Estimate an unmeasured midpoint value on a line graph
5.MD.B.2
Generated variants — 8
The line graph shows the plant height recorded in a town. Estimate the value at about week 3.5, in .
The graph is titled "Plant Height." The horizontal axis shows the week (1, 2, 3, 4, 5), and the vertical axis shows the value in . The vertical axis is labeled 5, 10, 15; since 5 grid squares represent 5, each grid square represents . The recorded values are: 1 , 2 , 3 , 4 , 5 . The value at week 3.5 was not recorded, so estimate it as the midpoint of the values at week 3 and week 4.
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A line graph of plant height shows 1 = 4, 2 = 8, 3 = 12, 4 = 20, 5 = 18 cm (each square = 1 cm). week 3.5 was not measured; I estimate it as the midpoint of the week 3 and week 4 readings.
- 1 = 4 cm, 2 = 8 cm, 3 = 12 cm, 4 = 20 cm, 5 = 18 cm
- Each small grid square = 1 cm
- week 3.5 is exactly halfway between week 3 and week 4
- Estimate week 3.5 as the midpoint of the week 3 and week 4 values
- The estimated value at about week 3.5 in cm
- week 3.5 lies between the two measured times, so its value should sit between 12 and 20
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. week 3.5 is the halfway time between week 3 and week 4, so I take the midpoint of 12 and 20.
Execute
Review
16 lies between 12 (week 3) and 20 (week 4), as it must for a time in between, and it is exactly in the middle, which fits week 3.5 being the middle time.
Use the rise (tool 8 / units): from week 3 to week 4 the value changed by 8, so half of that interval adds 8/2 to 12, giving 12 + 4 = 16 cm.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point
The line graph shows the cafe customers recorded in a town. Estimate the value at about 10:30 a.m., in .
The graph is titled "Cafe Customers." The horizontal axis shows the hour (8, 9, 10, 11, 12), and the vertical axis shows the value in . The vertical axis is labeled 10, 20, 30; since 5 grid squares represent 10, each grid square represents . The recorded values are: 8 , 9 , 10 , 11 , 12 . The value at 10:30 a.m. was not recorded, so estimate it as the midpoint of the values at 10 a.m. and 11 a.m..
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A line graph of cafe customers shows 8 = 12, 9 = 18, 10 = 24, 11 = 36, 12 = 30 people (each square = 2 people). 10:30 a.m. was not measured; I estimate it as the midpoint of the 10 a.m. and 11 a.m. readings.
- 8 = 12 people, 9 = 18 people, 10 = 24 people, 11 = 36 people, 12 = 30 people
- Each small grid square = 2 people
- 10:30 a.m. is exactly halfway between 10 a.m. and 11 a.m.
- Estimate 10:30 a.m. as the midpoint of the 10 a.m. and 11 a.m. values
- The estimated value at about 10:30 a.m. in people
- 10:30 a.m. lies between the two measured times, so its value should sit between 24 and 36
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. 10:30 a.m. is the halfway time between 10 a.m. and 11 a.m., so I take the midpoint of 24 and 36.
Execute
Review
30 lies between 24 (10 a.m.) and 36 (11 a.m.), as it must for a time in between, and it is exactly in the middle, which fits 10:30 a.m. being the middle time.
Use the rise (tool 8 / units): from 10 a.m. to 11 a.m. the value changed by 12, so half of that interval adds 12/2 to 24, giving 24 + 6 = 30 people.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point
The line graph shows the town temperature recorded in a town. Estimate the value at about 1:00 p.m., in .
The graph is titled "Town Temperature." The horizontal axis shows the time (8, 10, 12, 2, 4), and the vertical axis shows the value in . The vertical axis is labeled 5, 10, 15; since 5 grid squares represent 5, each grid square represents . The recorded values are: 8 , 10 , 12 , 2 , 4 . The value at 1:00 p.m. was not recorded, so estimate it as the midpoint of the values at 12 noon and 2 p.m..
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A line graph of town temperature shows 8 = 6, 10 = 8, 12 = 11, 2 = 15, 4 = 12 degrees C (each square = 1 degrees C). 1:00 p.m. was not measured; I estimate it as the midpoint of the 12 noon and 2 p.m. readings.
- 8 = 6 degrees C, 10 = 8 degrees C, 12 = 11 degrees C, 2 = 15 degrees C, 4 = 12 degrees C
- Each small grid square = 1 degrees C
- 1:00 p.m. is exactly halfway between 12 noon and 2 p.m.
- Estimate 1:00 p.m. as the midpoint of the 12 noon and 2 p.m. values
- The estimated value at about 1:00 p.m. in degrees C
- 1:00 p.m. lies between the two measured times, so its value should sit between 11 and 15
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. 1:00 p.m. is the halfway time between 12 noon and 2 p.m., so I take the midpoint of 11 and 15.
Execute
Review
13 lies between 11 (12 noon) and 15 (2 p.m.), as it must for a time in between, and it is exactly in the middle, which fits 1:00 p.m. being the middle time.
Use the rise (tool 8 / units): from 12 noon to 2 p.m. the value changed by 4, so half of that interval adds 4/2 to 11, giving 11 + 2 = 13 degrees C.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point
The line graph shows the library visitors recorded in a town. Estimate the value at about hour 3.5, in .
The graph is titled "Library Visitors." The horizontal axis shows the hour (1, 2, 3, 4, 5), and the vertical axis shows the value in . The vertical axis is labeled 10, 20, 30; since 5 grid squares represent 10, each grid square represents . The recorded values are: 1 , 2 , 3 , 4 , 5 . The value at hour 3.5 was not recorded, so estimate it as the midpoint of the values at hour 3 and hour 4.
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A line graph of library visitors shows 1 = 10, 2 = 16, 3 = 20, 4 = 30, 5 = 24 people (each square = 2 people). hour 3.5 was not measured; I estimate it as the midpoint of the hour 3 and hour 4 readings.
- 1 = 10 people, 2 = 16 people, 3 = 20 people, 4 = 30 people, 5 = 24 people
- Each small grid square = 2 people
- hour 3.5 is exactly halfway between hour 3 and hour 4
- Estimate hour 3.5 as the midpoint of the hour 3 and hour 4 values
- The estimated value at about hour 3.5 in people
- hour 3.5 lies between the two measured times, so its value should sit between 20 and 30
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. hour 3.5 is the halfway time between hour 3 and hour 4, so I take the midpoint of 20 and 30.
Execute
Review
25 lies between 20 (hour 3) and 30 (hour 4), as it must for a time in between, and it is exactly in the middle, which fits hour 3.5 being the middle time.
Use the rise (tool 8 / units): from hour 3 to hour 4 the value changed by 10, so half of that interval adds 10/2 to 20, giving 20 + 5 = 25 people.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point
The line graph shows the garden temperature recorded in a town. Estimate the value at about 11 a.m., in .
The graph is titled "Garden Temperature." The horizontal axis shows the time (6, 8, 10, 12, 2), and the vertical axis shows the value in . The vertical axis is labeled 5, 10, 15; since 5 grid squares represent 5, each grid square represents . The recorded values are: 6 , 8 , 10 , 12 , 2 . The value at 11 a.m. was not recorded, so estimate it as the midpoint of the values at 10 a.m. and 12 noon.
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A line graph of garden temperature shows 6 = 4, 8 = 7, 10 = 10, 12 = 16, 2 = 14 degrees C (each square = 1 degrees C). 11 a.m. was not measured; I estimate it as the midpoint of the 10 a.m. and 12 noon readings.
- 6 = 4 degrees C, 8 = 7 degrees C, 10 = 10 degrees C, 12 = 16 degrees C, 2 = 14 degrees C
- Each small grid square = 1 degrees C
- 11 a.m. is exactly halfway between 10 a.m. and 12 noon
- Estimate 11 a.m. as the midpoint of the 10 a.m. and 12 noon values
- The estimated value at about 11 a.m. in degrees C
- 11 a.m. lies between the two measured times, so its value should sit between 10 and 16
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. 11 a.m. is the halfway time between 10 a.m. and 12 noon, so I take the midpoint of 10 and 16.
Execute
Review
13 lies between 10 (10 a.m.) and 16 (12 noon), as it must for a time in between, and it is exactly in the middle, which fits 11 a.m. being the middle time.
Use the rise (tool 8 / units): from 10 a.m. to 12 noon the value changed by 6, so half of that interval adds 6/2 to 10, giving 10 + 3 = 13 degrees C.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point
The line graph shows the snow depth recorded in a town. Estimate the value at about day 3.5, in .
The graph is titled "Snow Depth." The horizontal axis shows the day (1, 2, 3, 4, 5), and the vertical axis shows the value in . The vertical axis is labeled 5, 10, 15; since 5 grid squares represent 5, each grid square represents . The recorded values are: 1 , 2 , 3 , 4 , 5 . The value at day 3.5 was not recorded, so estimate it as the midpoint of the values at day 3 and day 4.
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A line graph of snow depth shows 1 = 6, 2 = 10, 3 = 14, 4 = 22, 5 = 18 cm (each square = 1 cm). day 3.5 was not measured; I estimate it as the midpoint of the day 3 and day 4 readings.
- 1 = 6 cm, 2 = 10 cm, 3 = 14 cm, 4 = 22 cm, 5 = 18 cm
- Each small grid square = 1 cm
- day 3.5 is exactly halfway between day 3 and day 4
- Estimate day 3.5 as the midpoint of the day 3 and day 4 values
- The estimated value at about day 3.5 in cm
- day 3.5 lies between the two measured times, so its value should sit between 14 and 22
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. day 3.5 is the halfway time between day 3 and day 4, so I take the midpoint of 14 and 22.
Execute
Review
18 lies between 14 (day 3) and 22 (day 4), as it must for a time in between, and it is exactly in the middle, which fits day 3.5 being the middle time.
Use the rise (tool 8 / units): from day 3 to day 4 the value changed by 8, so half of that interval adds 8/2 to 14, giving 14 + 4 = 18 cm.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point
The line graph shows the pool temperature recorded in a town. Estimate the value at about 11:30 a.m., in .
The graph is titled "Pool Temperature." The horizontal axis shows the time (9, 10, 11, 12, 1), and the vertical axis shows the value in . The vertical axis is labeled 15, 20, 25; since 5 grid squares represent 5, each grid square represents . The recorded values are: 9 , 10 , 11 , 12 , 1 . The value at 11:30 a.m. was not recorded, so estimate it as the midpoint of the values at 11 a.m. and 12 noon.
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A line graph of pool temperature shows 9 = 18, 10 = 20, 11 = 22, 12 = 26, 1 = 28 degrees C (each square = 1 degrees C). 11:30 a.m. was not measured; I estimate it as the midpoint of the 11 a.m. and 12 noon readings.
- 9 = 18 degrees C, 10 = 20 degrees C, 11 = 22 degrees C, 12 = 26 degrees C, 1 = 28 degrees C
- Each small grid square = 1 degrees C
- 11:30 a.m. is exactly halfway between 11 a.m. and 12 noon
- Estimate 11:30 a.m. as the midpoint of the 11 a.m. and 12 noon values
- The estimated value at about 11:30 a.m. in degrees C
- 11:30 a.m. lies between the two measured times, so its value should sit between 22 and 26
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. 11:30 a.m. is the halfway time between 11 a.m. and 12 noon, so I take the midpoint of 22 and 26.
Execute
Review
24 lies between 22 (11 a.m.) and 26 (12 noon), as it must for a time in between, and it is exactly in the middle, which fits 11:30 a.m. being the middle time.
Use the rise (tool 8 / units): from 11 a.m. to 12 noon the value changed by 4, so half of that interval adds 4/2 to 22, giving 22 + 2 = 24 degrees C.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point
The line graph shows the road temperature recorded in a town. Estimate the value at about 12 noon, in .
The graph is titled "Road Temperature." The horizontal axis shows the time (7, 9, 11, 1, 3), and the vertical axis shows the value in . The vertical axis is labeled 5, 10, 15; since 5 grid squares represent 5, each grid square represents . The recorded values are: 7 , 9 , 11 , 1 , 3 . The value at 12 noon was not recorded, so estimate it as the midpoint of the values at 11 a.m. and 1 p.m..
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A line graph of road temperature shows 7 = 3, 9 = 6, 11 = 9, 1 = 17, 3 = 14 degrees C (each square = 1 degrees C). 12 noon was not measured; I estimate it as the midpoint of the 11 a.m. and 1 p.m. readings.
- 7 = 3 degrees C, 9 = 6 degrees C, 11 = 9 degrees C, 1 = 17 degrees C, 3 = 14 degrees C
- Each small grid square = 1 degrees C
- 12 noon is exactly halfway between 11 a.m. and 1 p.m.
- Estimate 12 noon as the midpoint of the 11 a.m. and 1 p.m. values
- The estimated value at about 12 noon in degrees C
- 12 noon lies between the two measured times, so its value should sit between 9 and 17
Plan
#5 Look for a Pattern · also uses: #1 Draw a Diagram
On a line graph the segment between two points rises steadily, so the value halfway across is the average of the two endpoints. 12 noon is the halfway time between 11 a.m. and 1 p.m., so I take the midpoint of 9 and 17.
Execute
Review
13 lies between 9 (11 a.m.) and 17 (1 p.m.), as it must for a time in between, and it is exactly in the middle, which fits 12 noon being the middle time.
Use the rise (tool 8 / units): from 11 a.m. to 1 p.m. the value changed by 8, so half of that interval adds 8/2 to 9, giving 9 + 4 = 13 degrees C.
Standards · min grade 5
5.MD.B.2Make a line plot to display a data set and solve problems using the data — Reading the two endpoint values and estimating the in-between point