Find the extreme decimal satisfying an inequality
Find the greatest number with two decimal places that can go in the .
Show solution
Understand
Find the greatest number with two decimal places that can fill the box so that box + 4.17 stays less than 10.45 - 2.71.
- The inequality is box + 4.17 < 10.45 - 2.71.
- The box must be a number with exactly two decimal places (a hundredths number).
- The greatest two-decimal-place number that fits in the box.
- The filled value must keep the inequality strictly true (less than, not equal).
- The answer must have exactly two decimal places.
Plan
#11 Work Backwards · also uses: #6 Guess and Check
First simplify the right side to a single number, then work backwards to isolate the box. The box must be less than some value, so the greatest two-decimal number is the largest hundredths value strictly below it.
Execute
Review
Test 3.56: 3.56 + 4.17 = 7.73, which is less than 7.74 - true. Test 3.57: 3.57 + 4.17 = 7.74, not less than 7.74 - false. So 3.56 is indeed the greatest value that works.
Guess and Check near the boundary: try 3.57 (fails, equals), then 3.56 (works), confirming 3.56 is the largest two-decimal number that keeps the inequality true.
Standards · min grade 5
5.NBT.B.7Add, subtract, multiply, and divide decimals to hundredths — Computing 10.45 - 2.71 and 7.74 - 4.17.4.NF.C.7Compare two decimals to hundredths by reasoning about their size — Choosing the greatest hundredths value strictly below 3.57.