← Find the constant skip-count step · Generalize a Growing Pattern into a Rule

Find the constant skip-count step · 10 practice problems

4.NBT.A.22.NBT.A.2

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Generated variants — 10

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has four evenly spaced tick marks. Reading from left to right, they are labeled $1200$ , $1210$ , $1220$ , $1230$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, four evenly spaced ticks read 1200, 1210, 1220, 1230 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 1200, 1210, 1220, 1230.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 1210 minus 1200 is 10. So one skip is 10.

1210 - 1200 = 10

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 10. Every gap is 10, so the skip-count step is 10.

1220 - 1210 = 10,\quad 1230 - 1220 = 10

If each evenly spaced jump is the same 10, the pattern is just counting by 10.

Answer: 10

4 · Reviewdoes it hold up?

Counting on by 10 from 1200 gives 1210, 1220, 1230, exactly the labels shown, so a step of 10 is correct.

Another way: Compare the first and last numbers: 1230 minus 1200 is 30, spread over 3 equal jumps, so each jump is 30 divided by 3, which is 10.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 2 easy

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has five evenly spaced tick marks. Reading from left to right, they are labeled $1111$ , $1121$ , $1131$ , $1141$ , $1151$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, five evenly spaced ticks read 1111, 1121, 1131, 1141, 1151 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 1111, 1121, 1131, 1141, 1151.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 1121 minus 1111 is 10. So one skip is 10.

1121 - 1111 = 10

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 10. Every gap is 10, so the skip-count step is 10.

1131 - 1121 = 10,\quad 1141 - 1131 = 10,\quad 1151 - 1141 = 10

If each evenly spaced jump is the same 10, the pattern is just counting by 10.

Answer: 10

4 · Reviewdoes it hold up?

Counting on by 10 from 1111 gives 1121, 1131, 1141, 1151, exactly the labels shown, so a step of 10 is correct.

Another way: Compare the first and last numbers: 1151 minus 1111 is 40, spread over 4 equal jumps, so each jump is 40 divided by 4, which is 10.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 3 easy

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has four evenly spaced tick marks. Reading from left to right, they are labeled $2500$ , $2700$ , $2900$ , $3100$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, four evenly spaced ticks read 2500, 2700, 2900, 3100 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 2500, 2700, 2900, 3100.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 2700 minus 2500 is 200. So one skip is 200.

2700 - 2500 = 200

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 200. Every gap is 200, so the skip-count step is 200.

2900 - 2700 = 200,\quad 3100 - 2900 = 200

If each evenly spaced jump is the same 200, the pattern is just counting by 200.

Answer: 200

4 · Reviewdoes it hold up?

Counting on by 200 from 2500 gives 2700, 2900, 3100, exactly the labels shown, so a step of 200 is correct.

Another way: Compare the first and last numbers: 3100 minus 2500 is 600, spread over 3 equal jumps, so each jump is 600 divided by 3, which is 200.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 4 medium

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has four evenly spaced tick marks. Reading from left to right, they are labeled $1000$ , $2000$ , $3000$ , $4000$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, four evenly spaced ticks read 1000, 2000, 3000, 4000 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 1000, 2000, 3000, 4000.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 2000 minus 1000 is 1000. So one skip is 1000.

2000 - 1000 = 1000

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 1000. Every gap is 1000, so the skip-count step is 1000.

3000 - 2000 = 1000,\quad 4000 - 3000 = 1000

If each evenly spaced jump is the same 1000, the pattern is just counting by 1000.

Answer: 1000

4 · Reviewdoes it hold up?

Counting on by 1000 from 1000 gives 2000, 3000, 4000, exactly the labels shown, so a step of 1000 is correct.

Another way: Compare the first and last numbers: 4000 minus 1000 is 3000, spread over 3 equal jumps, so each jump is 3000 divided by 3, which is 1000.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 5 medium

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has four evenly spaced tick marks. Reading from left to right, they are labeled $3829$ , $3929$ , $4029$ , $4129$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, four evenly spaced ticks read 3829, 3929, 4029, 4129 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 3829, 3929, 4029, 4129.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 3929 minus 3829 is 100. So one skip is 100.

3929 - 3829 = 100

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 100. Every gap is 100, so the skip-count step is 100.

4029 - 3929 = 100,\quad 4129 - 4029 = 100

If each evenly spaced jump is the same 100, the pattern is just counting by 100.

Answer: 100

4 · Reviewdoes it hold up?

Counting on by 100 from 3829 gives 3929, 4029, 4129, exactly the labels shown, so a step of 100 is correct.

Another way: Compare the first and last numbers: 4129 minus 3829 is 300, spread over 3 equal jumps, so each jump is 300 divided by 3, which is 100.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 6 medium

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has four evenly spaced tick marks. Reading from left to right, they are labeled $5230$ , $5280$ , $5330$ , $5380$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, four evenly spaced ticks read 5230, 5280, 5330, 5380 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 5230, 5280, 5330, 5380.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 5280 minus 5230 is 50. So one skip is 50.

5280 - 5230 = 50

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 50. Every gap is 50, so the skip-count step is 50.

5330 - 5280 = 50,\quad 5380 - 5330 = 50

If each evenly spaced jump is the same 50, the pattern is just counting by 50.

Answer: 50

4 · Reviewdoes it hold up?

Counting on by 50 from 5230 gives 5280, 5330, 5380, exactly the labels shown, so a step of 50 is correct.

Another way: Compare the first and last numbers: 5380 minus 5230 is 150, spread over 3 equal jumps, so each jump is 150 divided by 3, which is 50.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 7 medium

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has four evenly spaced tick marks. Reading from left to right, they are labeled $4060$ , $4560$ , $5060$ , $5560$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, four evenly spaced ticks read 4060, 4560, 5060, 5560 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 4060, 4560, 5060, 5560.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 4560 minus 4060 is 500. So one skip is 500.

4560 - 4060 = 500

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 500. Every gap is 500, so the skip-count step is 500.

5060 - 4560 = 500,\quad 5560 - 5060 = 500

If each evenly spaced jump is the same 500, the pattern is just counting by 500.

Answer: 500

4 · Reviewdoes it hold up?

Counting on by 500 from 4060 gives 4560, 5060, 5560, exactly the labels shown, so a step of 500 is correct.

Another way: Compare the first and last numbers: 5560 minus 4060 is 1500, spread over 3 equal jumps, so each jump is 1500 divided by 3, which is 500.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 8 hard

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has five evenly spaced tick marks. Reading from left to right, they are labeled $3015$ , $3115$ , $3215$ , $3315$ , $3415$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, five evenly spaced ticks read 3015, 3115, 3215, 3315, 3415 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 3015, 3115, 3215, 3315, 3415.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 3115 minus 3015 is 100. So one skip is 100.

3115 - 3015 = 100

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 100. Every gap is 100, so the skip-count step is 100.

3215 - 3115 = 100,\quad 3315 - 3215 = 100,\quad 3415 - 3315 = 100

If each evenly spaced jump is the same 100, the pattern is just counting by 100.

Answer: 100

4 · Reviewdoes it hold up?

Counting on by 100 from 3015 gives 3115, 3215, 3315, 3415, exactly the labels shown, so a step of 100 is correct.

Another way: Compare the first and last numbers: 3415 minus 3015 is 400, spread over 4 equal jumps, so each jump is 400 divided by 4, which is 100.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 9 hard

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has four evenly spaced tick marks. Reading from left to right, they are labeled $6400$ , $6600$ , $6800$ , $7000$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, four evenly spaced ticks read 6400, 6600, 6800, 7000 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 6400, 6600, 6800, 7000.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 6600 minus 6400 is 200. So one skip is 200.

6600 - 6400 = 200

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 200. Every gap is 200, so the skip-count step is 200.

6800 - 6600 = 200,\quad 7000 - 6800 = 200

If each evenly spaced jump is the same 200, the pattern is just counting by 200.

Answer: 200

4 · Reviewdoes it hold up?

Counting on by 200 from 6400 gives 6600, 6800, 7000, exactly the labels shown, so a step of 200 is correct.

Another way: Compare the first and last numbers: 7000 minus 6400 is 600, spread over 3 equal jumps, so each jump is 600 divided by 3, which is 200.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Variant 10 hard

The numbers below were made by skip-counting by $\bullet$ , shown on a number line. Find the value of $\bullet$ .

A number line has five evenly spaced tick marks. Reading from left to right, they are labeled $2008$ , $3008$ , $4008$ , $5008$ , $6008$ . The gap between each pair of neighboring numbers is the same, and the numbers were made by skip-counting by that amount.

Your answer

Show solution

1 · Understandwhat's really being asked

On a number line, five evenly spaced ticks read 2008, 3008, 4008, 5008, 6008 from left to right. The numbers were made by skip-counting by the same step each time. Find that step.

Givens

The labeled numbers, left to right, are 2008, 3008, 4008, 5008, 6008.
The ticks are evenly spaced, so the gap between neighbors is constant.
The numbers were made by skip-counting by that constant gap.

Unknowns

The size of each skip-count step (the value of the dot).

Constraints

Every neighboring pair differs by the same amount.

2 · Planchoose the strategy

#5 Look for a Pattern · also uses: #1 Draw a Diagram

Equally spaced numbers on a number line are a repeated-structure pattern, so I find the constant difference between two neighboring labels and confirm it repeats.

3 · Execute2 carry out the plan

1Find the gap between two neighbors

#5 Look for a Pattern 4.NBT.A.2

Subtract a number from the one just after it: 3008 minus 2008 is 1000. So one skip is 1000.

3008 - 2008 = 1000

The change from one tick to the next is exactly one skip, found by subtracting.

2Confirm the step repeats

#1 Draw a Diagram 2.NBT.A.2

Check the other gaps: each neighboring pair also differs by 1000. Every gap is 1000, so the skip-count step is 1000.

4008 - 3008 = 1000,\quad 5008 - 4008 = 1000,\quad 6008 - 5008 = 1000

If each evenly spaced jump is the same 1000, the pattern is just counting by 1000.

Answer: 1000

4 · Reviewdoes it hold up?

Counting on by 1000 from 2008 gives 3008, 4008, 5008, 6008, exactly the labels shown, so a step of 1000 is correct.

Another way: Compare the first and last numbers: 6008 minus 2008 is 4000, spread over 4 equal jumps, so each jump is 4000 divided by 4, which is 1000.

Standardsmin grade 4

4.NBT.A.2 Read and write multi-digit whole numbers and compare using symbols — Subtracting neighboring multi-digit labels to find the constant gap.
2.NBT.A.2 Count within 1000, skip-count by 5s, 10s, and 100s — Recognizing the evenly spaced labels as skip-counting by a fixed step.

💡Takeaway. Subtract one tick from the next and you've found the skip size!

Where next?

← Back to the problem: Find the constant skip-count step