Patterns & Reasoning

Problem

Knowing the multiple aids factoring into products

The four-digit number 284 followed by one missing digit must be a multiple of 6. I need to count how many different digits (0 through 9) can fill that blank.
Operations
Your answer
How to solve
Strategy Make a Systematic List — Being a multiple of 6 means being a multiple of 2 AND a multiple of 3. So I first list only the digits that keep the number even (the multiple-of-2 rule), then check each one against the multiple-of-3 rule (the digit sum). Listing the few candidates and checking them is faster and surer than dividing many numbers.
1STEP 1

Split 6 into 2 and 3

A multiple of 6 is a multiple of 2 and of 3, so the last digit settles one rule and the digit sum the other.

6 = 2 × 3
2STEP 2

Keep only the even endings

The even rule leaves only 0, 2, 4, 6, 8 to test instead of all ten digits.

■ ∈ {0, 2, 4, 6, 8}
3STEP 3

Check each even ending against the multiple-of-3 rule

The fixed digits add to 14, and only 14 + 4 = 18 is a multiple of 3, so the box is 4.

2+8+4=14; 14+0=14, 14+2=16, 14+4=18, 14+6=20, 14+8=22
4STEP 4

Count the digits that work

Only ■ = 4 passes both rules, giving the number 2844. So exactly one digit can fill the blank.

2844 ÷ 6 = 474
Answer
1 digit
There can be at most five even endings, so an answer of 1 is in range. Checking directly: 2844 ÷ 6 = 474 with no remainder, while the next even endings 2840, 2842, 2846, 2848 each leave a remainder, confirming 4 is the only digit that works.
Takeaway

To find multiples of 6, use the easy 2-rule and 3-rule together instead of dividing big numbers.

  • Split 6 into 2 and 3
  • Keep only the even endings
  • Check each even ending against the multiple-of-3 rule
  • Count the digits that work
Where next?
Another one like thissuggested

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