Perimeter & Area

Problem

Overlapping rectangles' edges form the outline

A square (side 12 cm) and a rectangle (height 9 cm) are overlapped, with the rectangle slid to the right. The square pokes up higher and the rectangle pokes out farther right, making an L-shaped staircase outline. The two shapes have equal area. Find the perimeter of the whole combined figure.
12 cm 9 cm 3 cm
Measurement & data
Your answer
How to solve
Strategy Draw a Diagram — This is a shape-and-position problem, so a diagram makes the staircase outline visible and shows which edges face outward. The work splits into two small subproblems: first find the rectangle's width from the equal-area fact, then add up the outside edges. Sketching also reveals that the bent outline reaches exactly as far across and as high as a single big rectangle, so its perimeter equals that of the bounding rectangle.
1STEP 1

Find the rectangle's width from equal area

The square's area is 12 × 12 = 144 cm². The rectangle has the same area and a height of 9 cm, so its width is 144 ÷ 9 = 16 cm.

12 × 12 = 144, 144 ÷ 9 = 16
2STEP 2

Sketch the outline and find total width

The square juts 3 cm left of the rectangle, so the figure spans 3 + 16 = 19 cm along the bottom.

3 + 16 = 19
3STEP 3

Trace the outside edges and add them

On a staircase each step right is matched on top and each step up on the side, so the perimeter is 62 cm.

(19 + 12) × 2 = 31 × 2 = 62
Answer
62 cm
The figure is wider (19 cm) than it is tall (12 cm), and 62 cm is the perimeter of a 19-by-12 box, which the L-shape exactly fits inside touching all four sides. That box perimeter (19 + 12) × 2 = 62 cm matches, so the answer is the right size and the units are cm of length.
Takeaway

An L-shaped outline has the same perimeter as the smallest box you can draw around it — the steps just slide to the edges.

  • Find the rectangle's width from equal area
  • Sketch the outline and find total width
  • Trace the outside edges and add them
Where next?
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▶ Practice — 12 problems