← Average distance per hour from total time · Average from Total

Average distance per hour from total time · 12 practice problems

6.RP.A.26.RP.A.3

Generated variants — 12

Freshly produced from the archetype’s parameters — problem, figure, and solution derived together.

Variant 1 easy answer: 55 km

A bus first travels 120 km120 \text{ km} at a steady pace of 60 km60 \text{ km} per hour, then travels another 45 km45 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 120 km at 60 km/h, then 45 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 120 km at 60 km per hour.
  • Second leg: 45 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
120÷60=2 h120 \div 60 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
45÷45=1 h45 \div 45 = 1\ \text{h}
The second leg takes 1 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
120+45=165 km,2+1=3 h120 + 45 = 165\ \text{km},\quad 2 + 1 = 3\ \text{h}
165 km in 3 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
165÷3=55165 \div 3 = 55
The bus averaged 55 km per hour.
Answer: 55 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 60, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 105/2, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 1.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 2 easy answer: 53 km

A bus first travels 130 km130 \text{ km} at a steady pace of 65 km65 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 130 km at 65 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 130 km at 65 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
130÷65=2 h130 \div 65 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
130+135=265 km,2+3=5 h130 + 135 = 265\ \text{km},\quad 2 + 3 = 5\ \text{h}
265 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
265÷5=53265 \div 5 = 53
The bus averaged 53 km per hour.
Answer: 53 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 65, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 55, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 3 easy answer: 49 km

A bus first travels 110 km110 \text{ km} at a steady pace of 55 km55 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 110 km at 55 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 110 km at 55 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
110÷55=2 h110 \div 55 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
110+135=245 km,2+3=5 h110 + 135 = 245\ \text{km},\quad 2 + 3 = 5\ \text{h}
245 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
245÷5=49245 \div 5 = 49
The bus averaged 49 km per hour.
Answer: 49 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 55, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 50, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 4 easy answer: 47 km

A bus first travels 100 km100 \text{ km} at a steady pace of 50 km50 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 100 km at 50 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 100 km at 50 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
100÷50=2 h100 \div 50 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
100+135=235 km,2+3=5 h100 + 135 = 235\ \text{km},\quad 2 + 3 = 5\ \text{h}
235 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
235÷5=47235 \div 5 = 47
The bus averaged 47 km per hour.
Answer: 47 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 50, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 95/2, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 5 medium answer: 55 km

A bus first travels 140 km140 \text{ km} at a steady pace of 70 km70 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 140 km at 70 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 140 km at 70 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
140÷70=2 h140 \div 70 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
140+135=275 km,2+3=5 h140 + 135 = 275\ \text{km},\quad 2 + 3 = 5\ \text{h}
275 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
275÷5=55275 \div 5 = 55
The bus averaged 55 km per hour.
Answer: 55 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 70, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 115/2, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 6 medium answer: 48 km

A bus first travels 90 km90 \text{ km} at a steady pace of 45 km45 \text{ km} per hour, then travels another 150 km150 \text{ km} at a steady pace of 50 km50 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 90 km at 45 km/h, then 150 km at 50 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 90 km at 45 km per hour.
  • Second leg: 150 km at 50 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
90÷45=2 h90 \div 45 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
150÷50=3 h150 \div 50 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
90+150=240 km,2+3=5 h90 + 150 = 240\ \text{km},\quad 2 + 3 = 5\ \text{h}
240 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
240÷5=48240 \div 5 = 48
The bus averaged 48 km per hour.
Answer: 48 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 50, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 95/2, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 7 medium answer: 65 km

A bus first travels 150 km150 \text{ km} at a steady pace of 75 km75 \text{ km} per hour, then travels another 45 km45 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 150 km at 75 km/h, then 45 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 150 km at 75 km per hour.
  • Second leg: 45 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
150÷75=2 h150 \div 75 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
45÷45=1 h45 \div 45 = 1\ \text{h}
The second leg takes 1 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
150+45=195 km,2+1=3 h150 + 45 = 195\ \text{km},\quad 2 + 1 = 3\ \text{h}
195 km in 3 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
195÷3=65195 \div 3 = 65
The bus averaged 65 km per hour.
Answer: 65 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 75, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 60, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 1.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 8 medium answer: 59 km

A bus first travels 160 km160 \text{ km} at a steady pace of 80 km80 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 160 km at 80 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 160 km at 80 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
160÷80=2 h160 \div 80 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
160+135=295 km,2+3=5 h160 + 135 = 295\ \text{km},\quad 2 + 3 = 5\ \text{h}
295 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
295÷5=59295 \div 5 = 59
The bus averaged 59 km per hour.
Answer: 59 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 80, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 125/2, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 9 hard answer: 61 km

A bus first travels 170 km170 \text{ km} at a steady pace of 85 km85 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 170 km at 85 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 170 km at 85 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
170÷85=2 h170 \div 85 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
170+135=305 km,2+3=5 h170 + 135 = 305\ \text{km},\quad 2 + 3 = 5\ \text{h}
305 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
305÷5=61305 \div 5 = 61
The bus averaged 61 km per hour.
Answer: 61 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 85, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 65, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 10 hard answer: 65 km

A bus first travels 190 km190 \text{ km} at a steady pace of 95 km95 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 190 km at 95 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 190 km at 95 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
190÷95=2 h190 \div 95 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
190+135=325 km,2+3=5 h190 + 135 = 325\ \text{km},\quad 2 + 3 = 5\ \text{h}
325 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
325÷5=65325 \div 5 = 65
The bus averaged 65 km per hour.
Answer: 65 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 95, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 70, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 11 hard answer: 67 km

A bus first travels 200 km200 \text{ km} at a steady pace of 100 km100 \text{ km} per hour, then travels another 135 km135 \text{ km} at a steady pace of 45 km45 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 200 km at 100 km/h, then 135 km at 45 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 200 km at 100 km per hour.
  • Second leg: 135 km at 45 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
200÷100=2 h200 \div 100 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
135÷45=3 h135 \div 45 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
200+135=335 km,2+3=5 h200 + 135 = 335\ \text{km},\quad 2 + 3 = 5\ \text{h}
335 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
335÷5=67335 \div 5 = 67
The bus averaged 67 km per hour.
Answer: 67 km
4 · Reviewdoes it hold up?

The answer sits between 45 and 100, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 145/2, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.
Variant 12 hard answer: 87 km

A bus first travels 180 km180 \text{ km} at a steady pace of 90 km90 \text{ km} per hour, then travels another 255 km255 \text{ km} at a steady pace of 85 km85 \text{ km} per hour. On average, how many kilometers did the bus travel per hour over the whole trip?

Show solution
1 · Understandwhat's really being asked

A bus covers 180 km at 90 km/h, then 255 km at 85 km/h. We need the average kilometres per hour for the trip as a whole.

Givens
  • First leg: 180 km at 90 km per hour.
  • Second leg: 255 km at 85 km per hour.
Unknowns
  • The average speed over the whole trip.
Constraints
  • Each leg is at a steady speed, but the two speeds differ.
2 · Planchoose the strategy

#7 Identify Subproblems · also uses: #8 Analyze the Units

Average speed means total distance divided by total time, so find each leg's time first. The units say so: kilometres per hour needs a kilometre total and an hour total, not two speeds averaged.

3 · Execute4 carry out the plan

1Time for the first part

#7 Identify Subproblems 6.RP.A.3
Distance divided by speed gives time.
180÷90=2 h180 \div 90 = 2\ \text{h}
The first leg takes 2 hours.

2Time for the second part

#7 Identify Subproblems 6.RP.A.3
Same again with the second leg's numbers.
255÷85=3 h255 \div 85 = 3\ \text{h}
The second leg takes 3 hours.

3Add the totals

#7 Identify Subproblems 6.RP.A.3
The whole trip is both distances and both times.
180+255=435 km,2+3=5 h180 + 255 = 435\ \text{km},\quad 2 + 3 = 5\ \text{h}
435 km in 5 hours.

4Find the average per hour

#8 Analyze the Units 6.RP.A.2
Divide the total distance by the total time.
435÷5=87435 \div 5 = 87
The bus averaged 87 km per hour.
Answer: 87 km
4 · Reviewdoes it hold up?

The answer sits between 85 and 90, as any average of the two speeds must, and leans towards the speed the bus held for longer.

Another way: Averaging the two speeds gives 175/2, which is wrong: it treats both legs as taking equal time when in fact one took 2 hours and the other 3.

Standardsmin grade 6
  • 6.RP.A.2 Understand the concept of a unit rate and use rate language — Reading the answer as a unit rate: kilometres per one hour.
  • 6.RP.A.3 Use ratio and rate reasoning to solve real-world and mathematical problems — Turning each distance and speed into a time, then totalling both.
💡Takeaway. Average speed is total distance over total time. Averaging the two speeds only works if the bus spent equal time at each.