Numbers & Place Value

Depth · one concept from first principles · step 2 of 4

Fix the signs, then compare reciprocals

Three nonzero rational numbers xx, yy, zz satisfy x+y<0x+y<0, x−z<0x-z<0, z−y>0z-y>0, and x×y×z>0x \times y \times z>0. List the following numbers from greatest to least.

−1x,−1x+y,−1z,1x−z,0-\frac{1}{x},\quad -\frac{1}{x+y},\quad -\frac{1}{z},\quad \frac{1}{x-z},\quad 0

Number system
Your answer
How to solve
Strategy Identify Subproblems — Split the job in two. First decide the sign of each of x, y, z, ruling out the impossible sign patterns. Then sort the five numbers into positives, zero, and negatives, and compare only within each group, where a comparison of sizes is enough.
1STEP 1

z is the largest

x-z < 0 means x < z, and z-y > 0 means y < z.

2STEP 2

Decide the signs

A positive product has zero or two negatives. All positive breaks x+y < 0, so two are negative, and the largest, z, is the positive one.

z > 0, x < 0, y < 0
3STEP 3

Sort the five numbers by sign

Use x < 0, x+y < 0, z > 0, and x-z < 0.

-1/x > 0, -1/(x+y) > 0, -1/z < 0, 1/(x-z) < 0
4STEP 4

Compare the two positives

Since y < 0, adding it moves x further left: x+y < x < 0. So x+y has the larger size, and 1 over a larger size is smaller.

0 < -x < -(x+y) → -1/(x+y) < -1/x
5STEP 5

Compare the two negatives

Since x < 0, we have z-x > z > 0. Note 1/(x-z) = -1/(z-x), and 1/(z-x) < 1/z.

0 < z < z-x → -1/z < -1/(z-x)=1/(x-z)
Answer
-1/x, -1/(x+y), 0, 1/(x-z), -1/z
Test values that satisfy every condition: x=-1, y=-2, z=1 (then x+y=-3, x-z=-2, z-y=3, xyz=2). The five numbers become 1, 1/3, -1, -1/2, 0, and from greatest to least they read 1, 1/3, 0, -1/2, -1, matching the order found.
Takeaway

Signs first, sizes second: group the numbers by sign and only compare inside each group.

  • z is the largest
  • Decide the signs
  • Sort the five numbers by sign
  • Compare the two positives
  • Compare the two negatives
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