Geometry & Figures

Problem

Overlapping congruent shapes leave congruent leftovers

A rectangular sheet ABCD is folded so its lower-right corner turns upward, making a shaded triangle of overlapping paper. The crease FC is 15 cm, the bottom piece BF is 9 cm, and the folded-over edge FE is 12 cm. I need to find the area of the whole original rectangle.
A B C D F E 9 cm 15 cm 12 cm
Geometry
Your answer
How to solve
Strategy Draw a Diagram — Folding is easiest to understand by drawing (and imagining folding) the sheet, then marking which lengths the crease creates. The crease, the bottom, and the rectangle's side form a right triangle, so I split the job into two small steps: first find the height of the rectangle from that right triangle, then find the width by using the fact that folding keeps lengths the same.
1STEP 1

Draw and label the fold

Draw the crease FC; corner B is square, so BFC is a right triangle with FC as its longest side.

2STEP 2

Find the height with the right triangle

With BF = 9 and FC = 15, the missing side BC is 12, the familiar 9-12-15 right triangle.

9² + BC² = 15² → 81 + BC² = 225 → BC = 12
3STEP 3

Find the width using the fold

The fold lays the bottom piece onto FE without stretching it, so the width is 9 + 12 = 21 cm.

width = BF + FE = 9 + 12 = 21
4STEP 4

Multiply to get the area

The rectangle is 21 cm wide and 12 cm tall, so its area is length times width: 21 x 12 = 252.

21 × 12 = 252
Answer
252 cm²
The height (12 cm) is shorter than the width (21 cm), which matches a wide rectangle, and both come out as whole numbers from the clean 9-12-15 triangle. The area 252 cm² has the right units (cm²) and a sensible size for a 21-by-12 sheet.
Takeaway

A fold never stretches the paper, so a folded edge keeps its length-use that, plus the 9-12-15 right triangle, to rebuild the whole sheet.

  • Draw and label the fold
  • Find the height with the right triangle
  • Find the width using the fold
  • Multiply to get the area
Where next?
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