Problem
Count the cubes in the finished shape
Five cells on the floor and three of them carrying a second cube.
The shape has 8 cubes, so it is two four-cube pieces.
5.MD.C.3Visualize Spatial RelationshipsPlace the piece with the least freedom
The flat square needs four cells forming a 2 × 2 patch, and the floor has exactly one such patch -- the two front cells with the two back cells beside them.
Piece A can only go one place.
6.G.A.4Eliminate PossibilitiesThe flat square piece can only go in one place.
Why?
That piece needs four cells meeting in a by block on the floor, and the shape's floor has exactly one such block.
Why?
Once it is placed, what is left has to be the other piece, because the two pieces together are the whole solid with nothing over.
See what is left
What remains is the third cell of the back row on the floor, plus the whole second layer -- a row of three with one cube below one end.
That is the same shape as D, turned over.
6.G.A.4Make A Systematic ListCheck the fit
The two pieces cover all eight cubes with nothing left over and nothing counted twice.
A and D build the shape.
5.MD.C.3Eliminate PossibilitiesPlace the piece with the fewest possible positions first -- it decides the rest.
- Count the cubes in the finished shape
- Place the piece with the least freedom
- See what is left
- Check the fit