Numbers & Place Value

Depth · one concept from first principles · step 2 of 4

Recover missing digits from column carries

In the multiplication below, find the digits AA and BB.

A B×62 8 8\begin{array}{r} A\ B \\ \times\quad 6 \\ \hline 2\ 8\ 8 \end{array}

Here AA is the tens digit and BB is the ones digit of the two-digit number being multiplied. The two-digit number times 66 equals 288288.

Base-ten numbersOperations
Your answer
How to solve
Strategy Work Backwards — The result of the multiplication is given, so we undo it: dividing 288 by 6 recovers the two-digit number, and reading its digits gives A and B. A quick column check confirms the carry.
1STEP 1

Undo the multiplication

Since the two-digit number times 6 equals 288, divide 288 by 6 to recover the number.

288 ÷ 6 = 48
2STEP 2

Read off the digits

The recovered number is 48, so the tens digit A is 4 and the ones digit B is 8.

48 → A = 4, B = 8
3STEP 3

Check the column multiplication

Rebuild the product column by column to confirm 48 × 6 lands back on 288.

48 × 6 = 288
Answer
A = 4, B = 8
288 ÷ 6 = 48 → A = 4, B = 8
48 times 6 = 288 exactly, and both A=4 and B=8 are valid single digits with A not zero, so the two-digit number 48 is legitimate.
Takeaway

When you know the answer to a times problem, just divide to walk backwards to the hidden number, then read its digits!

  • Undo the multiplication
  • Read off the digits
  • Check the column multiplication
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