← Make result largest or smallest · Build the Largest or Smallest Value from Digit Cards

Make result largest or smallest · 12 practice problems

5.OA.A.15.OA.A.2

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 56

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

6×7+312÷36 \times 7 + 3 - 12 \div 3

Show solution
1 · Understandwhat's really being asked

The expression 6 times 7 plus 3 minus 12 divided by 3 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 6×7+312÷36 \times 7 + 3 - 12 \div 3.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 6 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
6×7+312÷3=416 \times 7 + 3 - 12 \div 3 = 41
41 is the baseline to beat.

2Notice 6 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 6 gets multiplied by 6, so adding to that group is worth 6 times as much as adding outside it.
6×()6 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $56
56 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e41,a×(b+cd)÷e4,a×b+(cd)÷e39,(a×b+cd)÷e11(a \times b + c) - d \div e \to 41,\quad a \times (b + c - d) \div e \to -4,\quad a \times b + (c - d) \div e \to 39,\quad (a \times b + c - d) \div e \to 11
The largest result is 56.
Answer: 56
4 · Reviewdoes it hold up?

The winner beats the unbracketed 41, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 2 easy answer: 67

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

4×13+510÷24 \times 13 + 5 - 10 \div 2

Show solution
1 · Understandwhat's really being asked

The expression 4 times 13 plus 5 minus 10 divided by 2 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 4×13+510÷24 \times 13 + 5 - 10 \div 2.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 4 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
4×13+510÷2=524 \times 13 + 5 - 10 \div 2 = 52
52 is the baseline to beat.

2Notice 4 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 4 gets multiplied by 4, so adding to that group is worth 4 times as much as adding outside it.
4×()4 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $67
67 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e52,a×(b+cd)÷e16(a \times b + c) - d \div e \to 52,\quad a \times (b + c - d) \div e \to 16
The largest result is 67.
Answer: 67
4 · Reviewdoes it hold up?

The winner beats the unbracketed 52, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 3 easy answer: 102

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

13×5+314÷713 \times 5 + 3 - 14 \div 7

Show solution
1 · Understandwhat's really being asked

The expression 13 times 5 plus 3 minus 14 divided by 7 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 13×5+314÷713 \times 5 + 3 - 14 \div 7.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 13 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
13×5+314÷7=6613 \times 5 + 3 - 14 \div 7 = 66
66 is the baseline to beat.

2Notice 13 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 13 gets multiplied by 13, so adding to that group is worth 13 times as much as adding outside it.
13×()13 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $102
102 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e66(a \times b + c) - d \div e \to 66
The largest result is 102.
Answer: 102
4 · Reviewdoes it hold up?

The winner beats the unbracketed 66, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 4 easy answer: 74

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

7×9+215÷57 \times 9 + 2 - 15 \div 5

Show solution
1 · Understandwhat's really being asked

The expression 7 times 9 plus 2 minus 15 divided by 5 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 7×9+215÷57 \times 9 + 2 - 15 \div 5.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 7 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
7×9+215÷5=627 \times 9 + 2 - 15 \div 5 = 62
62 is the baseline to beat.

2Notice 7 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 7 gets multiplied by 7, so adding to that group is worth 7 times as much as adding outside it.
7×()7 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $74
74 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e62,(a×b+cd)÷e10(a \times b + c) - d \div e \to 62,\quad (a \times b + c - d) \div e \to 10
The largest result is 74.
Answer: 74
4 · Reviewdoes it hold up?

The winner beats the unbracketed 62, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 5 medium answer: 126

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

10×8+516÷410 \times 8 + 5 - 16 \div 4

Show solution
1 · Understandwhat's really being asked

The expression 10 times 8 plus 5 minus 16 divided by 4 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 10×8+516÷410 \times 8 + 5 - 16 \div 4.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 10 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
10×8+516÷4=8110 \times 8 + 5 - 16 \div 4 = 81
81 is the baseline to beat.

2Notice 10 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 10 gets multiplied by 10, so adding to that group is worth 10 times as much as adding outside it.
10×()10 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $126
126 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e81(a \times b + c) - d \div e \to 81
The largest result is 126.
Answer: 126
4 · Reviewdoes it hold up?

The winner beats the unbracketed 81, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 6 medium answer: 101

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

8×6+718÷68 \times 6 + 7 - 18 \div 6

Show solution
1 · Understandwhat's really being asked

The expression 8 times 6 plus 7 minus 18 divided by 6 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 8×6+718÷68 \times 6 + 7 - 18 \div 6.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 8 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
8×6+718÷6=528 \times 6 + 7 - 18 \div 6 = 52
52 is the baseline to beat.

2Notice 8 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 8 gets multiplied by 8, so adding to that group is worth 8 times as much as adding outside it.
8×()8 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $101
101 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e52(a \times b + c) - d \div e \to 52
The largest result is 101.
Answer: 101
4 · Reviewdoes it hold up?

The winner beats the unbracketed 52, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 7 medium answer: 77

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

9×5+420÷59 \times 5 + 4 - 20 \div 5

Show solution
1 · Understandwhat's really being asked

The expression 9 times 5 plus 4 minus 20 divided by 5 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 9×5+420÷59 \times 5 + 4 - 20 \div 5.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 9 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
9×5+420÷5=459 \times 5 + 4 - 20 \div 5 = 45
45 is the baseline to beat.

2Notice 9 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 9 gets multiplied by 9, so adding to that group is worth 9 times as much as adding outside it.
9×()9 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $77
77 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e45(a \times b + c) - d \div e \to 45
The largest result is 77.
Answer: 77
4 · Reviewdoes it hold up?

The winner beats the unbracketed 45, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 8 medium answer: 82

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

5×11+621÷75 \times 11 + 6 - 21 \div 7

Show solution
1 · Understandwhat's really being asked

The expression 5 times 11 plus 6 minus 21 divided by 7 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 5×11+621÷75 \times 11 + 6 - 21 \div 7.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 5 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
5×11+621÷7=585 \times 11 + 6 - 21 \div 7 = 58
58 is the baseline to beat.

2Notice 5 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 5 gets multiplied by 5, so adding to that group is worth 5 times as much as adding outside it.
5×()5 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $82
82 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e58(a \times b + c) - d \div e \to 58
The largest result is 82.
Answer: 82
4 · Reviewdoes it hold up?

The winner beats the unbracketed 58, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 9 hard answer: 153

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

12×4+924÷812 \times 4 + 9 - 24 \div 8

Show solution
1 · Understandwhat's really being asked

The expression 12 times 4 plus 9 minus 24 divided by 8 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 12×4+924÷812 \times 4 + 9 - 24 \div 8.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 12 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
12×4+924÷8=5412 \times 4 + 9 - 24 \div 8 = 54
54 is the baseline to beat.

2Notice 12 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 12 gets multiplied by 12, so adding to that group is worth 12 times as much as adding outside it.
12×()12 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $153
153 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e54(a \times b + c) - d \div e \to 54
The largest result is 153.
Answer: 153
4 · Reviewdoes it hold up?

The winner beats the unbracketed 54, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 10 hard answer: 118

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

11×3+827÷911 \times 3 + 8 - 27 \div 9

Show solution
1 · Understandwhat's really being asked

The expression 11 times 3 plus 8 minus 27 divided by 9 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 11×3+827÷911 \times 3 + 8 - 27 \div 9.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 11 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
11×3+827÷9=3811 \times 3 + 8 - 27 \div 9 = 38
38 is the baseline to beat.

2Notice 11 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 11 gets multiplied by 11, so adding to that group is worth 11 times as much as adding outside it.
11×()11 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $118
118 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e38(a \times b + c) - d \div e \to 38
The largest result is 118.
Answer: 118
4 · Reviewdoes it hold up?

The winner beats the unbracketed 38, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 11 hard answer: 91

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

6×12+430÷66 \times 12 + 4 - 30 \div 6

Show solution
1 · Understandwhat's really being asked

The expression 6 times 12 plus 4 minus 30 divided by 6 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 6×12+430÷66 \times 12 + 4 - 30 \div 6.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 6 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
6×12+430÷6=716 \times 12 + 4 - 30 \div 6 = 71
71 is the baseline to beat.

2Notice 6 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 6 gets multiplied by 6, so adding to that group is worth 6 times as much as adding outside it.
6×()6 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $91
91 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e71,a×(b+cd)÷e14(a \times b + c) - d \div e \to 71,\quad a \times (b + c - d) \div e \to -14
The largest result is 91.
Answer: 91
4 · Reviewdoes it hold up?

The winner beats the unbracketed 71, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.
Variant 12 hard answer: 113

Insert one pair of parentheses ( ) into the expression below so that the result is as large as possible, then find that largest result. (The result must be a whole number.)

9×7+632÷89 \times 7 + 6 - 32 \div 8

Show solution
1 · Understandwhat's really being asked

The expression 9 times 7 plus 6 minus 32 divided by 8 is given. One pair of brackets may go anywhere. We want the placement that makes the value largest, with a whole-number result.

Givens
  • The expression is 9×7+632÷89 \times 7 + 6 - 32 \div 8.
  • Exactly one pair of parentheses may be inserted.
  • The result must be a whole number.
Unknowns
  • The largest result obtainable.
Constraints
  • Parentheses may only group a run of the expression as written; the numbers cannot be reordered.
2 · Planchoose the strategy

#6 Guess and Check · also uses: #2 Make a Systematic List#5 Look for a Pattern

There are only a handful of places brackets can go, so they can all be tried. But thinking first narrows it: 9 multiplies whatever follows it, so brackets that make that partner bigger have the most leverage.

3 · Execute4 carry out the plan

1See what happens with no parentheses

#5 Look for a Pattern 5.OA.A.1
Ordinary order of operations: the multiplication and division first, then the addition and subtraction.
9×7+632÷8=659 \times 7 + 6 - 32 \div 8 = 65
65 is the baseline to beat.

2Notice 9 is a multiplier -- grow what it multiplies

#5 Look for a Pattern 5.OA.A.2
Everything inside brackets right after 9 gets multiplied by 9, so adding to that group is worth 9 times as much as adding outside it.
9×()9 \times (\ldots)
Leverage sits with the multiplier.

3Finish that candidate placement

#6 Guess and Check 5.OA.A.1
Working out the most promising bracketing gives its value.
a \times (b + c) - d \div e$ gives $113
113 is the candidate to beat.

4Check the other reasonable placements

#2 Make a Systematic List 5.OA.A.1
Each remaining bracketing that still leaves a whole number comes out smaller.
(a×b+c)d÷e65(a \times b + c) - d \div e \to 65
The largest result is 113.
Answer: 113
4 · Reviewdoes it hold up?

The winner beats the unbracketed 65, which it must if the brackets did anything useful.

Another way: Evaluating every placement without thinking first gives the same answer; the multiplier argument just says which one to try first.

Standardsmin grade 5
  • 5.OA.A.1 Use parentheses, brackets, or braces in numerical expressions, and evaluate expressions with these symbols. — Evaluating each bracketed version in the right order.
  • 5.OA.A.2 Write simple expressions that record calculations with numbers, and interpret numerical expressions without evaluating them. — Reading which grouping the multiplier amplifies, before computing.
💡Takeaway. Brackets next to a multiplier are worth the most -- whatever you put inside gets multiplied along with everything else.