Operations & Word Problems

Depth · one concept from first principles · step 2 of 4

Measure a border path strip by strip

A path runs around the inside edge of an x by y rectangle: 2 m wide at top and bottom, 3 m wide at the sides. Find the path's area A and the inner field's perimeter B, then add them.
x m y m 3 m 3 m 2 m 2 m
ExpressionsGeometry
Your answer
How to solve
Strategy Identify Subproblems — First find the field's side lengths from the picture. Then cut the path into four strips whose areas are easy linear expressions, and get the field's perimeter from its sides.
1STEP 1

Field dimensions

The field loses 3 m on each side across and 2 m at the top and bottom.

width=x-3-3=x-6, length=y-2-2=y-4
2STEP 2

Path area, strip by strip

The top and bottom strips run the full width x and are 2 m wide; the side strips fit between them, y-4 long and 3 m wide.

A=2×(2x)+2×3(y-4)=4x+6y-24
3STEP 3

Field perimeter

Use the field's width and length.

B=2(x-6)+2(y-4)=2x+2y-20
4STEP 4

Add

Combine like terms.

A+B=(4x+6y-24)+(2x+2y-20)=6x+8y-44
Answer
6x+8y-44
Try x=20, y=10. The field is 14 by 6, so the path's area is 200-84=116 and 4×20+6×10-24=116. The field's perimeter is 2×(14+6)=40 and 2×20+2×10-20=40. Then 116+40=156, and 6×20+8×10-44=156.
Takeaway

Break a frame-shaped region into simple strips and the algebra stays easy.

  • Field dimensions
  • Path area, strip by strip
  • Field perimeter
  • Add
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