Geometry & Figures

Problem

Square diagonals are equal and perpendicular bisectors

The outer square has side 16 cm with a \bigcirc drawn inside touching all four sides. The four touch points (the midpoints of the outer square's sides) are joined to make an inner square ABCD. Its diagonals AC and BD cross at the center M. I need the length of BM.
16 cm A B C D M
GeometryMeasurement & data
Your answer
cm
How to solve
Strategy Draw a Diagram — Read the picture carefully: the inner square's diagonals are just the center lines of the outer square, so each diagonal equals the outer side. Then halve it because the diagonals bisect each other.
1STEP 1

See that diagonal BD is the full width of the outer square

B and D are the midpoints of the right and left sides, so BD runs across the square's middle and equals its side, 16 cm.

BD = 16 cm
2STEP 2

Halve the diagonal to get BM

The diagonals of the inner square bisect each other at center M, so M is the midpoint of BD. Therefore BM = BD / 2 = 162\frac{16}{2} = 8 cm.

16 ÷ 2 = 8 cm
Answer
8 cm
16 ÷ 2 = 8 cm
BM = 8 cm is half the 16 cm width, which matches that M is the exact center of the figure (also the \bigcirc's center, radius 8 cm). The size and centimeter unit are sensible.
Takeaway

Joining opposite side-midpoints of a square gives a line as long as the side, and the diagonals split in half -- so BM is just 16 divided by 2!

  • See that diagonal BD is the full width of the outer square
  • Halve the diagonal to get BM
Where next?
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▶ Practice — 10 problems