Perimeter & Area

Depth · one concept from first principles · step 2 of 4

Slide pieces so the shaded part becomes one lump

The figure at the right shows congruent equilateral triangles drawn inside a circle, with some of them shaded. What is the total area of the shaded parts, in cm2\text{cm}^2?

12 cm
Geometry
Your answer
How to solve
Strategy Visualize Spatial Relationships — Neither an equilateral triangle nor a curved outer piece has an area a sixth-grader can work out. But the shading takes exactly half of each kind, and half of everything is half the circle -- so the pieces never have to be measured at all.
1STEP 1

Sort the circle into two kinds of piece

The circle is made of six congruent triangles inside the hexagon and six congruent pieces between the hexagon and the circle.

2STEP 2

Count how many of each kind are shaded

Three of the six triangles are shaded, and three of the six outer pieces are.

6 ÷ 2 = 3
3STEP 3

Slide the shaded pieces together

Half the triangles plus half the outer pieces is half of everything in the circle -- the shaded parts slide together into a semicircle.

4STEP 4

Take half the circle

Work out the circle and halve it.

12 × 12 × 3.14 ÷ 2 = 226.08
Answer
226.08 cm²
Check by symmetry: turning the picture by one sixth of a turn swaps the shaded and unshaded pieces exactly, so the two must have the same area, and together they are the whole circle.
Takeaway

If the shading takes half of every kind of piece, it takes half the whole.

  • Sort the circle into two kinds of piece
  • Count how many of each kind are shaded
  • Slide the shaded pieces together
  • Take half the circle
Where next?
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▶ Practice — 12 problems