Data & Graphs

Problem

Set up one-unknown equation from mean

A store sold cell phones over four quarters. We know Q1 = 450 and Q3 = 410, the four-quarter average is 395, and Q2 is 80 fewer than Q4. We must find how many phones were sold in Q4.
Data & probabilityExpressions
Your answer
How to solve
Strategy Work Backwards — The average is the end result, so we work backwards from it: multiply the average by 4 to recover the total of all four quarters. Then we split the job into small subproblems — subtract the two known quarters to find what Q2 and Q4 together must be, and use the Q2 = Q4 - 80 relationship to share that amount and pin down Q4.
1STEP 1

Recover the total from the average

Undoing the average, 395 x 4 = 1580 phones across the four quarters.

395 × 4 = 1580
2STEP 2

Find what Q2 and Q4 together must be

Take away the two quarters we already know, Q1 = 450 and Q3 = 410, from the total. What is left is the combined sales of Q2 and Q4.

1580 - 450 - 410 = 720
3STEP 3

Share the 720 using the 80 gap

Q2 is 80 below Q4, so 2 x Q4 - 80 = 720 gives 2 x Q4 = 800 and Q4 = 400.

2 × Q4 - 80 = 720 → 2 × Q4 = 800 → Q4 = 400
Answer
400 phones
Q4 = 400 gives Q2 = 400 - 80 = 320. The four quarters are 450, 320, 410, 400, which add to 1580, and 1580 ÷ 4 = 395 — exactly the stated average. The answer is a whole number of phones near the average, which is sensible.
Takeaway

An average is a total in disguise — multiply it back up, subtract what you know, then split the rest by the gap.

  • Recover the total from the average
  • Find what Q2 and Q4 together must be
  • Share the 720 using the 80 gap
Where next?
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