars=370\text{box} + 5\ \text{bars} = 300,\quad \text{box} + 7\ \text{bars} = 370
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 2 extra bars, so subtracting gives the weight of just those bars.
370300=70370 - 300 = 70
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 70 g are the weight of 2 identical bars, so split it into 2 equal parts.
70÷2=3570 \div 2 = 35
Equal bars share the extra weight equally, so one bar is 35 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 300 g is the box plus 5 bars. Those 5 bars weigh 175 g, so removing them leaves the box.
5×35=175,300175=1255 \times 35 = 175,\quad 300 - 175 = 125
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 125 g
4 · Reviewdoes it hold up?

Check both weighings: 125 + 5 x 35 = 300 and 125 + 7 x 35 = 370. Both match the numbers given.

Another way: Work from the second weighing instead: 370 - 245 = 125, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 70 by 2 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 3 easy answer: 140 g

A box holding 22 identical bars of soap weighs 260 g260\ \text{g}. After putting in 33 more identical bars of soap, the box weighs 440 g440\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 2 equal soap bars inside weighs 260 g. When 3 more equal bars are added, the same box now holds 5 bars and weighs 440 g. We need the weight of the empty box alone.

Givens
  • The box plus 2 bars weighs 260 g.
  • The box plus 5 bars weighs 440 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 2 equal bars (260 g) and the second as the same box with 5 bars (440 g). The box is identical in both pictures.
box+2 bars=260,box+5 bars=440\text{box} + 2\ \text{bars} = 260,\quad \text{box} + 5\ \text{bars} = 440
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 3 extra bars, so subtracting gives the weight of just those bars.
440260=180440 - 260 = 180
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 180 g are the weight of 3 identical bars, so split it into 3 equal parts.
180÷3=60180 \div 3 = 60
Equal bars share the extra weight equally, so one bar is 60 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 260 g is the box plus 2 bars. Those 2 bars weigh 120 g, so removing them leaves the box.
2×60=120,260120=1402 \times 60 = 120,\quad 260 - 120 = 140
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 140 g
4 · Reviewdoes it hold up?

Check both weighings: 140 + 2 x 60 = 260 and 140 + 5 x 60 = 440. Both match the numbers given.

Another way: Work from the second weighing instead: 440 - 300 = 140, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 180 by 3 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 4 easy answer: 190 g

A box holding 44 identical bars of soap weighs 370 g370\ \text{g}. After putting in 22 more identical bars of soap, the box weighs 460 g460\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 4 equal soap bars inside weighs 370 g. When 2 more equal bars are added, the same box now holds 6 bars and weighs 460 g. We need the weight of the empty box alone.

Givens
  • The box plus 4 bars weighs 370 g.
  • The box plus 6 bars weighs 460 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 4 equal bars (370 g) and the second as the same box with 6 bars (460 g). The box is identical in both pictures.
box+4 bars=370,box+6 bars=460\text{box} + 4\ \text{bars} = 370,\quad \text{box} + 6\ \text{bars} = 460
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 2 extra bars, so subtracting gives the weight of just those bars.
460370=90460 - 370 = 90
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 90 g are the weight of 2 identical bars, so split it into 2 equal parts.
90÷2=4590 \div 2 = 45
Equal bars share the extra weight equally, so one bar is 45 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 370 g is the box plus 4 bars. Those 4 bars weigh 180 g, so removing them leaves the box.
4×45=180,370180=1904 \times 45 = 180,\quad 370 - 180 = 190
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 190 g
4 · Reviewdoes it hold up?

Check both weighings: 190 + 4 x 45 = 370 and 190 + 6 x 45 = 460. Both match the numbers given.

Another way: Work from the second weighing instead: 460 - 270 = 190, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 90 by 2 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 5 medium answer: 195 g

A box holding 55 identical bars of soap weighs 395 g395\ \text{g}. After putting in 33 more identical bars of soap, the box weighs 515 g515\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 5 equal soap bars inside weighs 395 g. When 3 more equal bars are added, the same box now holds 8 bars and weighs 515 g. We need the weight of the empty box alone.

Givens
  • The box plus 5 bars weighs 395 g.
  • The box plus 8 bars weighs 515 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 5 equal bars (395 g) and the second as the same box with 8 bars (515 g). The box is identical in both pictures.
box+5 bars=395,box+8 bars=515\text{box} + 5\ \text{bars} = 395,\quad \text{box} + 8\ \text{bars} = 515
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 3 extra bars, so subtracting gives the weight of just those bars.
515395=120515 - 395 = 120
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 120 g are the weight of 3 identical bars, so split it into 3 equal parts.
120÷3=40120 \div 3 = 40
Equal bars share the extra weight equally, so one bar is 40 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 395 g is the box plus 5 bars. Those 5 bars weigh 200 g, so removing them leaves the box.
5×40=200,395200=1955 \times 40 = 200,\quad 395 - 200 = 195
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 195 g
4 · Reviewdoes it hold up?

Check both weighings: 195 + 5 x 40 = 395 and 195 + 8 x 40 = 515. Both match the numbers given.

Another way: Work from the second weighing instead: 515 - 320 = 195, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 120 by 3 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 6 medium answer: 210 g

A box holding 22 identical bars of soap weighs 320 g320\ \text{g}. After putting in 44 more identical bars of soap, the box weighs 540 g540\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 2 equal soap bars inside weighs 320 g. When 4 more equal bars are added, the same box now holds 6 bars and weighs 540 g. We need the weight of the empty box alone.

Givens
  • The box plus 2 bars weighs 320 g.
  • The box plus 6 bars weighs 540 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 2 equal bars (320 g) and the second as the same box with 6 bars (540 g). The box is identical in both pictures.
box+2 bars=320,box+6 bars=540\text{box} + 2\ \text{bars} = 320,\quad \text{box} + 6\ \text{bars} = 540
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 4 extra bars, so subtracting gives the weight of just those bars.
540320=220540 - 320 = 220
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 220 g are the weight of 4 identical bars, so split it into 4 equal parts.
220÷4=55220 \div 4 = 55
Equal bars share the extra weight equally, so one bar is 55 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 320 g is the box plus 2 bars. Those 2 bars weigh 110 g, so removing them leaves the box.
2×55=110,320110=2102 \times 55 = 110,\quad 320 - 110 = 210
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 210 g
4 · Reviewdoes it hold up?

Check both weighings: 210 + 2 x 55 = 320 and 210 + 6 x 55 = 540. Both match the numbers given.

Another way: Work from the second weighing instead: 540 - 330 = 210, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 220 by 4 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 7 medium answer: 230 g

A box holding 33 identical bars of soap weighs 455 g455\ \text{g}. After putting in 22 more identical bars of soap, the box weighs 605 g605\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 3 equal soap bars inside weighs 455 g. When 2 more equal bars are added, the same box now holds 5 bars and weighs 605 g. We need the weight of the empty box alone.

Givens
  • The box plus 3 bars weighs 455 g.
  • The box plus 5 bars weighs 605 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 3 equal bars (455 g) and the second as the same box with 5 bars (605 g). The box is identical in both pictures.
box+3 bars=455,box+5 bars=605\text{box} + 3\ \text{bars} = 455,\quad \text{box} + 5\ \text{bars} = 605
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 2 extra bars, so subtracting gives the weight of just those bars.
605455=150605 - 455 = 150
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 150 g are the weight of 2 identical bars, so split it into 2 equal parts.
150÷2=75150 \div 2 = 75
Equal bars share the extra weight equally, so one bar is 75 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 455 g is the box plus 3 bars. Those 3 bars weigh 225 g, so removing them leaves the box.
3×75=225,455225=2303 \times 75 = 225,\quad 455 - 225 = 230
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 230 g
4 · Reviewdoes it hold up?

Check both weighings: 230 + 3 x 75 = 455 and 230 + 5 x 75 = 605. Both match the numbers given.

Another way: Work from the second weighing instead: 605 - 375 = 230, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 150 by 2 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 8 medium answer: 220 g

A box holding 44 identical bars of soap weighs 420 g420\ \text{g}. After putting in 44 more identical bars of soap, the box weighs 620 g620\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 4 equal soap bars inside weighs 420 g. When 4 more equal bars are added, the same box now holds 8 bars and weighs 620 g. We need the weight of the empty box alone.

Givens
  • The box plus 4 bars weighs 420 g.
  • The box plus 8 bars weighs 620 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 4 equal bars (420 g) and the second as the same box with 8 bars (620 g). The box is identical in both pictures.
box+4 bars=420,box+8 bars=620\text{box} + 4\ \text{bars} = 420,\quad \text{box} + 8\ \text{bars} = 620
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 4 extra bars, so subtracting gives the weight of just those bars.
620420=200620 - 420 = 200
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 200 g are the weight of 4 identical bars, so split it into 4 equal parts.
200÷4=50200 \div 4 = 50
Equal bars share the extra weight equally, so one bar is 50 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 420 g is the box plus 4 bars. Those 4 bars weigh 200 g, so removing them leaves the box.
4×50=200,420200=2204 \times 50 = 200,\quad 420 - 200 = 220
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 220 g
4 · Reviewdoes it hold up?

Check both weighings: 220 + 4 x 50 = 420 and 220 + 8 x 50 = 620. Both match the numbers given.

Another way: Work from the second weighing instead: 620 - 400 = 220, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 200 by 4 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 9 hard answer: 175 g

A box holding 44 identical bars of soap weighs 435 g435\ \text{g}. After putting in 33 more identical bars of soap, the box weighs 630 g630\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 4 equal soap bars inside weighs 435 g. When 3 more equal bars are added, the same box now holds 7 bars and weighs 630 g. We need the weight of the empty box alone.

Givens
  • The box plus 4 bars weighs 435 g.
  • The box plus 7 bars weighs 630 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 4 equal bars (435 g) and the second as the same box with 7 bars (630 g). The box is identical in both pictures.
box+4 bars=435,box+7 bars=630\text{box} + 4\ \text{bars} = 435,\quad \text{box} + 7\ \text{bars} = 630
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 3 extra bars, so subtracting gives the weight of just those bars.
630435=195630 - 435 = 195
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 195 g are the weight of 3 identical bars, so split it into 3 equal parts.
195÷3=65195 \div 3 = 65
Equal bars share the extra weight equally, so one bar is 65 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 435 g is the box plus 4 bars. Those 4 bars weigh 260 g, so removing them leaves the box.
4×65=260,435260=1754 \times 65 = 260,\quad 435 - 260 = 175
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 175 g
4 · Reviewdoes it hold up?

Check both weighings: 175 + 4 x 65 = 435 and 175 + 7 x 65 = 630. Both match the numbers given.

Another way: Work from the second weighing instead: 630 - 455 = 175, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 195 by 3 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 10 hard answer: 240 g

A box holding 22 identical bars of soap weighs 480 g480\ \text{g}. After putting in 22 more identical bars of soap, the box weighs 720 g720\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 2 equal soap bars inside weighs 480 g. When 2 more equal bars are added, the same box now holds 4 bars and weighs 720 g. We need the weight of the empty box alone.

Givens
  • The box plus 2 bars weighs 480 g.
  • The box plus 4 bars weighs 720 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 2 equal bars (480 g) and the second as the same box with 4 bars (720 g). The box is identical in both pictures.
box+2 bars=480,box+4 bars=720\text{box} + 2\ \text{bars} = 480,\quad \text{box} + 4\ \text{bars} = 720
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 2 extra bars, so subtracting gives the weight of just those bars.
720480=240720 - 480 = 240
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 240 g are the weight of 2 identical bars, so split it into 2 equal parts.
240÷2=120240 \div 2 = 120
Equal bars share the extra weight equally, so one bar is 120 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 480 g is the box plus 2 bars. Those 2 bars weigh 240 g, so removing them leaves the box.
2×120=240,480240=2402 \times 120 = 240,\quad 480 - 240 = 240
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 240 g
4 · Reviewdoes it hold up?

Check both weighings: 240 + 2 x 120 = 480 and 240 + 4 x 120 = 720. Both match the numbers given.

Another way: Work from the second weighing instead: 720 - 480 = 240, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 240 by 2 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 11 hard answer: 260 g

A box holding 33 identical bars of soap weighs 500 g500\ \text{g}. After putting in 33 more identical bars of soap, the box weighs 740 g740\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 3 equal soap bars inside weighs 500 g. When 3 more equal bars are added, the same box now holds 6 bars and weighs 740 g. We need the weight of the empty box alone.

Givens
  • The box plus 3 bars weighs 500 g.
  • The box plus 6 bars weighs 740 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 3 equal bars (500 g) and the second as the same box with 6 bars (740 g). The box is identical in both pictures.
box+3 bars=500,box+6 bars=740\text{box} + 3\ \text{bars} = 500,\quad \text{box} + 6\ \text{bars} = 740
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 3 extra bars, so subtracting gives the weight of just those bars.
740500=240740 - 500 = 240
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 240 g are the weight of 3 identical bars, so split it into 3 equal parts.
240÷3=80240 \div 3 = 80
Equal bars share the extra weight equally, so one bar is 80 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 500 g is the box plus 3 bars. Those 3 bars weigh 240 g, so removing them leaves the box.
3×80=240,500240=2603 \times 80 = 240,\quad 500 - 240 = 260
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 260 g
4 · Reviewdoes it hold up?

Check both weighings: 260 + 3 x 80 = 500 and 260 + 6 x 80 = 740. Both match the numbers given.

Another way: Work from the second weighing instead: 740 - 480 = 260, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 240 by 3 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.
Variant 12 hard answer: 310 g

A box holding 33 identical bars of soap weighs 580 g580\ \text{g}. After putting in 22 more identical bars of soap, the box weighs 760 g760\ \text{g}. How many grams does the empty box weigh by itself?

Show solution
1 · Understandwhat's really being asked

A box with 3 equal soap bars inside weighs 580 g. When 2 more equal bars are added, the same box now holds 5 bars and weighs 760 g. We need the weight of the empty box alone.

Givens
  • The box plus 3 bars weighs 580 g.
  • The box plus 5 bars weighs 760 g.
  • Every bar of soap weighs the same.
Unknowns
  • The weight of the empty box.
Constraints
  • The same box is used in both weighings, so only the bars changed.
2 · Planchoose the strategy

#1 Draw a Diagram · also uses: #7 Identify Subproblems

Draw the two weighings side by side as a box plus a row of bars. Lining them up shows the only difference is the extra bars, so comparing the two totals cancels the box and leaves the bars alone.

3 · Execute4 carry out the plan

1Picture the two weighings

#1 Draw a Diagram 4.OA.A.3
Draw the first weighing as the box with 3 equal bars (580 g) and the second as the same box with 5 bars (760 g). The box is identical in both pictures.
box+3 bars=580,box+5 bars=760\text{box} + 3\ \text{bars} = 580,\quad \text{box} + 5\ \text{bars} = 760
Seeing the same box in both rows makes it clear its weight is shared and can be set aside.

2Compare to find the extra weight

#1 Draw a Diagram 4.OA.A.3
The second weighing is heavier only because of the 2 extra bars, so subtracting gives the weight of just those bars.
760580=180760 - 580 = 180
The box weight cancels when the two totals are compared, leaving only what changed.

3Find one bar's weight

#7 Identify Subproblems 5.NBT.B.6
Those 180 g are the weight of 2 identical bars, so split it into 2 equal parts.
180÷2=90180 \div 2 = 90
Equal bars share the extra weight equally, so one bar is 90 g.

4Find the box alone

#7 Identify Subproblems 4.OA.A.3
In the first weighing, 580 g is the box plus 3 bars. Those 3 bars weigh 270 g, so removing them leaves the box.
3×90=270,580270=3103 \times 90 = 270,\quad 580 - 270 = 310
Once one bar is known, the box is the total minus all the soap inside it.
Answer: 310 g
4 · Reviewdoes it hold up?

Check both weighings: 310 + 3 x 90 = 580 and 310 + 5 x 90 = 760. Both match the numbers given.

Another way: Work from the second weighing instead: 760 - 450 = 310, which gives the same box weight.

Standardsmin grade 5
  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Comparing two weighings and removing the known bars to reach the box weight.
  • 5.NBT.B.6 Find whole-number quotients with up to four-digit dividends and two-digit divisors — Dividing 180 by 2 to find the weight of one bar.
💡Takeaway. When the same thing sits in both weighings, compare them instead of solving each one: whatever is shared cancels out.