Operations & Word Problems

Depth · one concept from first principles · step 2 of 4

Match coefficients of like terms

The equation 3x(Bx+5)+A(Bx+5)=6x2+Cx−103x(Bx+5)+A(Bx+5)=6x^2+Cx-10 holds for every value of xx. Find the value of A+B+CA+B+C. (AA, BB, and CC are constants.)

AExpressions
Your answer
How to solve
Strategy Convert to Algebra — Expand the left side, sort it by powers of x, and set each coefficient equal to the matching one on the right. That turns one identity into three small equations.
1STEP 1

Expand the left side

Distribute 3x over (Bx+5) and A over (Bx+5).

3x(Bx+5)+A(Bx+5)=3Bx²+15x+ABx+5A
2STEP 2

Sort by powers of x

Collect the two x terms together; x × x = x² gives the square term.

3Bx²+(15+AB)x+5A
3STEP 3

Match the coefficients

Equal for every x means equal coefficients: x² with x², x with x, constant with constant.

3B=6, 15+AB=C, 5A=-10
4STEP 4

Solve the small equations

The first and last give B and A at once; then the middle one gives C.

B=2, A=-2, C=15+(-2) × 2=11
5STEP 5

Add them

Add the three constants.

A+B+C=-2+2+11=11
Answer
11
Put the values back: 3x(2x+5)-2(2x+5)=6x²+15x-4x-10=6x²+11x-10, which matches the right side with C=11.
Takeaway

If two polynomials are equal for every x, line up their terms and the unknowns fall out one by one.

  • Expand the left side
  • Sort by powers of x
  • Match the coefficients
  • Solve the small equations
  • Add them
Where next?
Another one like thissuggested

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