← Cutting the same from both leaves the difference untouched · Find Two Unknowns from Sum and Difference

Cutting the same from both leaves the difference untouched · 12 practice problems

7.EE.B.46.EE.B.6

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 21 cm

String A is 24 cm24\ \text{cm} long and string B is 26 cm26\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 3:53 : 5. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 24 cm and 26 cm, each lose the same length, and what is left is in the ratio 3 to 5. We want the length cut off.

Givens
  • String A is 24 cm and string B is 26 cm.
  • The same length is cut from each.
  • What remains is in the ratio 3 to 5.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
2624=226 - 24 = 2
Still 2 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 3 to 5, the gap is 2 parts.
53=25 - 3 = 2
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
2 parts come to 2 cm.
2÷2=12 \div 2 = 1
Each part is 1 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 3 parts, so the rest of its 24 cm was cut off.
241×3=2124 - 1 \times 3 = 21
21 cm was cut from each.
Answer: 21 cm
4 · Reviewdoes it hold up?

After cutting 21 cm the strings are 3 cm and 5 cm -- still 2 cm apart, and in the ratio 3 to 5.

Another way: Following string B instead gives 26 minus 21, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 2 easy answer: 15 cm

String A is 27 cm27\ \text{cm} long and string B is 30 cm30\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 4:54 : 5. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 27 cm and 30 cm, each lose the same length, and what is left is in the ratio 4 to 5. We want the length cut off.

Givens
  • String A is 27 cm and string B is 30 cm.
  • The same length is cut from each.
  • What remains is in the ratio 4 to 5.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
3027=330 - 27 = 3
Still 3 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 4 to 5, the gap is 1 part.
54=15 - 4 = 1
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
1 part come to 3 cm.
3÷1=33 \div 1 = 3
Each part is 3 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 4 parts, so the rest of its 27 cm was cut off.
273×4=1527 - 3 \times 4 = 15
15 cm was cut from each.
Answer: 15 cm
4 · Reviewdoes it hold up?

After cutting 15 cm the strings are 12 cm and 15 cm -- still 3 cm apart, and in the ratio 4 to 5.

Another way: Following string B instead gives 30 minus 15, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 3 easy answer: 16 cm

String A is 23 cm23\ \text{cm} long and string B is 37 cm37\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 1:31 : 3. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 23 cm and 37 cm, each lose the same length, and what is left is in the ratio 1 to 3. We want the length cut off.

Givens
  • String A is 23 cm and string B is 37 cm.
  • The same length is cut from each.
  • What remains is in the ratio 1 to 3.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
3723=1437 - 23 = 14
Still 14 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 1 to 3, the gap is 2 parts.
31=23 - 1 = 2
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
2 parts come to 14 cm.
14÷2=714 \div 2 = 7
Each part is 7 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 1 part, so the rest of its 23 cm was cut off.
237×1=1623 - 7 \times 1 = 16
16 cm was cut from each.
Answer: 16 cm
4 · Reviewdoes it hold up?

After cutting 16 cm the strings are 7 cm and 21 cm -- still 14 cm apart, and in the ratio 1 to 3.

Another way: Following string B instead gives 37 minus 16, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 4 easy answer: 22 cm

String A is 29 cm29\ \text{cm} long and string B is 43 cm43\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 1:31 : 3. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 29 cm and 43 cm, each lose the same length, and what is left is in the ratio 1 to 3. We want the length cut off.

Givens
  • String A is 29 cm and string B is 43 cm.
  • The same length is cut from each.
  • What remains is in the ratio 1 to 3.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
4329=1443 - 29 = 14
Still 14 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 1 to 3, the gap is 2 parts.
31=23 - 1 = 2
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
2 parts come to 14 cm.
14÷2=714 \div 2 = 7
Each part is 7 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 1 part, so the rest of its 29 cm was cut off.
297×1=2229 - 7 \times 1 = 22
22 cm was cut from each.
Answer: 22 cm
4 · Reviewdoes it hold up?

After cutting 22 cm the strings are 7 cm and 21 cm -- still 14 cm apart, and in the ratio 1 to 3.

Another way: Following string B instead gives 43 minus 22, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 5 medium answer: 2 cm

String A is 35 cm35\ \text{cm} long and string B is 46 cm46\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 3:43 : 4. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 35 cm and 46 cm, each lose the same length, and what is left is in the ratio 3 to 4. We want the length cut off.

Givens
  • String A is 35 cm and string B is 46 cm.
  • The same length is cut from each.
  • What remains is in the ratio 3 to 4.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
4635=1146 - 35 = 11
Still 11 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 3 to 4, the gap is 1 part.
43=14 - 3 = 1
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
1 part come to 11 cm.
11÷1=1111 \div 1 = 11
Each part is 11 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 3 parts, so the rest of its 35 cm was cut off.
3511×3=235 - 11 \times 3 = 2
2 cm was cut from each.
Answer: 2 cm
4 · Reviewdoes it hold up?

After cutting 2 cm the strings are 33 cm and 44 cm -- still 11 cm apart, and in the ratio 3 to 4.

Another way: Following string B instead gives 46 minus 2, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 6 medium answer: 20 cm

String A is 30 cm30\ \text{cm} long and string B is 50 cm50\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 1:31 : 3. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 30 cm and 50 cm, each lose the same length, and what is left is in the ratio 1 to 3. We want the length cut off.

Givens
  • String A is 30 cm and string B is 50 cm.
  • The same length is cut from each.
  • What remains is in the ratio 1 to 3.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
5030=2050 - 30 = 20
Still 20 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 1 to 3, the gap is 2 parts.
31=23 - 1 = 2
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
2 parts come to 20 cm.
20÷2=1020 \div 2 = 10
Each part is 10 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 1 part, so the rest of its 30 cm was cut off.
3010×1=2030 - 10 \times 1 = 20
20 cm was cut from each.
Answer: 20 cm
4 · Reviewdoes it hold up?

After cutting 20 cm the strings are 10 cm and 30 cm -- still 20 cm apart, and in the ratio 1 to 3.

Another way: Following string B instead gives 50 minus 20, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 7 medium answer: 40 cm

String A is 49 cm49\ \text{cm} long and string B is 52 cm52\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 3:43 : 4. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 49 cm and 52 cm, each lose the same length, and what is left is in the ratio 3 to 4. We want the length cut off.

Givens
  • String A is 49 cm and string B is 52 cm.
  • The same length is cut from each.
  • What remains is in the ratio 3 to 4.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
5249=352 - 49 = 3
Still 3 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 3 to 4, the gap is 1 part.
43=14 - 3 = 1
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
1 part come to 3 cm.
3÷1=33 \div 1 = 3
Each part is 3 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 3 parts, so the rest of its 49 cm was cut off.
493×3=4049 - 3 \times 3 = 40
40 cm was cut from each.
Answer: 40 cm
4 · Reviewdoes it hold up?

After cutting 40 cm the strings are 9 cm and 12 cm -- still 3 cm apart, and in the ratio 3 to 4.

Another way: Following string B instead gives 52 minus 40, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 8 medium answer: 16 cm

String A is 44 cm44\ \text{cm} long and string B is 58 cm58\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 2:32 : 3. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 44 cm and 58 cm, each lose the same length, and what is left is in the ratio 2 to 3. We want the length cut off.

Givens
  • String A is 44 cm and string B is 58 cm.
  • The same length is cut from each.
  • What remains is in the ratio 2 to 3.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
5844=1458 - 44 = 14
Still 14 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 2 to 3, the gap is 1 part.
32=13 - 2 = 1
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
1 part come to 14 cm.
14÷1=1414 \div 1 = 14
Each part is 14 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 2 parts, so the rest of its 44 cm was cut off.
4414×2=1644 - 14 \times 2 = 16
16 cm was cut from each.
Answer: 16 cm
4 · Reviewdoes it hold up?

After cutting 16 cm the strings are 28 cm and 42 cm -- still 14 cm apart, and in the ratio 2 to 3.

Another way: Following string B instead gives 58 minus 16, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 9 hard answer: 1 cm

String A is 17 cm17\ \text{cm} long and string B is 65 cm65\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 1:41 : 4. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 17 cm and 65 cm, each lose the same length, and what is left is in the ratio 1 to 4. We want the length cut off.

Givens
  • String A is 17 cm and string B is 65 cm.
  • The same length is cut from each.
  • What remains is in the ratio 1 to 4.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
6517=4865 - 17 = 48
Still 48 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 1 to 4, the gap is 3 parts.
41=34 - 1 = 3
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
3 parts come to 48 cm.
48÷3=1648 \div 3 = 16
Each part is 16 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 1 part, so the rest of its 17 cm was cut off.
1716×1=117 - 16 \times 1 = 1
1 cm was cut from each.
Answer: 1 cm
4 · Reviewdoes it hold up?

After cutting 1 cm the strings are 16 cm and 64 cm -- still 48 cm apart, and in the ratio 1 to 4.

Another way: Following string B instead gives 65 minus 1, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 10 hard answer: 32 cm

String A is 46 cm46\ \text{cm} long and string B is 67 cm67\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 2:52 : 5. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 46 cm and 67 cm, each lose the same length, and what is left is in the ratio 2 to 5. We want the length cut off.

Givens
  • String A is 46 cm and string B is 67 cm.
  • The same length is cut from each.
  • What remains is in the ratio 2 to 5.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
6746=2167 - 46 = 21
Still 21 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 2 to 5, the gap is 3 parts.
52=35 - 2 = 3
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
3 parts come to 21 cm.
21÷3=721 \div 3 = 7
Each part is 7 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 2 parts, so the rest of its 46 cm was cut off.
467×2=3246 - 7 \times 2 = 32
32 cm was cut from each.
Answer: 32 cm
4 · Reviewdoes it hold up?

After cutting 32 cm the strings are 14 cm and 35 cm -- still 21 cm apart, and in the ratio 2 to 5.

Another way: Following string B instead gives 67 minus 32, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 11 hard answer: 61 cm

String A is 69 cm69\ \text{cm} long and string B is 75 cm75\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 4:74 : 7. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 69 cm and 75 cm, each lose the same length, and what is left is in the ratio 4 to 7. We want the length cut off.

Givens
  • String A is 69 cm and string B is 75 cm.
  • The same length is cut from each.
  • What remains is in the ratio 4 to 7.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
7569=675 - 69 = 6
Still 6 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 4 to 7, the gap is 3 parts.
74=37 - 4 = 3
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
3 parts come to 6 cm.
6÷3=26 \div 3 = 2
Each part is 2 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 4 parts, so the rest of its 69 cm was cut off.
692×4=6169 - 2 \times 4 = 61
61 cm was cut from each.
Answer: 61 cm
4 · Reviewdoes it hold up?

After cutting 61 cm the strings are 8 cm and 14 cm -- still 6 cm apart, and in the ratio 4 to 7.

Another way: Following string B instead gives 75 minus 61, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.
Variant 12 hard answer: 53 cm

String A is 61 cm61\ \text{cm} long and string B is 93 cm93\ \text{cm} long. The same length is cut from each, after which the lengths remaining are in the ratio 1:51 : 5. How many centimeters were cut from string A?

Show solution
1 · Understandwhat's really being asked

Two strings, 61 cm and 93 cm, each lose the same length, and what is left is in the ratio 1 to 5. We want the length cut off.

Givens
  • String A is 61 cm and string B is 93 cm.
  • The same length is cut from each.
  • What remains is in the ratio 1 to 5.
Unknowns
  • The length cut from each string.
Constraints
  • Both strings lose the same amount, so their difference is unchanged.
2 · Planchoose the strategy

#16 Count the Complement · also uses: #13 Convert to Algebra#10 Create a Physical Representation

Both lengths change, so neither can be followed directly. Their difference does not change, and the new ratio says how many parts that difference is -- which fixes the size of a part.

3 · Execute4 carry out the plan

1Notice what the cut leaves alone

#16 Count the Complement 6.EE.B.6
Taking the same amount off both keeps the gap between them the same.
9361=3293 - 61 = 32
Still 32 cm apart.

2Count the parts in that gap

#10 Create a Physical Representation 7.EE.B.4
With the remainders in the ratio 1 to 5, the gap is 4 parts.
51=45 - 1 = 4
The gap is measured in parts.

3Find one part

#13 Convert to Algebra 7.EE.B.4
4 parts come to 32 cm.
32÷4=832 \div 4 = 8
Each part is 8 cm.

4Work back to the cut

#13 Convert to Algebra 7.EE.B.4
String A keeps 1 part, so the rest of its 61 cm was cut off.
618×1=5361 - 8 \times 1 = 53
53 cm was cut from each.
Answer: 53 cm
4 · Reviewdoes it hold up?

After cutting 53 cm the strings are 8 cm and 40 cm -- still 32 cm apart, and in the ratio 1 to 5.

Another way: Following string B instead gives 93 minus 53, the same cut reached from the longer string.

Standardsmin grade 7
  • 7.EE.B.4 Use variables to represent quantities and construct simple equations and inequalities — Solving for the part size and then the cut.
  • 6.EE.B.6 Use variables to represent numbers and write expressions — Naming the cut as one unknown taken from both strings.
💡Takeaway. Take the same amount from two lengths and the gap between them never moves. Work with the gap.