Patterns & Reasoning

Depth · one concept from first principles · step 2 of 4

Group by numerator plus denominator, then count

The positive rational numbers are listed, without reducing any fraction, in the following order:

(11),(21,12),(31,22,13),⋯\left(\frac{1}{1}\right), \left(\frac{2}{1}, \frac{1}{2}\right), \left(\frac{3}{1}, \frac{2}{2}, \frac{1}{3}\right), \cdots

In which position in the list is 57\frac{5}{7}? (For example, 13\frac{1}{3} is the 66th number.)

OperationsNumber system
Your answer
How to solve
Strategy Look for a Pattern — First find the rule behind the brackets: the kth bracket holds the k fractions whose numerator plus denominator is k + 1. Then the position of 5/7 is the number of fractions in all earlier brackets plus its place within its own bracket.
1STEP 1

Find the rule

In each bracket numerator plus denominator is constant: 2, then 3, then 4. Inside, the denominator goes 1, 2, 3, ….

1 + 1 = 2, 2 + 1 = 1 + 2 = 3, 3 + 1 = 2 + 2 = 1 + 3 = 4
2STEP 2

Locate the bracket of 5/7

For 5/7 the sum is 12, so it is in the bracket with sum 12, the 11th bracket.

5 + 7 = 12
3STEP 3

Count the earlier fractions

Those brackets have 1, 2, …, 10 fractions.

1 + 2 + 3 + … + 10 = 55
4STEP 4

Position inside its bracket

The sum-12 bracket starts at denominator 1 and goes up by one each time.

11/1, 10/2, 9/3, 8/4, 7/5, 6/6, 5/7
5STEP 5

Add

Add the earlier count and the place in the bracket.

55 + 7 = 62
Answer
62nd
Test the method on the given example: 1/3 has sum 4; brackets with sums 2 and 3 hold 1 + 2 = 3 fractions, and 1/3 has denominator 3, so it is number 3 + 3 = 6, matching the problem.
Takeaway

Big lists are easy to search once you know what each group has in common.

  • Find the rule
  • Locate the bracket of 5/7
  • Count the earlier fractions
  • Position inside its bracket
  • Add
Where next?
Another one like thissuggested

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▶ Practice — 12 problems

The same shape shows up later on the AMC, as Arithmetic Expression Decomposition, Geometric Series Share, Lattice / Grid Pattern from Small Cases. Why the shapes repeat →