Geometry & Figures

Depth · one concept from first principles · step 2 of 4

Symmetry axis or center bisects corresponding-point segment

In the figure, line ℓ\ell is used as the axis of symmetry to draw a line-symmetric figure. If triangle ABC is an isosceles triangle, find the area of triangle ABC in cm2\text{cm}^2.

ℓ 30° 12 cm A B C
Geometry
Your answer
How to solve
Strategy Draw a Diagram — Drawing the reflection of B across the axis turns the slanted picture into a complete symmetric figure I can measure. Once the diagram shows the mirror image B', the work splits into small subproblems: first find the shape of triangle AB-B' (its apex angle is 30 + 30), then read off the height of triangle ABC as half of BB', then use the area formula.
1STEP 1

Reflect B across the axis

Reflect B across the axis to B'; symmetry keeps AB' equal to AB and opens the apex to 60 degrees.

∠ BAB' = 30^° + 30^° = 60^°
2STEP 2

Recognize the equilateral triangle

Two equal legs with a 60 degree apex force both base angles to 60, so BB' is also 12 cm.

(180^° - 60^°) ÷ 2 = 60^°, BB' = 12 cm
3STEP 3

Find the height of triangle ABC

The axis bisects BB', so B stands 12 divided by 2 = 6 cm from AC, which is the height.

12 ÷ 2 = 6 cm
4STEP 4

Compute the area

With base AC = 12 cm and height 6 cm, the area is 12 x 6 divided by 2 = 36 square cm.

12 × 6 ÷ 2 = 36 (cm²)
Answer
36 cm²
The base is 12 cm and the height is 6 cm, so the answer 36 cm² is half of the 72 cm² rectangle that would surround the triangle. The units are cm² (area), which is correct, and the size is sensible for a triangle with a 12 cm side.
Takeaway

A line of symmetry is a fold line: the matching point sits the same distance on the other side, so half of that mirror gap is your triangle's height.

  • Reflect B across the axis
  • Recognize the equilateral triangle
  • Find the height of triangle ABC
  • Compute the area
Where next?
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▶ Practice — 12 problems

The same shape shows up later on the AMC, as Paper Fold-and-Cut Symmetry. Why the shapes repeat →