← Measure an awkward leftover by subtracting what you can measure · Circumference and Area of a Circle

Measure an awkward leftover by subtracting what you can measure · 12 practice problems

7.G.B.46.G.A.1

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 13.76 cm²

The figure at the right is the top view of 4 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 12.56 cm12.56\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

4 equal circles are packed 2 by 2 inside a square. Each is 12.56 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 12.56 cm.
  • The circles are packed 2 by 2, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
12.56÷3.14=4,radius=212.56 \div 3.14 = 4,\quad \text{radius} = 2
Each circle is 4 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
2 circles sit side by side along it, each touching the next and the wall.
4×2=84 \times 2 = 8
The square is 8 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 4 circles.
8×8=64,12.56×4=50.248 \times 8 = 64,\quad 12.56 \times 4 = 50.24
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
6450.24=13.7664 - 50.24 = 13.76
13.76 cm2 is empty.
Answer: 13.76 cm²
4 · Reviewdoes it hold up?

The circles cover 50.24 of the square's 64 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 4 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 2 easy answer: 30.96 cm²

The figure at the right is the top view of 9 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 12.56 cm12.56\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

9 equal circles are packed 3 by 3 inside a square. Each is 12.56 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 12.56 cm.
  • The circles are packed 3 by 3, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
12.56÷3.14=4,radius=212.56 \div 3.14 = 4,\quad \text{radius} = 2
Each circle is 4 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
3 circles sit side by side along it, each touching the next and the wall.
4×3=124 \times 3 = 12
The square is 12 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 9 circles.
12×12=144,12.56×9=113.0412 \times 12 = 144,\quad 12.56 \times 9 = 113.04
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
144113.04=30.96144 - 113.04 = 30.96
30.96 cm2 is empty.
Answer: 30.96 cm²
4 · Reviewdoes it hold up?

The circles cover 113.04 of the square's 144 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 9 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 3 easy answer: 55.04 cm²

The figure at the right is the top view of 16 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 12.56 cm12.56\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

16 equal circles are packed 4 by 4 inside a square. Each is 12.56 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 12.56 cm.
  • The circles are packed 4 by 4, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
12.56÷3.14=4,radius=212.56 \div 3.14 = 4,\quad \text{radius} = 2
Each circle is 4 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
4 circles sit side by side along it, each touching the next and the wall.
4×4=164 \times 4 = 16
The square is 16 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 16 circles.
16×16=256,12.56×16=200.9616 \times 16 = 256,\quad 12.56 \times 16 = 200.96
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
256200.96=55.04256 - 200.96 = 55.04
55.04 cm2 is empty.
Answer: 55.04 cm²
4 · Reviewdoes it hold up?

The circles cover 200.96 of the square's 256 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 16 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 4 easy answer: 30.96 cm²

The figure at the right is the top view of 4 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 18.84 cm18.84\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

4 equal circles are packed 2 by 2 inside a square. Each is 18.84 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 18.84 cm.
  • The circles are packed 2 by 2, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
18.84÷3.14=6,radius=318.84 \div 3.14 = 6,\quad \text{radius} = 3
Each circle is 6 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
2 circles sit side by side along it, each touching the next and the wall.
6×2=126 \times 2 = 12
The square is 12 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 4 circles.
12×12=144,28.26×4=113.0412 \times 12 = 144,\quad 28.26 \times 4 = 113.04
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
144113.04=30.96144 - 113.04 = 30.96
30.96 cm2 is empty.
Answer: 30.96 cm²
4 · Reviewdoes it hold up?

The circles cover 113.04 of the square's 144 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 4 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 5 medium answer: 278.64 cm²

The figure at the right is the top view of 9 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 37.68 cm37.68\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

9 equal circles are packed 3 by 3 inside a square. Each is 37.68 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 37.68 cm.
  • The circles are packed 3 by 3, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
37.68÷3.14=12,radius=637.68 \div 3.14 = 12,\quad \text{radius} = 6
Each circle is 12 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
3 circles sit side by side along it, each touching the next and the wall.
12×3=3612 \times 3 = 36
The square is 36 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 9 circles.
36×36=1296,113.04×9=1017.3636 \times 36 = 1296,\quad 113.04 \times 9 = 1017.36
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
12961017.36=278.641296 - 1017.36 = 278.64
278.64 cm2 is empty.
Answer: 278.64 cm²
4 · Reviewdoes it hold up?

The circles cover 1017.36 of the square's 1296 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 9 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 6 medium answer: 168.56 cm²

The figure at the right is the top view of 4 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 43.96 cm43.96\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

4 equal circles are packed 2 by 2 inside a square. Each is 43.96 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 43.96 cm.
  • The circles are packed 2 by 2, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
43.96÷3.14=14,radius=743.96 \div 3.14 = 14,\quad \text{radius} = 7
Each circle is 14 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
2 circles sit side by side along it, each touching the next and the wall.
14×2=2814 \times 2 = 28
The square is 28 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 4 circles.
28×28=784,153.86×4=615.4428 \times 28 = 784,\quad 153.86 \times 4 = 615.44
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
784615.44=168.56784 - 615.44 = 168.56
168.56 cm2 is empty.
Answer: 168.56 cm²
4 · Reviewdoes it hold up?

The circles cover 615.44 of the square's 784 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 4 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 7 medium answer: 278.64 cm²

The figure at the right is the top view of 4 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 56.52 cm56.52\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

4 equal circles are packed 2 by 2 inside a square. Each is 56.52 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 56.52 cm.
  • The circles are packed 2 by 2, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
56.52÷3.14=18,radius=956.52 \div 3.14 = 18,\quad \text{radius} = 9
Each circle is 18 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
2 circles sit side by side along it, each touching the next and the wall.
18×2=3618 \times 2 = 36
The square is 36 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 4 circles.
36×36=1296,254.34×4=1017.3636 \times 36 = 1296,\quad 254.34 \times 4 = 1017.36
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
12961017.36=278.641296 - 1017.36 = 278.64
278.64 cm2 is empty.
Answer: 278.64 cm²
4 · Reviewdoes it hold up?

The circles cover 1017.36 of the square's 1296 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 4 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 8 medium answer: 1376 cm²

The figure at the right is the top view of 16 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 62.8 cm62.8\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

16 equal circles are packed 4 by 4 inside a square. Each is 62.8 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 62.8 cm.
  • The circles are packed 4 by 4, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
62.8÷3.14=20,radius=1062.8 \div 3.14 = 20,\quad \text{radius} = 10
Each circle is 20 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
4 circles sit side by side along it, each touching the next and the wall.
20×4=8020 \times 4 = 80
The square is 80 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 16 circles.
80×80=6400,314×16=502480 \times 80 = 6400,\quad 314 \times 16 = 5024
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
64005024=13766400 - 5024 = 1376
1376 cm2 is empty.
Answer: 1376 cm²
4 · Reviewdoes it hold up?

The circles cover 5024 of the square's 6400 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 16 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 9 hard answer: 936.54 cm²

The figure at the right is the top view of 9 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 69.08 cm69.08\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

9 equal circles are packed 3 by 3 inside a square. Each is 69.08 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 69.08 cm.
  • The circles are packed 3 by 3, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
69.08÷3.14=22,radius=1169.08 \div 3.14 = 22,\quad \text{radius} = 11
Each circle is 22 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
3 circles sit side by side along it, each touching the next and the wall.
22×3=6622 \times 3 = 66
The square is 66 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 9 circles.
66×66=4356,379.94×9=3419.4666 \times 66 = 4356,\quad 379.94 \times 9 = 3419.46
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
43563419.46=936.544356 - 3419.46 = 936.54
936.54 cm2 is empty.
Answer: 936.54 cm²
4 · Reviewdoes it hold up?

The circles cover 3419.46 of the square's 4356 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 9 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 10 hard answer: 1114.56 cm²

The figure at the right is the top view of 9 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 75.36 cm75.36\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

9 equal circles are packed 3 by 3 inside a square. Each is 75.36 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 75.36 cm.
  • The circles are packed 3 by 3, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
75.36÷3.14=24,radius=1275.36 \div 3.14 = 24,\quad \text{radius} = 12
Each circle is 24 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
3 circles sit side by side along it, each touching the next and the wall.
24×3=7224 \times 3 = 72
The square is 72 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 9 circles.
72×72=5184,452.16×9=4069.4472 \times 72 = 5184,\quad 452.16 \times 9 = 4069.44
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
51844069.44=1114.565184 - 4069.44 = 1114.56
1114.56 cm2 is empty.
Answer: 1114.56 cm²
4 · Reviewdoes it hold up?

The circles cover 4069.44 of the square's 5184 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 9 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 11 hard answer: 1517.04 cm²

The figure at the right is the top view of 9 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 87.92 cm87.92\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

9 equal circles are packed 3 by 3 inside a square. Each is 87.92 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 87.92 cm.
  • The circles are packed 3 by 3, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
87.92÷3.14=28,radius=1487.92 \div 3.14 = 28,\quad \text{radius} = 14
Each circle is 28 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
3 circles sit side by side along it, each touching the next and the wall.
28×3=8428 \times 3 = 84
The square is 84 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 9 circles.
84×84=7056,615.44×9=5538.9684 \times 84 = 7056,\quad 615.44 \times 9 = 5538.96
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
70565538.96=1517.047056 - 5538.96 = 1517.04
1517.04 cm2 is empty.
Answer: 1517.04 cm²
4 · Reviewdoes it hold up?

The circles cover 5538.96 of the square's 7056 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 9 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.
Variant 12 hard answer: 774 cm²

The figure at the right is the top view of 4 identical cylinders packed snugly into a square box; each cylinder's base has a circumference of 94.2 cm94.2\ \text{cm}. What is the area of the empty space, in cm2\text{cm}^2? (Ignore the thickness of the box.)

Show solution
1 · Understandwhat's really being asked

4 equal circles are packed 2 by 2 inside a square. Each is 94.2 cm round, and we want the area the circles leave empty.

Givens
  • Each circle's circumference is 94.2 cm.
  • The circles are packed 2 by 2, touching each other and the square.
Unknowns
  • The area of the empty space inside the square.
Constraints
  • The circles touch the square's sides, so the packing fixes the square's size.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #11 Work Backwards#7 Identify Subproblems

The empty space is a shape with no formula, so do not measure it directly. Measure the square and the circles, which both have formulas, and subtract.

3 · Execute4 carry out the plan

1Recover the circle from its circumference

#11 Work Backwards 7.G.B.4
Dividing the way round by 3.14 gives the diameter.
94.2÷3.14=30,radius=1594.2 \div 3.14 = 30,\quad \text{radius} = 15
Each circle is 30 cm across.

2Get the square's side

#7 Identify Subproblems 6.G.A.1
2 circles sit side by side along it, each touching the next and the wall.
30×2=6030 \times 2 = 60
The square is 60 cm on a side.

3Measure both shapes

#7 Identify Subproblems 7.G.B.4
The square, and then all 4 circles.
60×60=3600,706.5×4=282660 \times 60 = 3600,\quad 706.5 \times 4 = 2826
Two areas, both easy.

4Subtract

#16 Count the Complement 6.G.A.1
What is left of the square is the empty space.
36002826=7743600 - 2826 = 774
774 cm2 is empty.
Answer: 774 cm²
4 · Reviewdoes it hold up?

The circles cover 2826 of the square's 3600 cm2, about 78 percent -- which is what circles packed in a square always come to, whatever their size.

Another way: Working with one circle and its surrounding square first and multiplying by 4 gives the same answer, since the packing repeats.

Standardsmin grade 7
  • 7.G.B.4 Know the formulas for area and circumference of a circle — Going from circumference to diameter and then to area.
  • 6.G.A.1 Find area of triangles, quadrilaterals, polygons by composing/decomposing — Measuring the square and subtracting the circles.
💡Takeaway. When the shape you want has no formula, measure the shapes around it and take them away.