Patterns & Reasoning

Problem

Count ways to make an amount with coins

Mia has 2 dimes, 2 nickels, and 10 pennies. Count how many different combinations of these coins pay exactly 20 cents.
Measurement & data
Your answer
ways
How to solve
Strategy Make a Systematic List — This is a 'how many ways' question over a small, bounded set of coins, so I make an organized list ordered by the number of dimes, tracking the cent value of each coin to keep the total at 20.
1STEP 1

Set up the goal in cents

Turn each coin into cents — dime 10, nickel 5, penny 1 — and hunt combinations totaling 20 cents within her supply.

10d + 5n + 1p = 20
2STEP 2

Try 2 dimes

Two dimes already make 20 cents, so no nickels or pennies are needed — that's 1 way.

10 + 10 = 20
3STEP 3

Try 1 dime

One dime leaves 10 cents: 2 nickels; 1 nickel + 5 pennies; or 10 pennies — all within her limits, so 3 ways.

10 + (2×5), 10 + 5 + (5×1), 10 + (10×1)
4STEP 4

Try 0 dimes

With no dimes, only 2 nickels + 10 pennies reach 20 cents; fewer nickels would need 15 or 20 pennies she lacks — 1 way.

(2×5) + (10×1) = 20
5STEP 5

Count all the ways

Add the cases — 1 with 2 dimes, 3 with 1 dime, 1 with 0 dimes: 1 + 3 + 1 = 5.

1 + 3 + 1 = 5
Answer
5 ways
1 + 3 + 1 = 5
Each listed combination sums to exactly 20 cents and never exceeds her supply of 2 dimes, 2 nickels, and 10 pennies, so 5 distinct ways is consistent.
Takeaway

Organize your guesses by how many dimes you use, and the rest of the coins fall into place by twenties!

  • Set up the goal in cents
  • Try 2 dimes
  • Try 1 dime
  • Try 0 dimes
  • Count all the ways
Where next?
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