Problem
Count the terms in each calculation
Term counts go 1, 3, 5, 7, 9, 11, up by 2 each time, so the 7th calculation has 13 terms.
Each step just tacks on the next two odd numbers, so the count of terms climbs by 2 every time.
4.OA.C.5Look For A PatternFind the last odd number used
With 13 terms it stops at the 13th odd number, 2 x 13 - 1 = 25.
The odd numbers in order are 1, 3, 5, ...; the 13th of them is 25, so that is where the sum stops.
4.OA.C.5Look For A PatternUse the square-number pattern for the result
Results 1, 9, 25, 49, 81 are each the number of terms multiplied by itself, so 13 terms gives 13 x 13.
Adding the first few odd numbers always builds a perfect square, so we can predict the total without adding all 13.
3.OA.D.9Solve An Easier Related ProblemThe seventh calculation's total equals the number of odd numbers it adds, 13, multiplied by itself, because adding consecutive odd numbers starting at 1 always builds a perfect square.
Why?
Show the running total as dots packed into a square, and each odd number you add becomes the L-shaped strip that grows the square to the next size up.
Why?
To grow a square to a side one dot longer, you lay down a new bottom row and a new side column of the same length and let them share the single corner dot, so the strip always holds an odd number of dots.
Why?
The larger square is exactly the smaller square plus that corner strip, with no dot left out and none counted twice, so the strip is just the extra dots needed to complete it.
Why?
Once the last odd strip is in place the dots fill a complete square, with as many rows as there are dots in each row, and that many rows of that many dots is that number times itself.
Why?
Counting equal rows of dots is the same as counting that many groups of that size, which is exactly what multiplying the two counts means.
Adding odd numbers starting at 1 always makes a square, so the 7th calculation (13 odd numbers) equals 13 x 13 = 169 with no long adding!
- Count the terms in each calculation
- Find the last odd number used
- Use the square-number pattern for the result