Operations & Word Problems

Problem

Equal heights make the area ratio the base ratio

Two triangles inside a larger one have equal areas. We need the ratio of one of them to a third triangle.
A B C D E 6 cm 4 cm 14 cm
GeometryRatios
Your answer
How to solve
Strategy Convert to Algebra — The right angle hands over both heights at once: AE is 10 and DE is 4, both perpendicular to the base. Then the equal-area condition is one equation about how the base splits, and the answer follows from the two pieces.
1STEP 1

Find the two heights

The whole segment AE is AD plus DE, and the right angle at E makes both AE and DE perpendicular to the base.

6 + 4 = 10
2STEP 2

Write the equal areas as an equation

Call BE ■; then EC is 14 - ■. Triangle ABE is ■ times 10 halved, and triangle DEC is (14 - ■) times 4 halved.

5 × ■ = 2 × (14 - ■)
3STEP 3

Solve for the two parts of the base

Expanding gives 5 of the unknown on the left and 28 minus 2 of it on the right, so 7 of it is 28.

28 ÷ 7 = 4, 14 - 4 = 10
4STEP 4

Compare the two triangles asked about

Both stand on the base with the same height 10, so their areas are in the same ratio as their bases.

4 : 10 = 2 : 5
Answer
2 : 5
Work the areas out: triangle ABE is 4 × 10 ÷ 2 = 20 and triangle DEC is 10 × 4 ÷ 2 = 20, equal as required; triangle AEC is 10 × 10 ÷ 2 = 50, and 20 : 50 is 2 : 5.
Takeaway

Triangles that share a height have areas in the same ratio as their bases.

  • Find the two heights
  • Write the equal areas as an equation
  • Solve for the two parts of the base
  • Compare the two triangles asked about

▶ Practice — 12 problems