Patterns & Reasoning

Problem

A repeating block gives any decimal place

An improper fraction is described by the quotient and remainder of its numerator over 27. Written as a decimal, we need the digit far down in the 18th place.
Number system
Your answer
How to solve
Strategy Look for a Pattern — Nobody divides eighteen places by hand. Once the block that repeats is known, the question becomes 'where in the block does place 18 land?', which is a remainder question.
1STEP 1

Rebuild the fraction

The numerator is the divisor times the quotient plus the remainder.

27 × 1 + 13 = 40
2STEP 2

Divide far enough to see it repeat

Dividing 40 by 27 gives 1 and then the digits 4, 8, 1 before the same remainder comes back and the pattern starts again.

40 ÷ 27 = 1.481481…
3STEP 3

Find where the 18th place falls in the block

The block is 3 digits long, so divide 18 by 3. It comes out exactly, which means the 18th place is the last digit of a block.

18 ÷ 3 = 6
4STEP 4

Read the digit off

The block is 4, 8, 1, so its third digit is 1.

Answer
1
Count a few by hand: places 1 to 6 are 4, 8, 1, 4, 8, 1, so every place that is a multiple of 3 holds 1 -- and 18 is one of them.
Takeaway

When a decimal repeats, a far-off digit is a remainder question, not a division you have to finish.

  • Rebuild the fraction
  • Divide far enough to see it repeat
  • Find where the 18th place falls in the block
  • Read the digit off

▶ Practice — 12 problems