The right-angle mark makes the height a known number · 12 practice problems

EC is 13.9 cm out of BC's 15 cm, so the triangle really does sit inside the trapezoid, and its area 55.6 is one 2th of 111.2.

Another way: Writing it as one equation, $\text{EC} \times 8 \div 2 = 111.2 \div 2$, is the same reasoning without the named intermediate values.

EC is 2.6 cm out of BC's 14.4 cm, so the triangle really does sit inside the trapezoid, and its area 22.1 is one 8th of 176.8.

Another way: Writing it as one equation, $\text{EC} \times 17 \div 2 = 176.8 \div 8$, is the same reasoning without the named intermediate values.

EC is 4.28 cm out of BC's 13 cm, so the triangle really does sit inside the trapezoid, and its area 36.38 is one 5th of 181.9.

Another way: Writing it as one equation, $\text{EC} \times 17 \div 2 = 181.9 \div 5$, is the same reasoning without the named intermediate values.

EC is 7.6 cm out of BC's 18 cm, so the triangle really does sit inside the trapezoid, and its area 30.4 is one 4th of 121.6.

Another way: Writing it as one equation, $\text{EC} \times 8 \div 2 = 121.6 \div 4$, is the same reasoning without the named intermediate values.

EC is 6.08 cm out of BC's 18.6 cm, so the triangle really does sit inside the trapezoid, and its area 27.36 is one 5th of 136.8.

Another way: Writing it as one equation, $\text{EC} \times 9 \div 2 = 136.8 \div 5$, is the same reasoning without the named intermediate values.

EC is 15.3 cm out of BC's 16.8 cm, so the triangle really does sit inside the trapezoid, and its area 153 is one 2th of 306.

Another way: Writing it as one equation, $\text{EC} \times 20 \div 2 = 306 \div 2$, is the same reasoning without the named intermediate values.

EC is 2.04 cm out of BC's 17 cm, so the triangle really does sit inside the trapezoid, and its area 20.4 is one 15th of 306.

Another way: Writing it as one equation, $\text{EC} \times 20 \div 2 = 306 \div 15$, is the same reasoning without the named intermediate values.

EC is 1.86 cm out of BC's 21 cm, so the triangle really does sit inside the trapezoid, and its area 5.58 is one 20th of 111.6.

Another way: Writing it as one equation, $\text{EC} \times 6 \div 2 = 111.6 \div 20$, is the same reasoning without the named intermediate values.

EC is 7.52 cm out of BC's 21.6 cm, so the triangle really does sit inside the trapezoid, and its area 52.64 is one 5th of 263.2.

Another way: Writing it as one equation, $\text{EC} \times 14 \div 2 = 263.2 \div 5$, is the same reasoning without the named intermediate values.

EC is 7.12 cm out of BC's 20.2 cm, so the triangle really does sit inside the trapezoid, and its area 78.32 is one 5th of 391.6.

Another way: Writing it as one equation, $\text{EC} \times 22 \div 2 = 391.6 \div 5$, is the same reasoning without the named intermediate values.

EC is 18.3 cm out of BC's 22.6 cm, so the triangle really does sit inside the trapezoid, and its area 146.4 is one 2th of 292.8.

Another way: Writing it as one equation, $\text{EC} \times 16 \div 2 = 292.8 \div 2$, is the same reasoning without the named intermediate values.

EC is 4 cm out of BC's 11.8 cm, so the triangle really does sit inside the trapezoid, and its area 46 is one 5th of 230.

Another way: Writing it as one equation, $\text{EC} \times 23 \div 2 = 230 \div 5$, is the same reasoning without the named intermediate values.