Depth · one concept from first principles · step 2 of 4
Same numerator: smaller denominator is larger
Find the values of and that satisfy both of the following equations.
Depth · one concept from first principles · step 2 of 4
Find the values of and that satisfy both of the following equations.
A over (B+4) equalling one fourth means the bottom is 4 copies of the top: B + 4 = 4 x A.
An equivalent fraction keeps the same value: to get 1/4 from A/(B+4), the bottom is just A copied 4 times. Fourth graders already build equivalent fractions this way.
3.NF.A.3Identify SubproblemsA over (B+4) being one fourth means B+4 is 4 times A.
Two fractions are equal when one is the other with the top and the bottom scaled by the same number, so A over (B+4) is one fourth with both parts multiplied by A.
A written over A is one, and multiplying one fourth by one leaves it unchanged.
Scaling the 1 and the 4 by A puts A on top and four groups of A on the bottom.
Trying whole numbers, the two rules hand back the same B only when A is 5.
Testing small numbers and watching the two B-values close in on each other is a concrete way to find the unknown without abstract symbol pushing.
3.OA.A.4Guess And CheckThe denominators differ by 5, and moving from a fourth to a fifth adds one copy of A, so A = 5.
Seeing that adding 5 to the bottom is exactly 'one more copy of A' reveals the answer as a comparison, confirming the guess instead of relying on luck.
4.OA.A.1Look For A PatternWith A = 5 the first rule gives B = 16, and 5/20 and 5/25 do reduce to a fourth and a fifth.
Plugging the found numbers back in and simplifying confirms the fractions really do equal 1/4 and 1/5.
3.NF.A.3Guess And CheckWhen a fraction equals a unit fraction like 1/4, the bottom is just the top copied 4 times, so you can test small numbers until both sentences agree.
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The same shape shows up later on the AMC, as Small-Domain Constrained Search. Why the shapes repeat →