← When both amounts are measured against a third, call that third 1 · Division as the Inverse of Multiplication

When both amounts are measured against a third, call that third 1 · 12 practice problems

6.NS.A.16.RP.A.3

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 316\frac{3}{16} times

My older brother's allowance is 2232\frac{2}{3} times mine, and my younger sibling's is 12\frac{1}{2} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 2 and 2/3 times my allowance and a sibling gets 1/2 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 2 and 2/3 times mine.
  • The sibling's allowance is 1/2 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=83,sibling=12\text{brother} = \frac{8}{3},\quad \text{sibling} = \frac{1}{2}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
12÷83\frac{1}{2} \div \frac{8}{3}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
12×38=316\frac{1}{2} \times \frac{3}{8} = \frac{3}{16}
The sibling gets 3/16 of the brother's.
Answer: 316\frac{3}{16} times
4 · Reviewdoes it hold up?

Checking the other way: 316×83=12\frac{3}{16} \times \frac{8}{3} = \frac{1}{2}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 6 won -- gives 16 and 3 won, whose quotient is the same 316\frac{3}{16}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 2 easy answer: 310\frac{3}{10} times

My older brother's allowance is 2122\frac{1}{2} times mine, and my younger sibling's is 34\frac{3}{4} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 2 and 1/2 times my allowance and a sibling gets 3/4 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 2 and 1/2 times mine.
  • The sibling's allowance is 3/4 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=52,sibling=34\text{brother} = \frac{5}{2},\quad \text{sibling} = \frac{3}{4}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
34÷52\frac{3}{4} \div \frac{5}{2}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
34×25=310\frac{3}{4} \times \frac{2}{5} = \frac{3}{10}
The sibling gets 3/10 of the brother's.
Answer: 310\frac{3}{10} times
4 · Reviewdoes it hold up?

Checking the other way: 310×52=34\frac{3}{10} \times \frac{5}{2} = \frac{3}{4}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 8 won -- gives 20 and 6 won, whose quotient is the same 310\frac{3}{10}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 3 easy answer: 310\frac{3}{10} times

My older brother's allowance is 1131\frac{1}{3} times mine, and my younger sibling's is 25\frac{2}{5} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 1 and 1/3 times my allowance and a sibling gets 2/5 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 1 and 1/3 times mine.
  • The sibling's allowance is 2/5 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=43,sibling=25\text{brother} = \frac{4}{3},\quad \text{sibling} = \frac{2}{5}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
25÷43\frac{2}{5} \div \frac{4}{3}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
25×34=310\frac{2}{5} \times \frac{3}{4} = \frac{3}{10}
The sibling gets 3/10 of the brother's.
Answer: 310\frac{3}{10} times
4 · Reviewdoes it hold up?

Checking the other way: 310×43=25\frac{3}{10} \times \frac{4}{3} = \frac{2}{5}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 15 won -- gives 20 and 6 won, whose quotient is the same 310\frac{3}{10}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 4 easy answer: 1033\frac{10}{33} times

My older brother's allowance is 2342\frac{3}{4} times mine, and my younger sibling's is 56\frac{5}{6} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 2 and 3/4 times my allowance and a sibling gets 5/6 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 2 and 3/4 times mine.
  • The sibling's allowance is 5/6 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=114,sibling=56\text{brother} = \frac{11}{4},\quad \text{sibling} = \frac{5}{6}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
56÷114\frac{5}{6} \div \frac{11}{4}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
56×411=1033\frac{5}{6} \times \frac{4}{11} = \frac{10}{33}
The sibling gets 10/33 of the brother's.
Answer: 1033\frac{10}{33} times
4 · Reviewdoes it hold up?

Checking the other way: 1033×114=56\frac{10}{33} \times \frac{11}{4} = \frac{5}{6}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 24 won -- gives 66 and 20 won, whose quotient is the same 1033\frac{10}{33}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 5 medium answer: 1277\frac{12}{77} times

My older brother's allowance is 1561\frac{5}{6} times mine, and my younger sibling's is 27\frac{2}{7} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 1 and 5/6 times my allowance and a sibling gets 2/7 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 1 and 5/6 times mine.
  • The sibling's allowance is 2/7 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=116,sibling=27\text{brother} = \frac{11}{6},\quad \text{sibling} = \frac{2}{7}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
27÷116\frac{2}{7} \div \frac{11}{6}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
27×611=1277\frac{2}{7} \times \frac{6}{11} = \frac{12}{77}
The sibling gets 12/77 of the brother's.
Answer: 1277\frac{12}{77} times
4 · Reviewdoes it hold up?

Checking the other way: 1277×116=27\frac{12}{77} \times \frac{11}{6} = \frac{2}{7}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 42 won -- gives 77 and 12 won, whose quotient is the same 1277\frac{12}{77}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 6 medium answer: 15136\frac{15}{136} times

My older brother's allowance is 3253\frac{2}{5} times mine, and my younger sibling's is 38\frac{3}{8} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 3 and 2/5 times my allowance and a sibling gets 3/8 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 3 and 2/5 times mine.
  • The sibling's allowance is 3/8 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=175,sibling=38\text{brother} = \frac{17}{5},\quad \text{sibling} = \frac{3}{8}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
38÷175\frac{3}{8} \div \frac{17}{5}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
38×517=15136\frac{3}{8} \times \frac{5}{17} = \frac{15}{136}
The sibling gets 15/136 of the brother's.
Answer: 15136\frac{15}{136} times
4 · Reviewdoes it hold up?

Checking the other way: 15136×175=38\frac{15}{136} \times \frac{17}{5} = \frac{3}{8}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 40 won -- gives 136 and 15 won, whose quotient is the same 15136\frac{15}{136}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 7 medium answer: 526\frac{5}{26} times

My older brother's allowance is 3143\frac{1}{4} times mine, and my younger sibling's is 58\frac{5}{8} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 3 and 1/4 times my allowance and a sibling gets 5/8 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 3 and 1/4 times mine.
  • The sibling's allowance is 5/8 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=134,sibling=58\text{brother} = \frac{13}{4},\quad \text{sibling} = \frac{5}{8}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
58÷134\frac{5}{8} \div \frac{13}{4}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
58×413=526\frac{5}{8} \times \frac{4}{13} = \frac{5}{26}
The sibling gets 5/26 of the brother's.
Answer: 526\frac{5}{26} times
4 · Reviewdoes it hold up?

Checking the other way: 526×134=58\frac{5}{26} \times \frac{13}{4} = \frac{5}{8}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 32 won -- gives 104 and 20 won, whose quotient is the same 526\frac{5}{26}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 8 hard answer: 827\frac{8}{27} times

My older brother's allowance is 1781\frac{7}{8} times mine, and my younger sibling's is 59\frac{5}{9} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 1 and 7/8 times my allowance and a sibling gets 5/9 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 1 and 7/8 times mine.
  • The sibling's allowance is 5/9 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=158,sibling=59\text{brother} = \frac{15}{8},\quad \text{sibling} = \frac{5}{9}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
59÷158\frac{5}{9} \div \frac{15}{8}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
59×815=827\frac{5}{9} \times \frac{8}{15} = \frac{8}{27}
The sibling gets 8/27 of the brother's.
Answer: 827\frac{8}{27} times
4 · Reviewdoes it hold up?

Checking the other way: 827×158=59\frac{8}{27} \times \frac{15}{8} = \frac{5}{9}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 72 won -- gives 135 and 40 won, whose quotient is the same 827\frac{8}{27}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 9 medium answer: 518\frac{5}{18} times

My older brother's allowance is 1351\frac{3}{5} times mine, and my younger sibling's is 49\frac{4}{9} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 1 and 3/5 times my allowance and a sibling gets 4/9 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 1 and 3/5 times mine.
  • The sibling's allowance is 4/9 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=85,sibling=49\text{brother} = \frac{8}{5},\quad \text{sibling} = \frac{4}{9}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
49÷85\frac{4}{9} \div \frac{8}{5}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
49×58=518\frac{4}{9} \times \frac{5}{8} = \frac{5}{18}
The sibling gets 5/18 of the brother's.
Answer: 518\frac{5}{18} times
4 · Reviewdoes it hold up?

Checking the other way: 518×85=49\frac{5}{18} \times \frac{8}{5} = \frac{4}{9}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 45 won -- gives 72 and 20 won, whose quotient is the same 518\frac{5}{18}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 10 hard answer: 745\frac{7}{45} times

My older brother's allowance is 4124\frac{1}{2} times mine, and my younger sibling's is 710\frac{7}{10} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 4 and 1/2 times my allowance and a sibling gets 7/10 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 4 and 1/2 times mine.
  • The sibling's allowance is 7/10 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=92,sibling=710\text{brother} = \frac{9}{2},\quad \text{sibling} = \frac{7}{10}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
710÷92\frac{7}{10} \div \frac{9}{2}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
710×29=745\frac{7}{10} \times \frac{2}{9} = \frac{7}{45}
The sibling gets 7/45 of the brother's.
Answer: 745\frac{7}{45} times
4 · Reviewdoes it hold up?

Checking the other way: 745×92=710\frac{7}{45} \times \frac{9}{2} = \frac{7}{10}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 20 won -- gives 90 and 14 won, whose quotient is the same 745\frac{7}{45}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 11 hard answer: 344\frac{3}{44} times

My older brother's allowance is 5135\frac{1}{3} times mine, and my younger sibling's is 411\frac{4}{11} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 5 and 1/3 times my allowance and a sibling gets 4/11 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 5 and 1/3 times mine.
  • The sibling's allowance is 4/11 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=163,sibling=411\text{brother} = \frac{16}{3},\quad \text{sibling} = \frac{4}{11}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
411÷163\frac{4}{11} \div \frac{16}{3}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
411×316=344\frac{4}{11} \times \frac{3}{16} = \frac{3}{44}
The sibling gets 3/44 of the brother's.
Answer: 344\frac{3}{44} times
4 · Reviewdoes it hold up?

Checking the other way: 344×163=411\frac{3}{44} \times \frac{16}{3} = \frac{4}{11}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 33 won -- gives 176 and 12 won, whose quotient is the same 344\frac{3}{44}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.
Variant 12 hard answer: 726\frac{7}{26} times

My older brother's allowance is 2162\frac{1}{6} times mine, and my younger sibling's is 712\frac{7}{12} of mine. My younger sibling's allowance is how many times my older brother's?

Show solution
1 · Understandwhat's really being asked

A brother gets 2 and 1/6 times my allowance and a sibling gets 7/12 of it. We want the sibling's as a multiple of the brother's.

Givens
  • The brother's allowance is 2 and 1/6 times mine.
  • The sibling's allowance is 7/12 of mine.
Unknowns
  • How many times the brother's allowance the sibling's is.
Constraints
  • My own allowance is never given.
2 · Planchoose the strategy

#9 Solve an Easier Related Problem · also uses: #8 Analyze the Units#7 Identify Subproblems

Both allowances are described against mine, so mine is the natural unit: call it 1 and the two become numbers. Then 'how many times' is a division, which undoes the multiplication that made them.

3 · Execute3 carry out the plan

1Call my allowance 1

#9 Solve an Easier Related Problem 6.RP.A.3
Everything is measured against it, so nothing is lost by naming it as the unit.
brother=136,sibling=712\text{brother} = \frac{13}{6},\quad \text{sibling} = \frac{7}{12}
Two plain fractions to compare.

2Read what the question asks

#8 Analyze the Units 6.NS.A.1
How many times the brother's the sibling's is means the sibling's divided by the brother's, not the other way round.
712÷136\frac{7}{12} \div \frac{13}{6}
Order matters here.

3Divide by multiplying by the reciprocal

#7 Identify Subproblems 6.NS.A.1
Flip the divisor and multiply.
712×613=726\frac{7}{12} \times \frac{6}{13} = \frac{7}{26}
The sibling gets 7/26 of the brother's.
Answer: 726\frac{7}{26} times
4 · Reviewdoes it hold up?

Checking the other way: 726×136=712\frac{7}{26} \times \frac{13}{6} = \frac{7}{12}, the sibling's share of mine. And the answer is less than 1, as it must be when the brother gets more than I do and the sibling less.

Another way: Picking a real allowance -- say 72 won -- gives 156 and 42 won, whose quotient is the same 726\frac{7}{26}. Any starting figure gives the same answer, which is why none is needed.

Standardsmin grade 6
  • 6.NS.A.1 Divide fractions by fractions — Dividing one fraction by another.
  • 6.RP.A.3 Use ratio and rate reasoning to solve problems — Reading 'times mine' and 'of mine' as measurements against one unit.
💡Takeaway. You do not need to know the amount if everything is measured against it. Call it 1 and carry on.