Data & Graphs

Depth · one concept from first principles · step 2 of 4

Read each runner's rate from one graph point

Both runners' distance is proportional to time, so each graph is a line y=kx through the origin. One marked point on each line gives its constant k (the speed). Use the speeds to find each runner's 100 m time and subtract.
x (s) y (m) A B 24 3 4 O
RatiosNumber system
Your answer
How to solve
Strategy Identify Subproblems — Split the job: first read each runner's constant from one point, then turn 100 m into a time for each runner, then compare. The units (meters per second) say the constant is a speed.
1STEP 1

Read A's speed

A covers 24 m in 3 s, so y/x is the same everywhere on A's line.

k_A = 24/3 = 8, so y = 8x
2STEP 2

Read B's speed

B covers the same 24 m but needs 4 s.

k_B = 24/4 = 6, so y = 6x
3STEP 3

Time each runner over 100 m

Put y = 100 into each equation and solve for x.

8x = 100 → x = 25/2, 6x = 100 → x = 50/3
4STEP 4

Subtract the times

B finishes later, so subtract A's time from B's using a common denominator.

50/3 - 25/2 = 100/6 - 75/6 = 25/6
Answer
25/6 seconds
A needs 12.5 s and B about 16.7 s, a gap of about 4.2 s, and 25/6 ≈ 4.17. A gap of a few seconds over 100 m between 8 m/s and 6 m/s runners is reasonable.
Takeaway

One point on a line through the origin tells you the whole line: divide y by x.

  • Read A's speed
  • Read B's speed
  • Time each runner over 100 m
  • Subtract the times
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