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← 4-2 · Subtract the overlap when joining fraction lengths · Overlap Reduces the Total

Subtract the overlap when joining fraction lengths · 10 practice problems

4.OA.A.34.NF.B.3

Generated variants — 10

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 answer: 34 6/8 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 143814\tfrac{3}{8} km, the distance from B to D is 185818\tfrac{5}{8} km, and the distance from D to E is 6786\tfrac{7}{8} km. Also, the distance from B to C (the overlapping section) is 5185\tfrac{1}{8} km.

A B C D E 14 3/8 km 18 5/8 km 6 7/8 km 5 1/8 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 14 3/8 km.
  • BD = 18 5/8 km.
  • DE = 6 7/8 km.
  • BC = 5 1/8 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 14 + 18 + 6 - 5 = 33.
14+18+65=3314+18+6-5=33
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 8: (3+5+7-1)/8 = 14/8 = 1 6/8.
38+58+7818=148=168\dfrac{3}{8}+\dfrac{5}{8}+\dfrac{7}{8}-\dfrac{1}{8}=\dfrac{14}{8}=1\tfrac{6}{8}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 33 + 1 6/8 = 34 6/8.
33+168=346833+1\tfrac{6}{8}=34\tfrac{6}{8}
Putting the pieces back together gives the full A-to-E distance.
Answer: 34 6/8 km

Review

Cross-check with segment pieces: AB = AC - BC = 9 2/8, CD = BD - BC = 13 4/8, so AE = AB + BC + CD + DE = 34 6/8 km. Same answer, and 34 6/8 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 8ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 2 answer: 23 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 101410\tfrac{1}{4} km, the distance from B to D is 133413\tfrac{3}{4} km, and the distance from D to E is 2242\tfrac{2}{4} km. Also, the distance from B to C (the overlapping section) is 3243\tfrac{2}{4} km.

A B C D E 10 1/4 km 13 3/4 km 2 2/4 km 3 2/4 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 10 1/4 km.
  • BD = 13 3/4 km.
  • DE = 2 2/4 km.
  • BC = 3 2/4 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 10 + 13 + 2 - 3 = 22.
10+13+23=2210+13+2-3=22
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 4: (1+3+2-2)/4 = 4/4 = 1.
14+34+2424=44=1\dfrac{1}{4}+\dfrac{3}{4}+\dfrac{2}{4}-\dfrac{2}{4}=\dfrac{4}{4}=1
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 22 + 1 = 23.
22+1=2322+1=23
Putting the pieces back together gives the full A-to-E distance.
Answer: 23 km

Review

Cross-check with segment pieces: AB = AC - BC = 6 3/4, CD = BD - BC = 10 1/4, so AE = AB + BC + CD + DE = 23 km. Same answer, and 23 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 4ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 3 answer: 26 4/5 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 121512\tfrac{1}{5} km, the distance from B to D is 153515\tfrac{3}{5} km, and the distance from D to E is 3253\tfrac{2}{5} km. Also, the distance from B to C (the overlapping section) is 4254\tfrac{2}{5} km.

A B C D E 12 1/5 km 15 3/5 km 3 2/5 km 4 2/5 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 12 1/5 km.
  • BD = 15 3/5 km.
  • DE = 3 2/5 km.
  • BC = 4 2/5 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 12 + 15 + 3 - 4 = 26.
12+15+34=2612+15+3-4=26
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 5: (1+3+2-2)/5 = 4/5 = 4/5.
15+35+2525=45=45\dfrac{1}{5}+\dfrac{3}{5}+\dfrac{2}{5}-\dfrac{2}{5}=\dfrac{4}{5}=\dfrac{4}{5}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 26 + 4/5 = 26 4/5.
26+45=264526+\dfrac{4}{5}=26\tfrac{4}{5}
Putting the pieces back together gives the full A-to-E distance.
Answer: 26 4/5 km

Review

Cross-check with segment pieces: AB = AC - BC = 7 4/5, CD = BD - BC = 11 1/5, so AE = AB + BC + CD + DE = 26 4/5 km. Same answer, and 26 4/5 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 5ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 4 answer: 19 4/5 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 8458\tfrac{4}{5} km, the distance from B to D is 112511\tfrac{2}{5} km, and the distance from D to E is 3153\tfrac{1}{5} km. Also, the distance from B to C (the overlapping section) is 3353\tfrac{3}{5} km.

A B C D E 8 4/5 km 11 2/5 km 3 1/5 km 3 3/5 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 8 4/5 km.
  • BD = 11 2/5 km.
  • DE = 3 1/5 km.
  • BC = 3 3/5 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 8 + 11 + 3 - 3 = 19.
8+11+33=198+11+3-3=19
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 5: (4+2+1-3)/5 = 4/5 = 4/5.
45+25+1535=45=45\dfrac{4}{5}+\dfrac{2}{5}+\dfrac{1}{5}-\dfrac{3}{5}=\dfrac{4}{5}=\dfrac{4}{5}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 19 + 4/5 = 19 4/5.
19+45=194519+\dfrac{4}{5}=19\tfrac{4}{5}
Putting the pieces back together gives the full A-to-E distance.
Answer: 19 4/5 km

Review

Cross-check with segment pieces: AB = AC - BC = 5 1/5, CD = BD - BC = 7 4/5, so AE = AB + BC + CD + DE = 19 4/5 km. Same answer, and 19 4/5 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 5ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 5 answer: 30 5/7 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 136713\tfrac{6}{7} km, the distance from B to D is 174717\tfrac{4}{7} km, and the distance from D to E is 4574\tfrac{5}{7} km. Also, the distance from B to C (the overlapping section) is 5375\tfrac{3}{7} km.

A B C D E 13 6/7 km 17 4/7 km 4 5/7 km 5 3/7 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 13 6/7 km.
  • BD = 17 4/7 km.
  • DE = 4 5/7 km.
  • BC = 5 3/7 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 13 + 17 + 4 - 5 = 29.
13+17+45=2913+17+4-5=29
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 7: (6+4+5-3)/7 = 12/7 = 1 5/7.
67+47+5737=127=157\dfrac{6}{7}+\dfrac{4}{7}+\dfrac{5}{7}-\dfrac{3}{7}=\dfrac{12}{7}=1\tfrac{5}{7}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 29 + 1 5/7 = 30 5/7.
29+157=305729+1\tfrac{5}{7}=30\tfrac{5}{7}
Putting the pieces back together gives the full A-to-E distance.
Answer: 30 5/7 km

Review

Cross-check with segment pieces: AB = AC - BC = 8 3/7, CD = BD - BC = 12 1/7, so AE = AB + BC + CD + DE = 30 5/7 km. Same answer, and 30 5/7 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 7ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 6 answer: 51 8/12 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 2551225\tfrac{5}{12} km, the distance from B to D is 28111228\tfrac{11}{12} km, and the distance from D to E is 76127\tfrac{6}{12} km. Also, the distance from B to C (the overlapping section) is 1021210\tfrac{2}{12} km.

A B C D E 25 5/12 km 28 11/12 km 7 6/12 km 10 2/12 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 25 5/12 km.
  • BD = 28 11/12 km.
  • DE = 7 6/12 km.
  • BC = 10 2/12 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 25 + 28 + 7 - 10 = 50.
25+28+710=5025+28+7-10=50
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 12: (5+11+6-2)/12 = 20/12 = 1 8/12.
512+1112+612212=2012=1812\dfrac{5}{12}+\dfrac{11}{12}+\dfrac{6}{12}-\dfrac{2}{12}=\dfrac{20}{12}=1\tfrac{8}{12}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 50 + 1 8/12 = 51 8/12.
50+1812=5181250+1\tfrac{8}{12}=51\tfrac{8}{12}
Putting the pieces back together gives the full A-to-E distance.
Answer: 51 8/12 km

Review

Cross-check with segment pieces: AB = AC - BC = 15 3/12, CD = BD - BC = 18 9/12, so AE = AB + BC + CD + DE = 51 8/12 km. Same answer, and 51 8/12 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 12ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 7 answer: 35 3/5 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 172517\tfrac{2}{5} km, the distance from B to D is 194519\tfrac{4}{5} km, and the distance from D to E is 4354\tfrac{3}{5} km. Also, the distance from B to C (the overlapping section) is 6156\tfrac{1}{5} km.

A B C D E 17 2/5 km 19 4/5 km 4 3/5 km 6 1/5 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 17 2/5 km.
  • BD = 19 4/5 km.
  • DE = 4 3/5 km.
  • BC = 6 1/5 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 17 + 19 + 4 - 6 = 34.
17+19+46=3417+19+4-6=34
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 5: (2+4+3-1)/5 = 8/5 = 1 3/5.
25+45+3515=85=135\dfrac{2}{5}+\dfrac{4}{5}+\dfrac{3}{5}-\dfrac{1}{5}=\dfrac{8}{5}=1\tfrac{3}{5}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 34 + 1 3/5 = 35 3/5.
34+135=353534+1\tfrac{3}{5}=35\tfrac{3}{5}
Putting the pieces back together gives the full A-to-E distance.
Answer: 35 3/5 km

Review

Cross-check with segment pieces: AB = AC - BC = 11 1/5, CD = BD - BC = 13 3/5, so AE = AB + BC + CD + DE = 35 3/5 km. Same answer, and 35 3/5 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 5ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 8 answer: 45 5/10 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 2171021\tfrac{7}{10} km, the distance from B to D is 2491024\tfrac{9}{10} km, and the distance from D to E is 83108\tfrac{3}{10} km. Also, the distance from B to C (the overlapping section) is 94109\tfrac{4}{10} km.

A B C D E 21 7/10 km 24 9/10 km 8 3/10 km 9 4/10 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 21 7/10 km.
  • BD = 24 9/10 km.
  • DE = 8 3/10 km.
  • BC = 9 4/10 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 21 + 24 + 8 - 9 = 44.
21+24+89=4421+24+8-9=44
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 10: (7+9+3-4)/10 = 15/10 = 1 5/10.
710+910+310410=1510=1510\dfrac{7}{10}+\dfrac{9}{10}+\dfrac{3}{10}-\dfrac{4}{10}=\dfrac{15}{10}=1\tfrac{5}{10}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 44 + 1 5/10 = 45 5/10.
44+1510=4551044+1\tfrac{5}{10}=45\tfrac{5}{10}
Putting the pieces back together gives the full A-to-E distance.
Answer: 45 5/10 km

Review

Cross-check with segment pieces: AB = AC - BC = 12 3/10, CD = BD - BC = 15 5/10, so AE = AB + BC + CD + DE = 45 5/10 km. Same answer, and 45 5/10 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 10ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 9 answer: 36 1/3 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 162316\tfrac{2}{3} km, the distance from B to D is 201320\tfrac{1}{3} km, and the distance from D to E is 5235\tfrac{2}{3} km. Also, the distance from B to C (the overlapping section) is 6136\tfrac{1}{3} km.

A B C D E 16 2/3 km 20 1/3 km 5 2/3 km 6 1/3 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 16 2/3 km.
  • BD = 20 1/3 km.
  • DE = 5 2/3 km.
  • BC = 6 1/3 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 16 + 20 + 5 - 6 = 35.
16+20+56=3516+20+5-6=35
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 3: (2+1+2-1)/3 = 4/3 = 1 1/3.
23+13+2313=43=113\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{4}{3}=1\tfrac{1}{3}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 35 + 1 1/3 = 36 1/3.
35+113=361335+1\tfrac{1}{3}=36\tfrac{1}{3}
Putting the pieces back together gives the full A-to-E distance.
Answer: 36 1/3 km

Review

Cross-check with segment pieces: AB = AC - BC = 10 1/3, CD = BD - BC = 14, so AE = AB + BC + CD + DE = 36 1/3 km. Same answer, and 36 1/3 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 3ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!
Variant 10 answer: 41 2/6 km

Use the figure to find the distance from point A to point E, in km.

Five points A, B, C, D, and E lie on one straight line in that order. The distance from A to C is 205620\tfrac{5}{6} km, the distance from B to D is 221622\tfrac{1}{6} km, and the distance from D to E is 5465\tfrac{4}{6} km. Also, the distance from B to C (the overlapping section) is 7267\tfrac{2}{6} km.

A B C D E 20 5/6 km 22 1/6 km 5 4/6 km 7 2/6 km
Show solution

Understand

Five points A, B, C, D, E sit on a line in that order. I'm given the spans AC, BD, DE, and the overlapping span BC. Using the number-line figure I must find the total distance from A to E.

Givens
  • Points lie in order A, B, C, D, E on one line.
  • AC = 20 5/6 km.
  • BD = 22 1/6 km.
  • DE = 5 4/6 km.
  • BC = 7 2/6 km is the overlap shared by AC and BD.
Unknowns
  • The distance from A to E, in km.
Constraints
  • AC and BD overlap exactly on the segment BC, since B is between A and C and C is between B and D.

Plan

#1 Draw a Diagram · also uses: #7 Identify Subproblems#16 Count the Complement

The figure shows A-B-C-D-E with AC and BD sharing the overlap BC. Adding AC + BD double-counts BC, so AE = AC + BD + DE - BC. The diagram makes the overlap easy to subtract.

Execute

#1 Draw a Diagram 4.OA.A.3
From the figure: AC stretches from A to C, BD from B to D, and these two arcs overlap on segment BC. Adding AC and BD counts the overlap BC twice, so AE = AC + BD + DE - BC.
AE=AC+BD+DEBCAE = AC + BD + DE - BC
Drawing the line shows the two arcs share the middle piece BC, so it must be removed once.
#7 Identify Subproblems 4.OA.A.3
Combine the whole numbers: 20 + 22 + 5 - 7 = 40.
20+22+57=4020+22+5-7=40
Handling the whole parts first keeps the fraction work small.
#7 Identify Subproblems 4.NF.B.3
All fractions share denominator 6: (5+1+4-2)/6 = 8/6 = 1 2/6.
56+16+4626=86=126\dfrac{5}{6}+\dfrac{1}{6}+\dfrac{4}{6}-\dfrac{2}{6}=\dfrac{8}{6}=1\tfrac{2}{6}
Like denominators let you add and subtract numerators, then regroup.
#16 Count the Complement 4.NF.B.3
Add the whole-part total and the fraction-part total: 40 + 1 2/6 = 41 2/6.
40+126=412640+1\tfrac{2}{6}=41\tfrac{2}{6}
Putting the pieces back together gives the full A-to-E distance.
Answer: 41 2/6 km

Review

Cross-check with segment pieces: AB = AC - BC = 13 3/6, CD = BD - BC = 14 5/6, so AE = AB + BC + CD + DE = 41 2/6 km. Same answer, and 41 2/6 is sensibly larger than each given span.

Work piece by piece (tool 7): find AB and CD by subtracting the overlap, then add AB + BC + CD + DE directly instead of using the overlap-subtraction formula.

Standards · min grade 4

  • 4.OA.A.3 Solve multi-step word problems using four operations with whole numbers — Setting up AE = AC + BD + DE - BC and combining the whole-number parts.
  • 4.NF.B.3 Understand a fraction with numerator greater than one as sum of unit fractions — Adding and subtracting the like-denominator 6ths and regrouping.
💡 This only needs Grade 4 fraction add/subtract — draw the line and remember the overlap gets counted twice, so subtract it once!