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Identify tiling pieces and total area · 3 practice problems

4.MD.A.34.OA.A.3

From the workbook (authentic) — 3

Real practice problems extracted and localized from the source 디딤돌 최상위 S workbook.

Workbook 1 answer: about 32

Four kinds of pattern-block pieces were each used several times to build the dog shape on the right: piece R is a rhombus, piece T is a trapezoid, piece H is a hexagon, and piece S is a square. The unit triangle has size $1$ , so a rhombus R has size $2$ , a trapezoid T has size $3$ , and a hexagon H has size $6$ . The square piece S has size about $2$ . About what is the size of the whole dog shape on the right?

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Understand

A dog shape is built from four kinds of pattern blocks measured against a unit triangle of size 1: rhombus R (size 2), trapezoid T (size 3), hexagon H (size 6), and square S (size about 2). The dog uses 2 rhombi, 2 trapezoids, 3 hexagons, and 2 squares. I need the total size of the whole dog shape.

Givens

The unit triangle has size 1.
Rhombus R has size 2; trapezoid T has size 3; hexagon H has size 6; square S has size about 2.
The dog uses 2 rhombi R (ears), 2 trapezoids T (middle of body), 3 hexagons H (head and two body sections), and 2 squares S (legs).

Unknowns

The total size of the whole dog shape.

Constraints

The whole shape is made only of these four piece types.
Total size = sum over piece types of (count) x (size).

Plan

#7 Identify Subproblems · also uses: #2 Make a Systematic List#1 Draw a Diagram

Break the dog into its four piece types, count each type, multiply each count by that piece's size, then add the four subtotals for the whole size.

Execute

#2 Make a Systematic List 4.MD.A.3

There are 2 rhombus pieces, each of size 2, so the rhombi cover 2 x 2 = 4.

2 \times 2 = 4

Two size-2 pieces add to 4 by multiplying count times size.

#2 Make a Systematic List 4.MD.A.3

There are 2 trapezoid pieces, each of size 3, so the trapezoids cover 3 x 2 = 6.

3 \times 2 = 6

Two size-3 pieces add to 6.

#2 Make a Systematic List 4.MD.A.3

There are 3 hexagon pieces, each of size 6, so the hexagons cover 6 x 3 = 18.

6 \times 3 = 18

Three size-6 pieces add to 18 by repeated addition of 6.

#2 Make a Systematic List 4.MD.A.3

There are 2 square pieces, each of size about 2, so the squares cover about 2 x 2 = 4.

2 \times 2 = 4

Two size-2 pieces add to 4.

#7 Identify Subproblems 4.OA.A.3

The whole size is 4 + 6 + 18 + 4 = 32.

4 + 6 + 18 + 4 = 32

Combining the four piece-type totals gives the full dog's size.

Answer: about 32

Review

The three hexagons alone give 18, the biggest chunk, and the smaller pieces (4 + 6 + 4 = 14) bring the total to 32; that is sensible since hexagons are the largest pieces and there are three of them.

Triangle-unit view (tool 8/15): convert every piece to unit triangles -- 2 rhombi = 4, 2 trapezoids = 6, 3 hexagons = 18, 2 squares = 4 -- and count 32 unit triangles in all, the same answer.

Standards · min grade 4

4.MD.A.3 Apply the area and perimeter formulas for rectangles in real world and mathematical problems — Finding each piece-type's subtotal by multiplying its count by its size.
4.OA.A.3 Solve multistep word problems posed with whole numbers and having whole-number answers using the four operations — Adding the four piece-type subtotals into the whole dog's size.

💡 Multiply each block by its size and add: 4 + 6 + 18 + 4 = about 32 -- just counting and grouping!

Workbook 2 answer: 6

A single pattern-block piece was used several times to build the shape on the right. The piece is a rhombus (the blue pattern-block rhombus). If this rhombus piece has size $1$ , what is the size of the whole shape on the right?

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Understand

One rhombus pattern-block piece of size 1 is used over and over to build a figure-eight shape: two equal regular hexagons joined at a single pinch point. Each hexagon is made of 3 of these rhombi. I need the total size of the whole figure-eight shape.

Givens

The piece is a rhombus with size 1.
The shape is two equal regular hexagons joined at one pinch point.
Each hexagon is tiled by 3 of the rhombus pieces.

Unknowns

The total size of the whole figure-eight shape.

Constraints

The whole shape is made only of the rhombus pieces.
Total size = (number of rhombi) x (size of one rhombus).

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#2 Make a Systematic List

Split the figure-eight into its two hexagons, find how many rhombi tile one hexagon, double it to count all the rhombi, then multiply the count by the size of one rhombus.

Execute

#1 Draw a Diagram 4.G.A.2

A regular hexagon is tiled by exactly 3 of the rhombus pieces, as shown by the lines inside each hexagon.

3 \text{ rhombi per hexagon}

Three congruent rhombi meeting at the center fill a regular hexagon -- a standard pattern-block fact you can see in the figure.

#2 Make a Systematic List 4.OA.A.3

There are two hexagons, and they only touch at a single point, so no rhombi are shared. The total number of rhombi is 3 + 3 = 6.

3 \times 2 = 6

Two separate hexagons of 3 rhombi each give 6 rhombi by simple doubling.

#7 Identify Subproblems 4.MD.A.3

Each of the 6 rhombi has size 1, so the whole shape has size 6 x 1 = 6.

6 \times 1 = 6

Multiplying the count of equal pieces by each piece's size gives the total size.

Answer: 6

Review

The shape is two hexagons and each hexagon is 3 rhombi, so 6 rhombi of size 1 must total 6. The pinch point is a single shared point (zero area), so nothing is double-counted -- 6 is consistent.

Pattern view (tool 5): each hexagon repeats the same 3-rhombus pattern, so the size grows by 3 per hexagon; with 2 hexagons the size is 3, 6 -- ending at 6.

Standards · min grade 4

4.G.A.2 Classify two-dimensional figures based on the presence or absence of parallel or perpendicular lines, or the presence or absence of angles of a specified size — Recognizing that a regular hexagon is composed of 3 congruent rhombi.
4.OA.A.3 Solve multistep word problems posed with whole numbers and having whole-number answers using the four operations — Combining the rhombi from both hexagons into one count.
4.MD.A.3 Apply the area and perimeter formulas for rectangles in real world and mathematical problems — Multiplying the rhombus count by each rhombus's size to get the total size.

💡 Each hexagon is just 3 rhombi, so two hexagons are 6 rhombi -- count and multiply, and the size is 6!

Workbook 3 answer: about 16

Two pattern-block pieces, piece A and piece B, were each used several times to build the shape on the right. Piece A is an equilateral triangle and piece B is a square. If piece A has size $1$ and piece B has size about $2$ , about what is the size of the whole shape on the right?

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Understand

A tall star-topped shape is built from two kinds of pattern blocks: triangle piece A of size 1, and square piece B of size about 2. The shape uses 12 of the triangle pieces and 2 of the square pieces. I need the total size of the whole shape.

Givens

Piece A is a triangle with size 1.
Piece B is a square with size about 2.
The shape is built from 12 triangle pieces A and 2 square pieces B.

Unknowns

The total size of the whole shape.

Constraints

The whole shape is made only of triangle and square pieces.
Total size = (count of A) x (size of A) + (count of B) x (size of B).

Plan

#7 Identify Subproblems · also uses: #2 Make a Systematic List#8 Analyze the Units

Separate the shape into its triangle part and its square part, count each kind of piece, multiply each count by that piece's size, and add the two totals.

Execute

#2 Make a Systematic List 4.MD.A.3

The star and bowtie parts are made of 12 triangle pieces A, each of size 1, so the triangles cover 12 x 1 = 12.

1 \times 12 = 12

Twelve equal size-1 pieces add to 12 by counting.

#2 Make a Systematic List 4.MD.A.3

Two square pieces B sit at the base, each of size about 2, so the squares cover about 2 x 2 = 4.

2 \times 2 = 4

Two pieces of size 2 each add to 4 by multiplying a count by a size.

#7 Identify Subproblems 4.OA.A.3

The whole size is the triangle total plus the square total: 12 + 4 = 16.

12 + 4 = 16

Combining the triangle area and the square area gives the full shape's size.

Answer: about 16

Review

The triangles give 12 and the two size-2 squares add only 4 more, so a total near 16 makes sense; the triangle part dominates because there are many more triangles.

Units view (tool 8): measure everything in triangle-units -- each square is worth 2 triangles, so the 2 squares are 4 triangle-units; with 12 triangle-units already, the total is 16 triangle-units.

Standards · min grade 4

4.MD.A.3 Apply the area and perimeter formulas for rectangles in real world and mathematical problems — Finding each piece-type's total by multiplying its count by its size.
4.OA.A.3 Solve multistep word problems posed with whole numbers and having whole-number answers using the four operations — Adding the triangle total and the square total into the whole shape's size.

💡 Twelve size-1 triangles make 12, plus two size-2 squares make 4 -- add them for about 16!