Problem
Rebuild the fraction
The numerator is the divisor times the quotient plus the remainder.
The fraction is 40/27.
6.NS.B.3Identify SubproblemsDivide far enough to see it repeat
Dividing 40 by 27 gives 1 and then the digits 4, 8, 1 before the same remainder comes back and the pattern starts again.
The block 481 repeats forever.
7.NS.A.2Solve An Easier Related ProblemFind where the 18th place falls in the block
The block is 3 digits long, so divide 18 by 3. It comes out exactly, which means the 18th place is the last digit of a block.
It is the third digit of the block.
7.NS.A.2Look For A PatternThe th decimal place holds the last digit of the repeating block.
Why?
The digits repeat in a fixed block of three, so the sequence comes back to the same place in the block every three steps.
Why?
is six whole blocks with nothing over, so place lands exactly at the end of a block.
Read the digit off
The block is 4, 8, 1, so its third digit is 1.
The 18th decimal place holds 1.
7.NS.A.2Look For A PatternWhen a decimal repeats, a far-off digit is a remainder question, not a division you have to finish.
- Rebuild the fraction
- Divide far enough to see it repeat
- Find where the 18th place falls in the block
- Read the digit off