Geometry & Figures

Depth · one concept from first principles · step 2 of 4

No triangle: a parallel pair or one common point

Three different lines are x-y=0, 2x+y=3, and mx-4y=16. For which values of m do they fail to enclose a triangle?
ExpressionsFunctions
Your answer
How to solve
Strategy Make a Systematic List — List every way a triangle can fail: some pair of lines is parallel (that pair never meets), or all three pass through one point (the three corners collapse). Line 3 is the only one that moves with m, so check it against each fixed line and against their crossing point.
1STEP 1

Write each line in slope form

Solve each equation for y to read off the slopes.

y=x, y=-2x+3, y=(m/4)x-4
2STEP 2

Case 1: line 3 parallel to line 1

Parallel lines have equal slopes and different intercepts (-4 ≠ 0).

m/4=1, m=4
3STEP 3

Case 2: line 3 parallel to line 2

Again equal slopes, and the intercepts -4 and 3 differ.

m/4=-2, m=-8
4STEP 4

Case 3: all three through one point

Lines 1 and 2 cross where x=-2x+3, so x=1 and y=1. Line 3 must pass through (1, 1).

m × 1-4 × 1=16, m=20
Answer
m=-8, 4, 20
Check each value: m=4 gives y=x-4, parallel to y=x; m=-8 gives y=-2x-4, parallel to y=-2x+3; m=20 gives y=5x-4, and 5 × 1-4=1, so it passes through (1, 1). In every case the three lines are still distinct.
Takeaway

Three lines miss a triangle only two ways: two run parallel, or all three meet at one point.

  • Write each line in slope form
  • Case 1: line 3 parallel to line 1
  • Case 2: line 3 parallel to line 2
  • Case 3: all three through one point
Where next?
Another one like thissuggested

A parent dashboard for the family lives at sensimlab.com.

▶ Practice — 12 problems