Sensim Math · Depth 한국어

← 4-2 · Perimeter as decimal side sums minus overlaps · Perimeter by Tracing Every Side

Perimeter as decimal side sums minus overlaps · 10 practice problems

5.NBT.B.74.MD.A.3

Generated variants — 10

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 answer: 2 m

Using a 3.5 m3.5\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 0.5 m0.5\ \text{m}.)

0.5 m
Show solution

Understand

A 3.5 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 0.5 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 3.5 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 0.5 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 0.5 m, so the wire used is the sum of the three sides.
0.5+0.5+0.5=0.5×3=1.5 m0.5 + 0.5 + 0.5 = 0.5 \times 3 = 1.5 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
3.51.5=2 m3.5 - 1.5 = 2 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 2 m

Review

The triangle uses 1.5 m out of the 3.5 m wire. Check: 1.5 + 2 = 3.5 m, exactly the original wire, so 2 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 2 answer: 2.26 m

Using a 4 m4\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 0.58 m0.58\ \text{m}.)

0.58 m
Show solution

Understand

A 4 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 0.58 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 4 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 0.58 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 0.58 m, so the wire used is the sum of the three sides.
0.58+0.58+0.58=0.58×3=1.74 m0.58 + 0.58 + 0.58 = 0.58 \times 3 = 1.74 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
41.74=2.26 m4 - 1.74 = 2.26 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 2.26 m

Review

The triangle uses 1.74 m out of the 4 m wire. Check: 1.74 + 2.26 = 4 m, exactly the original wire, so 2.26 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 3 answer: 5.5 m

Using a 10 m10\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 1.5 m1.5\ \text{m}.)

1.5 m
Show solution

Understand

A 10 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 1.5 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 10 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 1.5 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 1.5 m, so the wire used is the sum of the three sides.
1.5+1.5+1.5=1.5×3=4.5 m1.5 + 1.5 + 1.5 = 1.5 \times 3 = 4.5 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
104.5=5.5 m10 - 4.5 = 5.5 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 5.5 m

Review

The triangle uses 4.5 m out of the 10 m wire. Check: 4.5 + 5.5 = 10 m, exactly the original wire, so 5.5 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 4 answer: 1.65 m

Using a 3 m3\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 0.45 m0.45\ \text{m}.)

0.45 m
Show solution

Understand

A 3 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 0.45 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 3 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 0.45 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 0.45 m, so the wire used is the sum of the three sides.
0.45+0.45+0.45=0.45×3=1.35 m0.45 + 0.45 + 0.45 = 0.45 \times 3 = 1.35 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
31.35=1.65 m3 - 1.35 = 1.65 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 1.65 m

Review

The triangle uses 1.35 m out of the 3 m wire. Check: 1.35 + 1.65 = 3 m, exactly the original wire, so 1.65 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 5 answer: 4.25 m

Using a 8 m8\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 1.25 m1.25\ \text{m}.)

1.25 m
Show solution

Understand

A 8 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 1.25 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 8 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 1.25 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 1.25 m, so the wire used is the sum of the three sides.
1.25+1.25+1.25=1.25×3=3.75 m1.25 + 1.25 + 1.25 = 1.25 \times 3 = 3.75 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
83.75=4.25 m8 - 3.75 = 4.25 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 4.25 m

Review

The triangle uses 3.75 m out of the 8 m wire. Check: 3.75 + 4.25 = 8 m, exactly the original wire, so 4.25 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 6 answer: 2.7 m

Using a 4.5 m4.5\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 0.6 m0.6\ \text{m}.)

0.6 m
Show solution

Understand

A 4.5 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 0.6 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 4.5 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 0.6 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 0.6 m, so the wire used is the sum of the three sides.
0.6+0.6+0.6=0.6×3=1.8 m0.6 + 0.6 + 0.6 = 0.6 \times 3 = 1.8 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
4.51.8=2.7 m4.5 - 1.8 = 2.7 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 2.7 m

Review

The triangle uses 1.8 m out of the 4.5 m wire. Check: 1.8 + 2.7 = 4.5 m, exactly the original wire, so 2.7 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 7 answer: 1.6 m

Using a 4 m4\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 0.8 m0.8\ \text{m}.)

0.8 m
Show solution

Understand

A 4 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 0.8 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 4 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 0.8 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 0.8 m, so the wire used is the sum of the three sides.
0.8+0.8+0.8=0.8×3=2.4 m0.8 + 0.8 + 0.8 = 0.8 \times 3 = 2.4 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
42.4=1.6 m4 - 2.4 = 1.6 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 1.6 m

Review

The triangle uses 2.4 m out of the 4 m wire. Check: 2.4 + 1.6 = 4 m, exactly the original wire, so 1.6 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 8 answer: 2.84 m

Using a 5 m5\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 0.72 m0.72\ \text{m}.)

0.72 m
Show solution

Understand

A 5 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 0.72 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 5 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 0.72 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 0.72 m, so the wire used is the sum of the three sides.
0.72+0.72+0.72=0.72×3=2.16 m0.72 + 0.72 + 0.72 = 0.72 \times 3 = 2.16 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
52.16=2.84 m5 - 2.16 = 2.84 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 2.84 m

Review

The triangle uses 2.16 m out of the 5 m wire. Check: 2.16 + 2.84 = 5 m, exactly the original wire, so 2.84 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 9 answer: 3.3 m

Using a 6 m6\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 0.9 m0.9\ \text{m}.)

0.9 m
Show solution

Understand

A 6 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 0.9 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 6 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 0.9 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 0.9 m, so the wire used is the sum of the three sides.
0.9+0.9+0.9=0.9×3=2.7 m0.9 + 0.9 + 0.9 = 0.9 \times 3 = 2.7 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
62.7=3.3 m6 - 2.7 = 3.3 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 3.3 m

Review

The triangle uses 2.7 m out of the 6 m wire. Check: 2.7 + 3.3 = 6 m, exactly the original wire, so 3.3 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!
Variant 10 answer: 3.7 m

Using a 7 m7\ \text{m} length of wire without overlapping, you bent it to make one equilateral triangle like the one shown. How many meters of wire are left over?

(Figure: one equilateral triangle, with one side labeled 1.1 m1.1\ \text{m}.)

1.1 m
Show solution

Understand

A 7 m piece of wire is bent (no overlap) into one equilateral triangle whose side is 1.1 m. I need to find how much wire is left over after making the triangle.

Givens
  • Total wire length is 7 m.
  • The shape made is an equilateral triangle (all three sides equal).
  • Each side of the triangle is 1.1 m.
  • No wire overlaps when bending.
Unknowns
  • The length of wire left over, in meters.
Constraints
  • An equilateral triangle has exactly 3 equal sides.
  • Wire used equals the triangle's perimeter; leftover = total - perimeter.

Plan

#7 Identify Subproblems · also uses: #1 Draw a Diagram#8 Analyze the Units

Break the task into two small steps: first the perimeter (a side-length sum for an equilateral triangle), then a subtraction from the total wire. The figure shows one labeled side, and all sides are equal, so the perimeter is 3 copies of the side. Keeping the meters consistent guards against place-value slips with decimals.

Execute

#7 Identify Subproblems 5.NBT.B.7
An equilateral triangle has three equal sides of 1.1 m, so the wire used is the sum of the three sides.
1.1+1.1+1.1=1.1×3=3.3 m1.1 + 1.1 + 1.1 = 1.1 \times 3 = 3.3 \text{ m}
Adding three equal decimals is the same as multiplying by 3; lining up the hundredths keeps the place values straight.
#7 Identify Subproblems 5.NBT.B.7
The leftover wire is the total length minus the wire used for the triangle.
73.3=3.7 m7 - 3.3 = 3.7 \text{ m}
Subtract the used wire from the total, regrouping the decimals just like money amounts.
Answer: 3.7 m

Review

The triangle uses 3.3 m out of the 7 m wire. Check: 3.3 + 3.7 = 7 m, exactly the original wire, so 3.7 m left over is consistent.

Use Draw a Diagram (tool 1): sketch the wire as a number line, mark off three side-length hops for the triangle, and read the remaining length.

Standards · min grade 5

  • 5.NBT.B.7 Add, subtract, multiply, and divide decimals to hundredths — Multiplying the side by 3 for the perimeter and subtracting that from the total.
  • 4.MD.A.3 Apply area and perimeter formulas for rectangles in real-world problems — Treating the wire used as the triangle's perimeter (sum of side lengths).
💡 Add up the three equal sides, then subtract from the total: leftover wire is just a tidy decimal subtraction you already know!