← Factor out a common factor with parentheses · Decompose a Number into Parts and Factors

Factor out a common factor with parentheses · 12 practice problems

5.OA.A.15.NBT.B.73.OA.B.5

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 1.25×(700+60+30)=987.51.25 \times (700 + 60 + 30) = 987.5

Rewrite the following as a simpler expression, then evaluate it.

125×7+12.5×6+1.25×30125 \times 7 + 12.5 \times 6 + 1.25 \times 30

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 125, 12.5 and 1.25 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 125 x 7 + 12.5 x 6 + 1.25 x 30.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 1.25 times a power of ten, so moving that power onto the other side of each product makes 1.25 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 1.25

#5 Look for a Pattern 5.NBT.B.7
125 is 1.25 times 100, 12.5 is 1.25 times 10, and 1.25 is 1.25 itself.
125=1.25×100,12.5=1.25×10125 = 1.25 \times 100,\quad 12.5 = 1.25 \times 10
The same digits, three places apart.

2Turn each product into 1.25 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
1.25×700+1.25×60+1.25×301.25 \times 700 + 1.25 \times 60 + 1.25 \times 30
Now 1.25 appears in every term.

3Factor out 1.25 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
1.25×(700+60+30)1.25 \times (700 + 60 + 30)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
1.25×790=987.51.25 \times 790 = 987.5
The value is 987.5.
Answer: 1.25×(700+60+30)=987.51.25 \times (700 + 60 + 30) = 987.5
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 875 + 75 + 37.5 = 987.5. The rewrite kept the value.

Another way: Factoring out 125 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 2 easy answer: 1.68×(600+40+25)=1117.21.68 \times (600 + 40 + 25) = 1117.2

Rewrite the following as a simpler expression, then evaluate it.

168×6+16.8×4+1.68×25168 \times 6 + 16.8 \times 4 + 1.68 \times 25

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 168, 16.8 and 1.68 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 168 x 6 + 16.8 x 4 + 1.68 x 25.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 1.68 times a power of ten, so moving that power onto the other side of each product makes 1.68 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 1.68

#5 Look for a Pattern 5.NBT.B.7
168 is 1.68 times 100, 16.8 is 1.68 times 10, and 1.68 is 1.68 itself.
168=1.68×100,16.8=1.68×10168 = 1.68 \times 100,\quad 16.8 = 1.68 \times 10
The same digits, three places apart.

2Turn each product into 1.68 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
1.68×600+1.68×40+1.68×251.68 \times 600 + 1.68 \times 40 + 1.68 \times 25
Now 1.68 appears in every term.

3Factor out 1.68 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
1.68×(600+40+25)1.68 \times (600 + 40 + 25)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
1.68×665=1117.21.68 \times 665 = 1117.2
The value is 1117.2.
Answer: 1.68×(600+40+25)=1117.21.68 \times (600 + 40 + 25) = 1117.2
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 1008 + 67.2 + 42 = 1117.2. The rewrite kept the value.

Another way: Factoring out 168 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 3 easy answer: 1.875×(900+60+15)=1828.1251.875 \times (900 + 60 + 15) = 1828.125

Rewrite the following as a simpler expression, then evaluate it.

187.5×9+18.75×6+1.875×15187.5 \times 9 + 18.75 \times 6 + 1.875 \times 15

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 187.5, 18.75 and 1.875 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 187.5 x 9 + 18.75 x 6 + 1.875 x 15.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 1.875 times a power of ten, so moving that power onto the other side of each product makes 1.875 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 1.875

#5 Look for a Pattern 5.NBT.B.7
187.5 is 1.875 times 100, 18.75 is 1.875 times 10, and 1.875 is 1.875 itself.
187.5=1.875×100,18.75=1.875×10187.5 = 1.875 \times 100,\quad 18.75 = 1.875 \times 10
The same digits, three places apart.

2Turn each product into 1.875 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
1.875×900+1.875×60+1.875×151.875 \times 900 + 1.875 \times 60 + 1.875 \times 15
Now 1.875 appears in every term.

3Factor out 1.875 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
1.875×(900+60+15)1.875 \times (900 + 60 + 15)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
1.875×975=1828.1251.875 \times 975 = 1828.125
The value is 1828.125.
Answer: 1.875×(900+60+15)=1828.1251.875 \times (900 + 60 + 15) = 1828.125
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 1687.5 + 112.5 + 28.125 = 1828.125. The rewrite kept the value.

Another way: Factoring out 187.5 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 4 easy answer: 2.175×(800+50+40)=1935.752.175 \times (800 + 50 + 40) = 1935.75

Rewrite the following as a simpler expression, then evaluate it.

217.5×8+21.75×5+2.175×40217.5 \times 8 + 21.75 \times 5 + 2.175 \times 40

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 217.5, 21.75 and 2.175 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 217.5 x 8 + 21.75 x 5 + 2.175 x 40.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 2.175 times a power of ten, so moving that power onto the other side of each product makes 2.175 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 2.175

#5 Look for a Pattern 5.NBT.B.7
217.5 is 2.175 times 100, 21.75 is 2.175 times 10, and 2.175 is 2.175 itself.
217.5=2.175×100,21.75=2.175×10217.5 = 2.175 \times 100,\quad 21.75 = 2.175 \times 10
The same digits, three places apart.

2Turn each product into 2.175 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
2.175×800+2.175×50+2.175×402.175 \times 800 + 2.175 \times 50 + 2.175 \times 40
Now 2.175 appears in every term.

3Factor out 2.175 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
2.175×(800+50+40)2.175 \times (800 + 50 + 40)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
2.175×890=1935.752.175 \times 890 = 1935.75
The value is 1935.75.
Answer: 2.175×(800+50+40)=1935.752.175 \times (800 + 50 + 40) = 1935.75
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 1740 + 108.75 + 87 = 1935.75. The rewrite kept the value.

Another way: Factoring out 217.5 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 5 medium answer: 2.64×(800+70+20)=2349.62.64 \times (800 + 70 + 20) = 2349.6

Rewrite the following as a simpler expression, then evaluate it.

264×8+26.4×7+2.64×20264 \times 8 + 26.4 \times 7 + 2.64 \times 20

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 264, 26.4 and 2.64 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 264 x 8 + 26.4 x 7 + 2.64 x 20.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 2.64 times a power of ten, so moving that power onto the other side of each product makes 2.64 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 2.64

#5 Look for a Pattern 5.NBT.B.7
264 is 2.64 times 100, 26.4 is 2.64 times 10, and 2.64 is 2.64 itself.
264=2.64×100,26.4=2.64×10264 = 2.64 \times 100,\quad 26.4 = 2.64 \times 10
The same digits, three places apart.

2Turn each product into 2.64 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
2.64×800+2.64×70+2.64×202.64 \times 800 + 2.64 \times 70 + 2.64 \times 20
Now 2.64 appears in every term.

3Factor out 2.64 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
2.64×(800+70+20)2.64 \times (800 + 70 + 20)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
2.64×890=2349.62.64 \times 890 = 2349.6
The value is 2349.6.
Answer: 2.64×(800+70+20)=2349.62.64 \times (800 + 70 + 20) = 2349.6
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 2112 + 184.8 + 52.8 = 2349.6. The rewrite kept the value.

Another way: Factoring out 264 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 6 medium answer: 2.925×(500+80+35)=1798.8752.925 \times (500 + 80 + 35) = 1798.875

Rewrite the following as a simpler expression, then evaluate it.

292.5×5+29.25×8+2.925×35292.5 \times 5 + 29.25 \times 8 + 2.925 \times 35

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 292.5, 29.25 and 2.925 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 292.5 x 5 + 29.25 x 8 + 2.925 x 35.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 2.925 times a power of ten, so moving that power onto the other side of each product makes 2.925 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 2.925

#5 Look for a Pattern 5.NBT.B.7
292.5 is 2.925 times 100, 29.25 is 2.925 times 10, and 2.925 is 2.925 itself.
292.5=2.925×100,29.25=2.925×10292.5 = 2.925 \times 100,\quad 29.25 = 2.925 \times 10
The same digits, three places apart.

2Turn each product into 2.925 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
2.925×500+2.925×80+2.925×352.925 \times 500 + 2.925 \times 80 + 2.925 \times 35
Now 2.925 appears in every term.

3Factor out 2.925 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
2.925×(500+80+35)2.925 \times (500 + 80 + 35)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
2.925×615=1798.8752.925 \times 615 = 1798.875
The value is 1798.875.
Answer: 2.925×(500+80+35)=1798.8752.925 \times (500 + 80 + 35) = 1798.875
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 1462.5 + 234 + 102.375 = 1798.875. The rewrite kept the value.

Another way: Factoring out 292.5 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 7 medium answer: 3.125×(700+30+45)=2421.8753.125 \times (700 + 30 + 45) = 2421.875

Rewrite the following as a simpler expression, then evaluate it.

312.5×7+31.25×3+3.125×45312.5 \times 7 + 31.25 \times 3 + 3.125 \times 45

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 312.5, 31.25 and 3.125 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 312.5 x 7 + 31.25 x 3 + 3.125 x 45.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 3.125 times a power of ten, so moving that power onto the other side of each product makes 3.125 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 3.125

#5 Look for a Pattern 5.NBT.B.7
312.5 is 3.125 times 100, 31.25 is 3.125 times 10, and 3.125 is 3.125 itself.
312.5=3.125×100,31.25=3.125×10312.5 = 3.125 \times 100,\quad 31.25 = 3.125 \times 10
The same digits, three places apart.

2Turn each product into 3.125 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
3.125×700+3.125×30+3.125×453.125 \times 700 + 3.125 \times 30 + 3.125 \times 45
Now 3.125 appears in every term.

3Factor out 3.125 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
3.125×(700+30+45)3.125 \times (700 + 30 + 45)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
3.125×775=2421.8753.125 \times 775 = 2421.875
The value is 2421.875.
Answer: 3.125×(700+30+45)=2421.8753.125 \times (700 + 30 + 45) = 2421.875
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 2187.5 + 93.75 + 140.625 = 2421.875. The rewrite kept the value.

Another way: Factoring out 312.5 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 8 medium answer: 3.6×(400+90+50)=19443.6 \times (400 + 90 + 50) = 1944

Rewrite the following as a simpler expression, then evaluate it.

360×4+36×9+3.6×50360 \times 4 + 36 \times 9 + 3.6 \times 50

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 360, 36 and 3.6 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 360 x 4 + 36 x 9 + 3.6 x 50.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 3.6 times a power of ten, so moving that power onto the other side of each product makes 3.6 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 3.6

#5 Look for a Pattern 5.NBT.B.7
360 is 3.6 times 100, 36 is 3.6 times 10, and 3.6 is 3.6 itself.
360=3.6×100,36=3.6×10360 = 3.6 \times 100,\quad 36 = 3.6 \times 10
The same digits, three places apart.

2Turn each product into 3.6 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
3.6×400+3.6×90+3.6×503.6 \times 400 + 3.6 \times 90 + 3.6 \times 50
Now 3.6 appears in every term.

3Factor out 3.6 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
3.6×(400+90+50)3.6 \times (400 + 90 + 50)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
3.6×540=19443.6 \times 540 = 1944
The value is 1944.
Answer: 3.6×(400+90+50)=19443.6 \times (400 + 90 + 50) = 1944
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 1440 + 324 + 180 = 1944. The rewrite kept the value.

Another way: Factoring out 360 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 9 hard answer: 4.234×(900+80+20)=42344.234 \times (900 + 80 + 20) = 4234

Rewrite the following as a simpler expression, then evaluate it.

423.4×9+42.34×8+4.234×20423.4 \times 9 + 42.34 \times 8 + 4.234 \times 20

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 423.4, 42.34 and 4.234 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 423.4 x 9 + 42.34 x 8 + 4.234 x 20.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 4.234 times a power of ten, so moving that power onto the other side of each product makes 4.234 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 4.234

#5 Look for a Pattern 5.NBT.B.7
423.4 is 4.234 times 100, 42.34 is 4.234 times 10, and 4.234 is 4.234 itself.
423.4=4.234×100,42.34=4.234×10423.4 = 4.234 \times 100,\quad 42.34 = 4.234 \times 10
The same digits, three places apart.

2Turn each product into 4.234 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
4.234×900+4.234×80+4.234×204.234 \times 900 + 4.234 \times 80 + 4.234 \times 20
Now 4.234 appears in every term.

3Factor out 4.234 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
4.234×(900+80+20)4.234 \times (900 + 80 + 20)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
4.234×1000=42344.234 \times 1000 = 4234
The value is 4234.
Answer: 4.234×(900+80+20)=42344.234 \times (900 + 80 + 20) = 4234
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 3810.6 + 338.72 + 84.68 = 4234. The rewrite kept the value.

Another way: Factoring out 423.4 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 10 hard answer: 4.4×(200+90+70)=15844.4 \times (200 + 90 + 70) = 1584

Rewrite the following as a simpler expression, then evaluate it.

440×2+44×9+4.4×70440 \times 2 + 44 \times 9 + 4.4 \times 70

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 440, 44 and 4.4 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 440 x 2 + 44 x 9 + 4.4 x 70.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 4.4 times a power of ten, so moving that power onto the other side of each product makes 4.4 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 4.4

#5 Look for a Pattern 5.NBT.B.7
440 is 4.4 times 100, 44 is 4.4 times 10, and 4.4 is 4.4 itself.
440=4.4×100,44=4.4×10440 = 4.4 \times 100,\quad 44 = 4.4 \times 10
The same digits, three places apart.

2Turn each product into 4.4 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
4.4×200+4.4×90+4.4×704.4 \times 200 + 4.4 \times 90 + 4.4 \times 70
Now 4.4 appears in every term.

3Factor out 4.4 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
4.4×(200+90+70)4.4 \times (200 + 90 + 70)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
4.4×360=15844.4 \times 360 = 1584
The value is 1584.
Answer: 4.4×(200+90+70)=15844.4 \times (200 + 90 + 70) = 1584
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 880 + 396 + 308 = 1584. The rewrite kept the value.

Another way: Factoring out 440 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 11 hard answer: 5.04×(300+70+60)=2167.25.04 \times (300 + 70 + 60) = 2167.2

Rewrite the following as a simpler expression, then evaluate it.

504×3+50.4×7+5.04×60504 \times 3 + 50.4 \times 7 + 5.04 \times 60

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 504, 50.4 and 5.04 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 504 x 3 + 50.4 x 7 + 5.04 x 60.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 5.04 times a power of ten, so moving that power onto the other side of each product makes 5.04 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 5.04

#5 Look for a Pattern 5.NBT.B.7
504 is 5.04 times 100, 50.4 is 5.04 times 10, and 5.04 is 5.04 itself.
504=5.04×100,50.4=5.04×10504 = 5.04 \times 100,\quad 50.4 = 5.04 \times 10
The same digits, three places apart.

2Turn each product into 5.04 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
5.04×300+5.04×70+5.04×605.04 \times 300 + 5.04 \times 70 + 5.04 \times 60
Now 5.04 appears in every term.

3Factor out 5.04 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
5.04×(300+70+60)5.04 \times (300 + 70 + 60)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
5.04×430=2167.25.04 \times 430 = 2167.2
The value is 2167.2.
Answer: 5.04×(300+70+60)=2167.25.04 \times (300 + 70 + 60) = 2167.2
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 1512 + 352.8 + 302.4 = 2167.2. The rewrite kept the value.

Another way: Factoring out 504 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.
Variant 12 hard answer: 5.25×(400+50+55)=2651.255.25 \times (400 + 50 + 55) = 2651.25

Rewrite the following as a simpler expression, then evaluate it.

525×4+52.5×5+5.25×55525 \times 4 + 52.5 \times 5 + 5.25 \times 55

Show solution
1 · Understandwhat's really being asked

Three products are added. Their first factors -- 525, 52.5 and 5.25 -- are the same digits with the decimal point in different places. We must simplify before evaluating.

Givens
  • The expression is 525 x 4 + 52.5 x 5 + 5.25 x 55.
  • The three first factors share their digits.
Unknowns
  • A simpler equivalent expression, and its value.
Constraints
  • The rewrite must keep the same value, not just a similar shape.
2 · Planchoose the strategy

#15 Organize Information in More Ways · also uses: #5 Look for a Pattern#7 Identify Subproblems

Nothing here is a common factor as written. But every first factor is 5.25 times a power of ten, so moving that power onto the other side of each product makes 5.25 common to all three.

3 · Execute4 carry out the plan

1Rewrite each decimal as a multiple of 5.25

#5 Look for a Pattern 5.NBT.B.7
525 is 5.25 times 100, 52.5 is 5.25 times 10, and 5.25 is 5.25 itself.
525=5.25×100,52.5=5.25×10525 = 5.25 \times 100,\quad 52.5 = 5.25 \times 10
The same digits, three places apart.

2Turn each product into 5.25 times a number

#7 Identify Subproblems 3.OA.B.5
Multiplication can be regrouped, so the power of ten joins the other factor.
5.25×400+5.25×50+5.25×555.25 \times 400 + 5.25 \times 50 + 5.25 \times 55
Now 5.25 appears in every term.

3Factor out 5.25 with parentheses

#15 Organize Information in More Ways 5.OA.A.1
The distributive law runs backwards here: a common factor comes out and the rest goes inside brackets.
5.25×(400+50+55)5.25 \times (400 + 50 + 55)
Three multiplications have become one.

4Add inside the parentheses, then multiply

#15 Organize Information in More Ways 5.NBT.B.7
The bracket is plain whole-number addition, and the final multiplication is by a round number.
5.25×505=2651.255.25 \times 505 = 2651.25
The value is 2651.25.
Answer: 5.25×(400+50+55)=2651.255.25 \times (400 + 50 + 55) = 2651.25
4 · Reviewdoes it hold up?

Evaluate the original directly as a check: 2100 + 262.5 + 288.75 = 2651.25. The rewrite kept the value.

Another way: Factoring out 525 instead works too, but leaves fractions of a hundredth inside the brackets; taking the smallest of the three keeps every number whole.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions and evaluate — Writing the factored form with parentheses and evaluating it.
  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Relating the three decimals by powers of ten and finishing the multiplication.
  • 3.OA.B.5 Apply properties of operations as strategies to multiply and divide — Regrouping each product so the shared factor can come out.
💡Takeaway. Numbers that look different can share a factor once you move the decimal point's worth onto the other side.