Patterns & Reasoning

Problem

A multiple is divisible by its factor

A mystery number and 48 are in a factor-multiple relationship, which means the mystery number is either a factor of 48 or a multiple of 48. I need to count how many two-digit numbers (10 through 99) the mystery number could be.
Operations
Your answer
How to solve
Strategy Make a Systematic List — A factor-multiple relationship splits into two cases: the mystery number is a factor of 48, or it is a multiple of 48. I will treat each case as its own small subproblem, list every value, keep only the two-digit ones, then combine the lists without double-counting.
1STEP 1

Split into two cases

The relationship allows either side, so the number is a factor of 48 or a multiple of 48.

2STEP 2

List the two-digit factors of 48

All factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48. Keeping only the two-digit ones gives 12, 16, 24, and 48.

48 = 1×48 = 2×24 = 3×16 = 4×12 = 6×8
3STEP 3

List the two-digit multiples of 48

The multiples of 48 are 48, 96, 144, ... Only 48 and 96 are two-digit numbers.

48×1 = 48, 48×2 = 96, 48×3 = 144
4STEP 4

Combine the lists and remove duplicates

Merging {12, 16, 24, 48} with {48, 96} and counting 48 only once leaves 5 numbers.

{12, 16, 24, 48} ∪ {48, 96} = {12, 16, 24, 48, 96}
Answer
5
All five answers are between 10 and 99, so they are genuine two-digit numbers. Each one checks out: 12, 16, 24 divide 48 evenly; 48 equals 48; and 96 = 48 x 2 is a multiple. No other two-digit number divides 48 or is a multiple of 48, so 5 is complete.
Takeaway

Factor or multiple? List both, then count each number just once.

  • Split into two cases
  • List the two-digit factors of 48
  • List the two-digit multiples of 48
  • Combine the lists and remove duplicates
Where next?
Another one like thissuggested

▶ Practice — 12 problems