← Product of two numbers equals GCF times LCM · Divisibility and Remainder Reasoning

Product of two numbers equals GCF times LCM · 12 practice problems

6.NS.B.46.NS.B.2

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 40

A certain number and 2424 have a greatest common factor of 88 and a least common multiple of 120120. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 24. Paired with a hidden number, their greatest common factor is 8 and their least common multiple is 120. We need the hidden number.

Givens
  • One of the two numbers is 24.
  • Their greatest common factor is 8.
  • Their least common multiple is 120.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 8, since 8 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 8 times 120.
24×=8×120=96024 \times \square = 8 \times 120 = 960
The two numbers multiply to 960.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 960 by the number we know.
960÷24=40960 \div 24 = 40
The hidden number is 40.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 40 and 24 really do have that greatest common factor and least common multiple.
gcd(40,24)=8,lcm(40,24)=120\gcd(40, 24) = 8,\quad \operatorname{lcm}(40, 24) = 120
Both conditions hold, so the answer is confirmed.
Answer: 40
4 · Reviewdoes it hold up?

40 is a multiple of 8, as it must be, and 40 divides 120 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 8 times something: 24 is 8 x 3, so the other is 8 x 5 where 3 and 5 share no factor. That gives 40 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 960 by 24 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 2 easy answer: 42

A certain number and 2424 have a greatest common factor of 66 and a least common multiple of 168168. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 24. Paired with a hidden number, their greatest common factor is 6 and their least common multiple is 168. We need the hidden number.

Givens
  • One of the two numbers is 24.
  • Their greatest common factor is 6.
  • Their least common multiple is 168.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 6, since 6 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 6 times 168.
24×=6×168=100824 \times \square = 6 \times 168 = 1008
The two numbers multiply to 1008.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 1008 by the number we know.
1008÷24=421008 \div 24 = 42
The hidden number is 42.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 42 and 24 really do have that greatest common factor and least common multiple.
gcd(42,24)=6,lcm(42,24)=168\gcd(42, 24) = 6,\quad \operatorname{lcm}(42, 24) = 168
Both conditions hold, so the answer is confirmed.
Answer: 42
4 · Reviewdoes it hold up?

42 is a multiple of 6, as it must be, and 42 divides 168 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 6 times something: 24 is 6 x 4, so the other is 6 x 7 where 4 and 7 share no factor. That gives 42 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 1008 by 24 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 3 easy answer: 60

A certain number and 3636 have a greatest common factor of 1212 and a least common multiple of 180180. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 36. Paired with a hidden number, their greatest common factor is 12 and their least common multiple is 180. We need the hidden number.

Givens
  • One of the two numbers is 36.
  • Their greatest common factor is 12.
  • Their least common multiple is 180.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 12, since 12 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 12 times 180.
36×=12×180=216036 \times \square = 12 \times 180 = 2160
The two numbers multiply to 2160.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 2160 by the number we know.
2160÷36=602160 \div 36 = 60
The hidden number is 60.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 60 and 36 really do have that greatest common factor and least common multiple.
gcd(60,36)=12,lcm(60,36)=180\gcd(60, 36) = 12,\quad \operatorname{lcm}(60, 36) = 180
Both conditions hold, so the answer is confirmed.
Answer: 60
4 · Reviewdoes it hold up?

60 is a multiple of 12, as it must be, and 60 divides 180 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 12 times something: 36 is 12 x 3, so the other is 12 x 5 where 3 and 5 share no factor. That gives 60 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 2160 by 36 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 4 easy answer: 36

A certain number and 4545 have a greatest common factor of 99 and a least common multiple of 180180. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 45. Paired with a hidden number, their greatest common factor is 9 and their least common multiple is 180. We need the hidden number.

Givens
  • One of the two numbers is 45.
  • Their greatest common factor is 9.
  • Their least common multiple is 180.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 9, since 9 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 9 times 180.
45×=9×180=162045 \times \square = 9 \times 180 = 1620
The two numbers multiply to 1620.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 1620 by the number we know.
1620÷45=361620 \div 45 = 36
The hidden number is 36.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 36 and 45 really do have that greatest common factor and least common multiple.
gcd(36,45)=9,lcm(36,45)=180\gcd(36, 45) = 9,\quad \operatorname{lcm}(36, 45) = 180
Both conditions hold, so the answer is confirmed.
Answer: 36
4 · Reviewdoes it hold up?

36 is a multiple of 9, as it must be, and 36 divides 180 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 9 times something: 45 is 9 x 5, so the other is 9 x 4 where 5 and 4 share no factor. That gives 36 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 1620 by 45 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 5 medium answer: 90

A certain number and 3636 have a greatest common factor of 1818 and a least common multiple of 180180. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 36. Paired with a hidden number, their greatest common factor is 18 and their least common multiple is 180. We need the hidden number.

Givens
  • One of the two numbers is 36.
  • Their greatest common factor is 18.
  • Their least common multiple is 180.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 18, since 18 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 18 times 180.
36×=18×180=324036 \times \square = 18 \times 180 = 3240
The two numbers multiply to 3240.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 3240 by the number we know.
3240÷36=903240 \div 36 = 90
The hidden number is 90.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 90 and 36 really do have that greatest common factor and least common multiple.
gcd(90,36)=18,lcm(90,36)=180\gcd(90, 36) = 18,\quad \operatorname{lcm}(90, 36) = 180
Both conditions hold, so the answer is confirmed.
Answer: 90
4 · Reviewdoes it hold up?

90 is a multiple of 18, as it must be, and 90 divides 180 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 18 times something: 36 is 18 x 2, so the other is 18 x 5 where 2 and 5 share no factor. That gives 90 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 3240 by 36 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 6 medium answer: 105

A certain number and 3030 have a greatest common factor of 1515 and a least common multiple of 210210. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 30. Paired with a hidden number, their greatest common factor is 15 and their least common multiple is 210. We need the hidden number.

Givens
  • One of the two numbers is 30.
  • Their greatest common factor is 15.
  • Their least common multiple is 210.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 15, since 15 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 15 times 210.
30×=15×210=315030 \times \square = 15 \times 210 = 3150
The two numbers multiply to 3150.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 3150 by the number we know.
3150÷30=1053150 \div 30 = 105
The hidden number is 105.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 105 and 30 really do have that greatest common factor and least common multiple.
gcd(105,30)=15,lcm(105,30)=210\gcd(105, 30) = 15,\quad \operatorname{lcm}(105, 30) = 210
Both conditions hold, so the answer is confirmed.
Answer: 105
4 · Reviewdoes it hold up?

105 is a multiple of 15, as it must be, and 105 divides 210 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 15 times something: 30 is 15 x 2, so the other is 15 x 7 where 2 and 7 share no factor. That gives 105 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 3150 by 30 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 7 medium answer: 70

A certain number and 3030 have a greatest common factor of 1010 and a least common multiple of 210210. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 30. Paired with a hidden number, their greatest common factor is 10 and their least common multiple is 210. We need the hidden number.

Givens
  • One of the two numbers is 30.
  • Their greatest common factor is 10.
  • Their least common multiple is 210.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 10, since 10 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 10 times 210.
30×=10×210=210030 \times \square = 10 \times 210 = 2100
The two numbers multiply to 2100.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 2100 by the number we know.
2100÷30=702100 \div 30 = 70
The hidden number is 70.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 70 and 30 really do have that greatest common factor and least common multiple.
gcd(70,30)=10,lcm(70,30)=210\gcd(70, 30) = 10,\quad \operatorname{lcm}(70, 30) = 210
Both conditions hold, so the answer is confirmed.
Answer: 70
4 · Reviewdoes it hold up?

70 is a multiple of 10, as it must be, and 70 divides 210 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 10 times something: 30 is 10 x 3, so the other is 10 x 7 where 3 and 7 share no factor. That gives 70 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 2100 by 30 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 8 medium answer: 70

A certain number and 4242 have a greatest common factor of 1414 and a least common multiple of 210210. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 42. Paired with a hidden number, their greatest common factor is 14 and their least common multiple is 210. We need the hidden number.

Givens
  • One of the two numbers is 42.
  • Their greatest common factor is 14.
  • Their least common multiple is 210.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 14, since 14 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 14 times 210.
42×=14×210=294042 \times \square = 14 \times 210 = 2940
The two numbers multiply to 2940.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 2940 by the number we know.
2940÷42=702940 \div 42 = 70
The hidden number is 70.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 70 and 42 really do have that greatest common factor and least common multiple.
gcd(70,42)=14,lcm(70,42)=210\gcd(70, 42) = 14,\quad \operatorname{lcm}(70, 42) = 210
Both conditions hold, so the answer is confirmed.
Answer: 70
4 · Reviewdoes it hold up?

70 is a multiple of 14, as it must be, and 70 divides 210 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 14 times something: 42 is 14 x 3, so the other is 14 x 5 where 3 and 5 share no factor. That gives 70 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 2940 by 42 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 9 hard answer: 63

A certain number and 2828 have a greatest common factor of 77 and a least common multiple of 252252. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 28. Paired with a hidden number, their greatest common factor is 7 and their least common multiple is 252. We need the hidden number.

Givens
  • One of the two numbers is 28.
  • Their greatest common factor is 7.
  • Their least common multiple is 252.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 7, since 7 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 7 times 252.
28×=7×252=176428 \times \square = 7 \times 252 = 1764
The two numbers multiply to 1764.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 1764 by the number we know.
1764÷28=631764 \div 28 = 63
The hidden number is 63.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 63 and 28 really do have that greatest common factor and least common multiple.
gcd(63,28)=7,lcm(63,28)=252\gcd(63, 28) = 7,\quad \operatorname{lcm}(63, 28) = 252
Both conditions hold, so the answer is confirmed.
Answer: 63
4 · Reviewdoes it hold up?

63 is a multiple of 7, as it must be, and 63 divides 252 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 7 times something: 28 is 7 x 4, so the other is 7 x 9 where 4 and 9 share no factor. That gives 63 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 1764 by 28 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 10 hard answer: 88

A certain number and 3333 have a greatest common factor of 1111 and a least common multiple of 264264. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 33. Paired with a hidden number, their greatest common factor is 11 and their least common multiple is 264. We need the hidden number.

Givens
  • One of the two numbers is 33.
  • Their greatest common factor is 11.
  • Their least common multiple is 264.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 11, since 11 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 11 times 264.
33×=11×264=290433 \times \square = 11 \times 264 = 2904
The two numbers multiply to 2904.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 2904 by the number we know.
2904÷33=882904 \div 33 = 88
The hidden number is 88.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 88 and 33 really do have that greatest common factor and least common multiple.
gcd(88,33)=11,lcm(88,33)=264\gcd(88, 33) = 11,\quad \operatorname{lcm}(88, 33) = 264
Both conditions hold, so the answer is confirmed.
Answer: 88
4 · Reviewdoes it hold up?

88 is a multiple of 11, as it must be, and 88 divides 264 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 11 times something: 33 is 11 x 3, so the other is 11 x 8 where 3 and 8 share no factor. That gives 88 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 2904 by 33 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 11 hard answer: 72

A certain number and 120120 have a greatest common factor of 2424 and a least common multiple of 360360. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 120. Paired with a hidden number, their greatest common factor is 24 and their least common multiple is 360. We need the hidden number.

Givens
  • One of the two numbers is 120.
  • Their greatest common factor is 24.
  • Their least common multiple is 360.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 24, since 24 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 24 times 360.
120×=24×360=8640120 \times \square = 24 \times 360 = 8640
The two numbers multiply to 8640.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 8640 by the number we know.
8640÷120=728640 \div 120 = 72
The hidden number is 72.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 72 and 120 really do have that greatest common factor and least common multiple.
gcd(72,120)=24,lcm(72,120)=360\gcd(72, 120) = 24,\quad \operatorname{lcm}(72, 120) = 360
Both conditions hold, so the answer is confirmed.
Answer: 72
4 · Reviewdoes it hold up?

72 is a multiple of 24, as it must be, and 72 divides 360 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 24 times something: 120 is 24 x 5, so the other is 24 x 3 where 5 and 3 share no factor. That gives 72 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 8640 by 120 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.
Variant 12 hard answer: 140

A certain number and 6060 have a greatest common factor of 2020 and a least common multiple of 420420. Find the number.

Show solution
1 · Understandwhat's really being asked

One number is 60. Paired with a hidden number, their greatest common factor is 20 and their least common multiple is 420. We need the hidden number.

Givens
  • One of the two numbers is 60.
  • Their greatest common factor is 20.
  • Their least common multiple is 420.
Unknowns
  • The other number.
Constraints
  • Both numbers are multiples of 20, since 20 divides both.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #5 Look for a Pattern#6 Guess and Check

Try a small pair where the gcf and lcm are easy to see, notice how they relate to the product, then use that relationship on the numbers given.

3 · Execute5 carry out the plan

1Discover the rule with a small pair

#9 Solve an Easier Related Problem 6.NS.B.4
Take 4 and 6: their greatest common factor is 2 and their least common multiple is 12. Compare 2 times 12 with 4 times 6.
2×12=24,4×6=242 \times 12 = 24,\quad 4 \times 6 = 24
The two products came out the same. That is not a coincidence.

2State the pattern

#5 Look for a Pattern 6.NS.B.4
For any two numbers, multiplying the greatest common factor by the least common multiple gives the same answer as multiplying the two numbers.
a×b=gcd(a,b)×lcm(a,b)a \times b = \gcd(a, b) \times \operatorname{lcm}(a, b)
The gcf holds the shared factors and the lcm holds the rest, so together they account for every factor exactly once each.

3Plug in the known values

#9 Solve an Easier Related Problem 6.NS.B.4
The right-hand side is fully known: 20 times 420.
60×=20×420=840060 \times \square = 20 \times 420 = 8400
The two numbers multiply to 8400.

4Find the missing number

#9 Solve an Easier Related Problem 6.NS.B.2
Divide 8400 by the number we know.
8400÷60=1408400 \div 60 = 140
The hidden number is 140.

5Check the candidate by guess and check

#6 Guess and Check 6.NS.B.4
Verify directly that 140 and 60 really do have that greatest common factor and least common multiple.
gcd(140,60)=20,lcm(140,60)=420\gcd(140, 60) = 20,\quad \operatorname{lcm}(140, 60) = 420
Both conditions hold, so the answer is confirmed.
Answer: 140
4 · Reviewdoes it hold up?

140 is a multiple of 20, as it must be, and 140 divides 420 -- both are necessary for the stated gcf and lcm.

Another way: Write both as 20 times something: 60 is 20 x 3, so the other is 20 x 7 where 3 and 7 share no factor. That gives 140 without the product rule.

Standardsmin grade 6
  • 6.NS.B.4 Find greatest common factor and least common multiple of two numbers — Relating the greatest common factor and least common multiple to the product of the two numbers.
  • 6.NS.B.2 Fluently divide multi-digit numbers using the standard algorithm — Dividing 8400 by 60 to recover the missing number.
💡Takeaway. The greatest common factor and the least common multiple multiply to the same thing the two numbers do -- so any three of the four give you the fourth.