Problem
Name a unit length from the picture
Four short sides stacked reach the height of one long side, so a long side is 4 units.
Drawing and labeling the figure lets me compare lengths just by counting how many equal pieces fit, instead of measuring.
3.MD.D.8Draw A DiagramWrite each side of the big rectangle in units
The big rectangle stands 4 units tall and 1 + 4 = 5 units wide.
Breaking each side into the small repeated piece turns a tricky shape into simple counting of unit lengths.
3.MD.D.8Identify SubproblemsExpress the perimeter as a multiple of the unit length
Its perimeter is 2 times (5 + 4) = 18 unit lengths.
Adding up all the unit lengths around the border shows the whole perimeter is just 18 copies of the same little length.
3.MD.D.8Identify SubproblemsThe perimeter of ABCD measures 18 unit lengths.
Why?
Every side of the big rectangle is built from whole copies of the same small unit, so any distance along its edges is a whole number of those units.
Why?
Going all the way round is two widths and two heights, so it comes to twice the 5 units and 4 units together, with no edge missed and none walked twice.
Find the unit length
Those 18 units make 54 inches, so one unit is 54 divided by 18 = 3 inches.
Once the perimeter is a count of equal pieces, splitting 54 into 18 equal parts gives the size of one piece, and I test it to be sure.
4.MD.A.3Guess And CheckCompute the area
The big rectangle is 15 inches wide and 12 inches tall, so its area is width times height = 15 times 12 = 180 square inches.
Area of a rectangle is just how many unit squares fit inside, which is the two side lengths multiplied together.
4.MD.A.3Identify SubproblemsCall the short side '1 unit,' count how many units go around the border, and the perimeter becomes easy sharing: 54 in over 18 units = 3 in each.
- Name a unit length from the picture
- Write each side of the big rectangle in units
- Express the perimeter as a multiple of the unit length
- Find the unit length
- Compute the area